# Quant Test for SBI PO 2018 Prelim Exam Set – 49

Hello Aspirants

State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on 1st, 7th & 8th of July 2018. Details of the exam are as under: Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.

Directions(1-5): What approximate value will come in place of question mark ‘?’ in the given questions.

1. [(18)^2 /4] + (? – 40) = 79.96
20
17
39
41
28
Option C
[(18)^2 /4] + (? – 40) = 79.96
=> [324/4] + (?-40) = 80
=> 81 + ? – 40 = 80
=> ? = 39

2. 14.98% of 1100 – 6.03^2 – ? = 299.88
-100
-111
-75
-171
-90
Option D
14.98% of 1100 – 6.03^2 – ? = 299.88
=> 15% of 1100 – 36 – ? = 300
=> 165 – 36 – ? =300
=> ? = -171

3. [1024.23 /3.82 + (12.02)^1.88 ]^1/2 * 13.21 = ?
260
200
244
201
274
Option A
[1024.23 /3.82 + (12.02)^1.88 ]^1/2 * 13.21 = ?
=> [1024/4 + 144]^1/2 * 13.21 = ?
=> (256 + 144)^1/2 * 13 = ?
=> (400)^1/2 * 13 =?
=> ? = 20*13 = 260

4. 812.16 – 126.99 * 5.002 + 89.56*2.02 = ?
357
450
354
225
466
Option A
812.16 – 126.99 * 5.002 + 89.56*2.02 = ?
=> 812 – 127*5 + 90*2 = ?
=> 812 – 635 + 180 = ?
=> ? = 357

5. [33.89 * 20.01 + (527.92)^1/2 – (14.88)^2.04]/[(25.02)^1.8 – 384.77] = ?
3
7
4
5
2
Option E
[33.89 * 20.01 + (527.92)^1/2 – (14.88)^2.04]/[(25.02)^1.8 – 384.77] = ?
=> [34*20 + 23 – 225]/[625 – 385] => [680 + 23 – 225 ]/240
=> 2

6. Directions(6-10): The following pie-chart shows the percentage distribution of total
population of six cities, and the table shows the percentage of males among them.
(Total population of City F = 1526000).  7. What is the difference between the male and the female population of City B?
45000
42560
38995
33550
49280
Option E
TotalB = 7000000 × 11/100 = 770000
Males are 53.2%,
so females = 100 – 53.2 = 46.8%
Diff = 53.2 – 46.8 = 6.4%
Required answer = 770000 × 6.4/100 = 49280

8. What is the total number of females in City A?
746214
588900
775500
655255
828900
Option A
Total number of people in all six cities
=1526000 * 100/21 = 7266666.67
Total population of City A = 7266666.67 × 21/100 = 1526000
MaleA = 1526000 × 51.1/100 = 779786
FemaleA = 1470000 – 779786= 746214

9. What is the total number of males in all six cities together?
5227455
4555500
3560078
4478250
3606820
Option E
Total males
= 7000000/100*100 {21 × 51.1 + 11 × 53.2 + 24 × 52.9 + 15 × 53.8 + 7 × 47.9 + 22 × 49.2}
= 700 {1073.1 + 585.2 + 1269.6 + 807 + 335.3 + 1082.4}
= 700 × 5151.08 = 3606820

10. The female population of City F is approximately what percentage of the female population of City E?
199.8%
222.2%
148.9%
322.32%
233.4%
Option D
FemaleE = 7000000 *7/100* (100 – 49.2)/100
= 700 × 7 × 50.8 = 248920
FemaleF = 7000000 *22/100* (100-47.9)/100
= 700 × 22 × 52.1 = 802340
Required % = 802340/248920 ×100 = 322.32%

11. The total number of females in all six cities together is what percentage of the total population of all six cities together? (Answer in approximate value)
72.2%
55.5%
60.5%
48.5%
54.4%
Option D
Total population in all six cities = 7000000
Total females in all six cities = 7000000 – 3606820 = 3393180
Required % = 3393180/7000000*100
= 48.474 == 48.5%