Hello Aspirants

**State Bank of India (SBI)** is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on **1st, 7th & 8th of July 2018. **Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.

- 23% of 6783 + 57% of 8431 = ?
8500.47007.55445.26365.76060.6Option D

23% of 6783 + 57% of 8431 = ? = 1560.09 + 4805.67 = 6365.7 - (2477.68 + 1254.87 – 3647.89) = ? × 13 – 84.34
1317101216Option A

(2477.68 + 1254.87 – 3647.89) = ? × 13 – 84.34 =>(2477.68 + 1254.87 – 3647.89) = ? × 13 – 84.34 =>(3732.55 – 3647.89) = ? × 13 – 84.34 =>84.66 + 84.34 = ? × 13 =>169 ÷ 13 = ? =>? = 13 - 27.5% of 256 – ?% of 340 = – 31.6
6010305040Option C

27.5% of 256 – ?% of 340 = – 31.6 =>55% of 128 – ?% of 340 = – 31.6 =>70.4 + 31.6 = 3.40 × ? =>102 = 3.40 × ? =>? = 102/3.4= 30 - 94.5 × 512 ÷ (343)^1/3 ÷ 6.4 = ?^2 + 56
5242226232Option E

94.5 × 512 ÷ (343)^1/3 ÷ 6.4 = ?2 + 56 =>945 ×512/(7 × 64) = ?^2 + 56 =>135 × 8 – 56 = ?^2 =>1080 – 56 = ?^2 =>?^2 = 1024 =>? = 32 - 32.5% of 1388 – (4096)^1/2 ÷ 4 × (529)^1/2 = ?
9083687066Option B

32.5% of 1388 – (4096)^1/2 ÷ 4 × (529)^1/2 = ? =>? = 65% of 694 – 64 ÷ 4 × 23 =>? = 451.1 – 16 × 23 =>? = 451.1 – 368 =>? = 83.1 ==83 - Ram completed 25% of a task in 5 days and thn he takes the help of laxman and sita .lakshman is 20% as efficient as ram and sita 20% as efficient as lakshman .in how many more days will they complete the work.
375/31300/13352/41305/22323/27Option A

Ram 25% in 5 days So, 100% in 20 days now, Laxman is 20% efficient. 20/100 = 1/5 so, his time = 20*5 =100 days Sita == 1/5 so, 100*5 =500 days Total work = 500 Ram— 25 , Laxman—5 , Sita–1 Total units/days = 31 75% of work = 375 Hence, time = 375/31 - A swimmimng pool has 3 drain pipes. The first two pipes A and B operating simultaneously, can empty the pool in half the time that C, the third pipe alone takes to empty it. Pipe A is working alone, takes half the time taken by pipe B. All together they takes 6hours 40minutes to empty the pool. Find the time taken by pipe A to empty the pool (in hour).
17 hr.25 hr.12 hr.15 hr.20 hr.Option D

Total time = 6hr40min = 400 min Given, A+B+C = 1 A = 2B and A+B = 2C so, C = 1/3 so, B = 2/9 and A = 4/9 so, A alone takes time = 400/4/9 = 900 min = 15 hr. - A man sold an article at 15% discount and earned 36% profit. The discount given on the article was Rs. 576. What should be the selling price if the shopkeeper wanted to earn 42% profit?
Rs.2500Rs.3408Rs.3255Rs.4205Rs.3002Option B

Let the marked price of the article be Rs.x 15% of x = 576 => x = Rs.3840 SP = 3840 – 576 = Rs.3264 Cost price of the article = (3264*100)/136 = Rs.2400 Required Selling Price = 142% of 2400 = Rs.3408 - A certain sum of money amounted to Rs.1680 at 8% in a year and Rs.760 amounted to Rs.1140 at 3% in the same period. If the rate of interest is simple find the sum.
Rs.600Rs.550Rs.700Rs.810Rs.720Option E

760 is amounted to 1140 at 3% SI=1140-760=380 T=380×100 760×3 = 50/3 𝑦𝑒𝑎𝑟𝑠 Now, P+(P×8×50)/(3×100) = 1680 P + 8P/6 = 1680 14P = 1680 × 6=Rs.720 - A basket contains 5 white and 9 black balls. There is another basket which contains 7 white and 7 black balls. One ball is to drawn from either of the two baskets. What is the probability of drawing a black ball?
4/73/87/115/94/7Option A

Probability of choosing a bucket = ½ Probability of black ball from the first bucket = ½ * 9C1/14C1 = 9/28 Probability of black ball from the scond bucket = ½ * 7C1/14C1 = 7/28 Required Probability = 9/28 + 7/28 = 4/7

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