# Quant Test for SBI PO 2018 Prelim Exam Set – 48

Hello Aspirants

State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on 1st, 7th & 8th of July 2018. Details of the exam are as under: Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.

Directions(1-5): Find the relation between x and y and choose a correct option.

1. I. 6x2 + 77x + 121 = 0
II. y2 + 9y – 22 = 0

y>x
x=y or relation cannot be established.
y>=x
x>y
x>=y
Option B
I. 6x2 + 77x + 121 = 0
=> 6x2 + 66x + 11x + 121 = 0
=> 6x (x + 11) + 11 (x + 11) = 0
=> (x + 11) (6x + 11) = 0
=> x = – 11 or – 11/6
II. y2 + 11y – 2y – 22 = 0
=>y (y + 11) – 2 (y + 11) = 0
=>(y – 2) (y + 11) = 0
=>y = 2 or -11
x=y or relation cannot be established.

2. I. 16x2 + 8x – 15 = 0
II. 4y2 + 29y + 30 = 0

x=y or relation cannot be established.
y>=x
x>y
x>=y
y>x
Option D
I. 16x2 + 8x – 15 = 0
=>16x2 + 8x – 15 = 0
=>16x2 + 20x – 12x – 15 = 0
=>x = -5/4, 3/4
II. 4y2 + 29y + 30 = 0
=>4y2 + 29y + 30 = 0
=>4y2 + 24y + 5y + 30 = 0
=>y = -6, -5/4
x ≥ y

3. I. 3x2 + 23x + 30 = 0
II. 3y2 – 4y – 4 = 0

x>y
x>=y
x=y or relation cannot be established.
y>x
y>=x
Option D
I. 3x2 + 23x + 30 = 0
=> 3x2 + 23x + 30 = 0
=> 3x2 + 18x + 5x + 30 = 0
=> x = -5/3, -6
II. 3y2 – 4y – 4 = 0
=> 3y2 – 4y – 4 = 0
=> 3y2 – 6y + 2y – 4 = 0
=> y = 2, -2/3
x < y

4. I. 5x2 – 36x – 32 = 0
II. 3y2 – 17y – 6 = 0

x>=y
x>y
y>=x
y>x
x=y or relation cannot be established.
Option E
I. 5x2 – 36x – 32 = 0
=>5x2 – 36x – 32 = 0
=>5x2 + 4x – 40x – 32 = 0
=> x = -4/5, 8
II. 3y2 – 17y – 6 = 0
=>3y2 – 17y – 6 = 0
=> 3y2 + y – 18y – 6 = 0
=> y= -1/3, 6
x = y or relation cannot be established

5. I. 3x2 + 20x + 32 = 0
II. 3y2 – 4y – 4 = 0

y>x
x=y or relation cannot be established.
y>=x
x>=y
x>y
Option A
I. 3x2 + 20x + 32 = 0
=>3x2 + 20x + 32 = 0
=>3x2 + 12x + 8x + 32 = 0
=>x = -4, -8/3
II. 3y2 – 4y – 4 = 0
=>3y2 – 4y – 4 = 0
=>3y2 – 6y + 2y – 4 = 0
=> y = -2/3, 2
x < y

6. A sum was put at simple interest at a certain rate for 3 yr. Had it been put at 1% higher rate, it would have fetched Rs 5100 more. Find the sum.
Rs 1,10,000
Rs 1,20,000
Rs 1,70,000
Rs 1,30,000
Rs 1,50,000
Option C
Simple interest for 1 yr = 5100/3 = Rs 1700
1% of sum 1700
Sum = 1700 * 100 = Rs 1,70,000

7. A shopkeeper buys 144 items at 90 paise each. On the way 20 items broken. He sells the remainder at Rs.1.20 each. His gain percent correct to one decimal place.
14.81%
14.61%
17.21%
13.20%
15.11%
Option A
20 items are broken out of 144.
CP of 124 items = 144*90/100 = Rs.129.6
Total SP = 1.2*124 = Rs.148.8
Gain% = [148.8 – 129.6]/129.6 *100 = 14.81%

8. A man gave 50% of his savings of Rs. 84,100 to his wife and divided the remaining sum among his two sons A and B of 15 and 13 years old of age resp. He divided it in such a way that each of his sons, when they attain the age of 18 years , would receive the same amount at 5% compound interest per annum. Find the share of B.
Rs.10,000
Rs.80,000
Rs.20,000
Rs.50,000
Rs.60,000
Option C
50% of savings = 50/100*84100 = Rs.42050
Difference of their ages = 2 years
Rate = 5%
Ratio of shares = A:B = (21/20)^2 = 441/400
B’s share = 42050/841*400 = Rs.20,000

9. A trader buys goods at 20% discount on marked price. If he wants to make a profit of 25% after allowing a discount of 20% , by what percent should his marked price be greater than the original marked price?
35%
10%
15%
25%
40%
Option D
Let the original price be 100x.
cost price = 80% of 100x = 80x
Profit 25% selling price = 125/100*80x = 100x
Allowed discount = 20%
Trader’s market price = 100x/80*100 = 125
Required % = [125x-100x]/100x*100 = 25%

10. Average age of A,B and C is 84 years. When D joins them the average age becomes 80 years. A new person E, whose age is 4 years more than D, replaces A and the average of B,C,D and E becomes 78 years. What is the age of A?
60 years
40 years
80 years
90 years
50 years
Option C
A+B+C = 3*84 = 252 years
A+B+C+D = 80*4 = 320 years
D’s age = 320 – 252 = 68 years
E’s age = 68 + 4 = 72 years
B+C+D+E = 78*4 = 312 years
B+C = 312 – 68 – 72 =172 years
A’s age = 252 – 172 = 80 years