Hello Aspirants

**State Bank of India (SBI)** is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on **1st, 7th & 8th of July 2018. **Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.

**Directions(1-5):** What value should come in place of question mark ‘?’ in the following questions?

- 1(1/4) + 1(5/9) * 1(5/9) / 6(1/2) = ?
1(23/46)5(22/59)3(27/41)1(23/36)1(21/37)Option D

1(1/4) + 1(5/9) * 1(5/9) / 6(1/2) = ?

=> ? = 5/4 + 14/9 *13/8 *2/13

=> ? = 1(23/36) - (5^2 *14 – 6*7 + 4^? )^1/2= 18
462810Option C

(5^2 *14 – 6*7 + 4^? )^1/2= 18

=> 324 = 25*14 – 42 + 4^?

=> 4^? = 324 – 308 = 16

=> ? = 2 - 7/11 of 6908 – 4/9 of 7704 = ? * 72
13.511.718.223.38.2Option A

7/11 of 6908 – 4/9 of 7704 = ? * 72

=> 4396 – 3424 = 72 * ?

=> ? = 13.5 - 65% of 768 + 35% of 864 = ?
705.5691.9603.5700.3801.6Option E

65% of 768 + 35% of 864 = ?

499.2 + 302.4 = 801.6 - 4571 * 72 * = ? * 18 + 3621 * 36
1104211000120021304615050Option A

4571 * 72 * = ? * 18 + 3621 * 36

=> 18x = 36(4571*2 – 3621)

=> x = 11042 - Two trains start from stations A and B travel towards each other at speed of 50 km/hr. and 60 km/hr. resp. At the time of their meeting the second train has travelled 120 km more than the first. Find the distance between A and B.
1000 km1320 km1150 km1220 km1450 kmOption B

Let the trains meet after t time.

Then, 60t – 50t = 120

=> t = 12 hr.

Distance from A to B = 50*12 + 60*12 = 1320 km - A playground is in the shape of a rectangle. A sum of Rs. 1000 was spent to make the ground usable at the rate of 25 paise per metre square. The breadth of the ground is 50m. If the length of the ground is increased by 20 m, what will be the expenditure (in Rupees) at the same rate per metre square.?
Rs.1010Rs.1720Rs.1250Rs.1440Rs.1200Option C

Area of a rectangular field = 1000/0.25

= 4000 m sq.

Length = 4000/50 = 80 m

New length = 80 + 20 = 100 m

New area = 100 * 50 = 5000 m sq.

New expenditure = 5000*(25/100) = Rs.1250 - A 10 hectare of a field is reaped by 2 men, 3 women and 4 children together in 10 days. If working capabilities of a man, a woman and a children are in the ratio 5:4:2, then in how many days a 16 hectare field will be reaped by 6 men, 4 women and 7 children?
6 days4 days8 days12 days10 daysOption C

One day work of 2 men = 10 units One day work of 3 women = 12 units

One day work of 4 children = 8 units Let time taken be T.

(10+12+8)*10/10 = [(6*5) + (4*4) + (7*2)]*T /16

=> 30 * 16 = T * 60

=> T = 8 days - Rajesh has a total of Rs.42,000. And in that, he lends Rs.8,000 at 9/2% per annum simple interest and Rs.12,000 at 8% per annum simple interest. He lends the remaining money at a certain rate of interest so that he gets total interest of Rs. 3600 at the end of one year. The rate of interest per annum, at which the remaining money is lent, is?
31.03%20.26%15.15%10.36%11.33%Option D

For first loan 𝑆𝐼 = 𝑃*𝑁*𝑅/ 100

= 8000×9×1/ 100×2 = 360

For Second loan=12000×8×1/100 = 960

Total interest = 3600 So for the third loan

SI = 3600 – (960+360) = 2280

Rate of interest for third loan = 2280×100/22000 = 10.36% - I forgot the last digit of a 7-digit telephone number. If 1 randomly dial the final 3 digits after correctly dialling the first four, then what is the chance of dialling the correct number?
1/50001/30001/20001/10001/4000Option D

It is given that last three digits are randomly dialled. Then each of the digit can be selected out of 10 digits in 10 ways.

Hence, required probability =(1/10)^3 = 1/1000