Quant Test for SBI PO 2018 Prelim Exam Set – 61

Hello Aspirants

State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled onΒ 1st, 7th & 8th of July 2018. Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.Β 


 

Directions(1-5): Study the following graph and table and answer the following questions. The line graph shows the number of school students participated in the national level sports.

The table given the percentage of girls participated in the sports competition:

  1. What is the total number of boys who participated in the sports competition from State 3?
    610
    599
    648
    666
    606
    Option C
    π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘π‘œπ‘¦π‘  𝑀ho π‘π‘Žπ‘Ÿπ‘‘π‘–π‘π‘–π‘π‘Žπ‘‘π‘’π‘‘ 𝑖𝑛 𝑐h𝑒𝑠𝑠 π‘“π‘Ÿπ‘œπ‘š π‘ π‘‘π‘Žπ‘‘π‘’ 3 = 350 Γ— 84/ 100 = 294
    π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘π‘œπ‘¦π‘  𝑀hπ‘œ π‘π‘Žπ‘Ÿπ‘‘π‘–π‘π‘–π‘π‘Žπ‘‘π‘’π‘‘ 𝑖𝑛 πΉπ‘œπ‘œπ‘‘ π‘π‘Žπ‘™π‘™ π‘“π‘Ÿπ‘œπ‘š π‘ π‘‘π‘Žπ‘‘π‘’ 3 = 250 Γ— 52/ 100 = 130
    π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘π‘œπ‘¦π‘  𝑀hπ‘œ π‘π‘Žπ‘Ÿπ‘‘π‘–π‘π‘–π‘π‘Žπ‘‘π‘’π‘‘ 𝑖𝑛 π»π‘œπ‘π‘˜π‘’π‘¦ π‘“π‘Ÿπ‘œπ‘š π‘ π‘‘π‘Žπ‘‘π‘’ 3 = 350 Γ— 64 /100 = 224
    Total=648
    π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘π‘œπ‘¦π‘  𝑀ho π‘π‘Žπ‘Ÿπ‘‘π‘–π‘π‘–π‘π‘Žπ‘‘π‘’π‘‘ 𝑖𝑛 𝑐h𝑒𝑠𝑠 π‘“π‘Ÿπ‘œπ‘š π‘ π‘‘π‘Žπ‘‘π‘’ 3 = 350 Γ— 84 /100 = 294
    π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘π‘œπ‘¦π‘  𝑀hπ‘œ π‘π‘Žπ‘Ÿπ‘‘π‘–π‘π‘–π‘π‘Žπ‘‘π‘’π‘‘ 𝑖𝑛 πΉπ‘œπ‘œπ‘‘ π‘π‘Žπ‘™π‘™ π‘“π‘Ÿπ‘œπ‘š π‘ π‘‘π‘Žπ‘‘π‘’ 3 = 250 Γ— 52 /100 = 130
    π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘π‘œπ‘¦π‘  𝑀hπ‘œ π‘π‘Žπ‘Ÿπ‘‘π‘–π‘π‘–π‘π‘Žπ‘‘π‘’π‘‘ 𝑖𝑛 π»π‘œπ‘π‘˜π‘’π‘¦ π‘“π‘Ÿπ‘œπ‘š π‘ π‘‘π‘Žπ‘‘π‘’ 3 = 350 Γ— 64/ 100 = 224
    Total=648

     

  2. Number of boys participated in Hockey from States 1 and 3 together is what percentage of the average number of students participated in all the sports from state 2?
    105.15%
    122.23%
    98.9%
    101.5%
    115.43%
    Option E
    Number of boys who participated in Hockey from State 1
    = 300 Γ— 60 /100 = 180
    Number of boys who participated in Hockey from State 3= 350 Γ— 64 /100 = 224
    Total=404
    Average number of students who participated in all the sports from state 2 = [300 + 350 + 400]/ 3 = 350 π‘…π‘’π‘žπ‘’π‘–π‘Ÿπ‘’π‘‘ π‘π‘’π‘Ÿπ‘π‘’π‘›π‘‘π‘Žπ‘”π‘’ = 404 350 Γ— 100 = 115.43%

     

