# Quant Test for SBI PO 2018 Prelim Exam Set – 70

Hello Aspirants

State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on 1st, 7th & 8th of July 2018. Details of the exam are as under: Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.

Directions(1-5): Find the missing term of the given series.

1. 4, 8, 16, 24, 36, ?
40
48
34
32
45
Option B
Pattern is 2^2, 3^2-1, 4^2, 5^2 – 1, 6^2 and so on.
? = 48

2. 3, 22, ?, 673, 2696, 8093
113
130
134
122
150
Option C
×7 + 1, ×6 + 2, ×5 + 3, ×4 + 4, ×3 + 5….
=>?=22 × 6 + 2 = 134

3. 286 ,142, ?, 34, 16, 7
50
80
40
60
70
Option E
(/ 2 – 1), (/ 2 – 1), (/2 – 1)…
=>142/2 – 1 = 71 –1 = 70

4. 17, 9, ?, 16.5, 35, 90
15
10
21
25
17
Option B
(×0.5 + 0.5), (×1 + 1), (×1.5 + 1.5), (×2 + 2)
=> 9 × 1 + 1 = 10

5. 730, 675, 626, 575, ?
515
530
680
720
844
Option B
Pattern is (27^2+1),( 26^2 – 1), (25^2+1),(24^2 – 1), and so on.
? = 23^2+ 1= 530 .

6. Two pipes A and B can fill a tank in 15 hours and 20 hours respectively while a third pipe C can empty the full tank in 25 hours. All the three pipes are opened in the beginning. After 10 hours, C is closed. Now how much time more is required to fill the tank?
5 hrs.
3 hrs.
2 hrs.
9 hrs.
4 hrs.
Option C
Let the required time be T hours.
Now part filled by A in (10 + T) hours + part filled by B in (10 + T) hours + part empty by C in 10 hours = 1
=>[𝑇 + 10]/15+[𝑇 + 10]/20−10/25=1
=>𝑇= 2 hrs.

7. A, B and C can do a piece of work individually in 8, 12 and 15 days, respectively. A and B start working but A quits after working for 2 days. After this, C joins B till the completion of work. In how many days will the work be completed?
3(1/9) days
5(8/9) days
2(2/5) days
5(3/7) days
7(8/9) days
Option B
Work was done by A and b in 1 day
=1/8+1/12=5/24 2 day’s work of A and B = 10/24
After 2 day’s A left the work
∴ Remaining work =1−10/24=14/24
One day work of B and C together =1/12+1/15=9/60
So, the number of days required by B and C to finish work
=14/24/9/60 =14/24×60/9 =35/9
∴ Total days to complete the work
=2+35/9 = 53/9 = 5(8/9) days

8. Mahesh borrows Rs.7500 from a bank at SI. After 5 years he paid Rs.3500 to the bank and at the end of 8 yrs from the date of borrowing he paid Rs.6500 to the bank to settle the account. Find the rate of interest.
9.05%
7.02%
4.00%
5.05%
8.03%
Option D
Total interest
=(interest on 7500 for 5 years)+(interest on 4000 for 3 years)
=> 7500×5×𝑅 /100 + 4000×3×𝑅/ 100 = 3500+6500-7500
=> 375R+120R=2500
=>R=5.05%

9. 85 kg of a mixture contains milk and water in the ratio 27 : 7. How much more water is to be added to get a new mixture containing milk and water in the ratio 3 : 1?
5 kg.
8 kg.
7 kg.
10 kg.
4 kg.
Option A
Milk in 85 kg of mixture = (85×27/34) kg =135/2 kg.
Water in it = (85−135/2) kg =352 kg.
Let x kg of water be added to it.
Then, (135/2)/(35/2 + 𝑥)= 31
=>135/35+2𝑥=31
=>105+6𝑥=135
=> 6𝑥=30
=>𝑥=5.
Hence,Quantity of water to be added = 5 kg.

10. Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?
11/17
9/20
10/19
2/11
5/9
Option B
S = {1, 2, 3, 4, …., 19, 20}.
Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.
P(E) = n(E)/n(S) =9/20 .