  3. What is the difference between the number of boys who participated in all the sports from state 4 and the number of girls who participated in Hockey from all states together?
    32
    60
    44
    51
    83
    Option A
    Number of boys who participated in all the sports from state 4, Number of boys who participated in Chess from State 4= 280 Γ— 60/ 100 = 168
    Number of boys who participated in Hockey from State 3= 280 Γ— 25/ 100 = 210
    Number of boys who participated in Hockey from State 3= 360 Γ— 35 /100 = 234
    Total=612
    π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘”π‘–π‘Ÿπ‘™π‘  𝑀hπ‘œ π‘π‘Žπ‘Ÿπ‘‘π‘–π‘π‘–π‘π‘Žπ‘‘π‘’π‘‘ 𝑖𝑛 π»π‘œπ‘π‘˜π‘’π‘¦ π‘“π‘Ÿπ‘œπ‘š π‘ π‘‘π‘Žπ‘‘π‘’ 1 = 300 Γ— 40/ 100 = 120
    π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘”π‘–π‘Ÿπ‘™π‘  𝑀hπ‘œ π‘π‘Žπ‘Ÿπ‘‘π‘–π‘π‘–π‘π‘Žπ‘‘π‘’π‘‘ 𝑖𝑛 π»π‘œπ‘π‘˜π‘’π‘¦ π‘“π‘Ÿπ‘œπ‘š π‘ π‘‘π‘Žπ‘‘π‘’ 2 = 400 Γ— 38/ 100 = 152
    π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘”π‘–π‘Ÿπ‘™π‘  𝑀hπ‘œ π‘π‘Žπ‘Ÿπ‘‘π‘–π‘π‘–π‘π‘Žπ‘‘π‘’π‘‘ 𝑖𝑛 π»π‘œπ‘π‘˜π‘’π‘¦ π‘“π‘Ÿπ‘œπ‘š π‘ π‘‘π‘Žπ‘‘π‘’ 3 = 350 Γ— 36 /100 = 126
    π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘”π‘–π‘Ÿπ‘™π‘  𝑀hπ‘œ π‘π‘Žπ‘Ÿπ‘‘π‘–π‘π‘–π‘π‘Žπ‘‘π‘’π‘‘ 𝑖𝑛 π»π‘œπ‘π‘˜π‘’π‘¦ π‘“π‘Ÿπ‘œπ‘š π‘ π‘‘π‘Žπ‘‘π‘’ 4 = 360 Γ— 35/ 100 = 126
    π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘”π‘–π‘Ÿπ‘™π‘  𝑀hπ‘œ π‘π‘Žπ‘Ÿπ‘‘π‘–π‘π‘–π‘π‘Žπ‘‘π‘’π‘‘ 𝑖𝑛 π»π‘œπ‘π‘˜π‘’π‘¦ π‘“π‘Ÿπ‘œπ‘š π‘ π‘‘π‘Žπ‘‘π‘’ 5 = 280 Γ— 20/100 = 56
    Total=580
    Difference=612-580=32

     

  4. How many students participated in Hockey from all the states?
    1100
    1690
    1225
    1548
    1220
    Option B
    300+400+350+360+280 = 1690

     

  5. Number of girls who participated in foot ball from state 5 is what percentage of the number of boys who participated in foot ball from state 2?
    42.25%
    34.75%
    55.55%
    20.02%
    31.13%
    Option B
    Number of girls who participated in foot ball from state 5= 300 Γ— 30/ 100 = 90
    Number of boys who participated in foot ball from state 2= 350 Γ— 74/ 100 = 259
    π‘…π‘’π‘žπ‘’π‘–π‘Ÿπ‘’π‘‘ π‘π‘’π‘Ÿπ‘π‘’π‘›π‘‘π‘Žπ‘”π‘’ = 90 259 Γ— 100 = 34.75%

     

  6. Directions(6-10): Find the missing term of the following series.

  7. ?, 4111,4623,4687,4695,4696
    20
    10
    15
    25
    30
    Option C
    +(8)^4, +(8)^3, +(8)^2, +(8)^1, +(8)^0

     

  8. 565,960,1276,?,1671,1750
    1513
    1600
    2002
    1712
    1102
    Option A
    +395,+316,+237,+158,+79

     

  9. 15,9.5,?,10.375,46.875,13.8125
    13.6
    22.5
    30
    16.6
    25.5
    Option E
    /2+2,/3+3,/4+4,/5+5,/6+6

     

  10. 7, 10, 8, 11, 9, 12, ?
    12
    15
    8
    10
    18
    Option D
    +3,-2,+3,-2+3,-2

     

  11. 210, 209, 213, 186, 202,?
    66
    88
    55
    77
    99
    Option D
    210 – 1Β³= 209
    209 + 2Β² = 213
    213 – 3Β³ = 186
    186 + 4Β² = 202
    202 – 5Β³ = 202 – 125 = 77

     


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