Quant Test for SBI PO Prelims 2020 Exam set – 20

  1. Study the follwing and answer the questions:

    a)x^2 – 55x + 750 = 0
    b)y^2 – 60y + 900 = 0

    x>y
    x
    x is less than or equal to y
    x is greater than or equal to y
    x=y or relationship cannot be established
    Option C
    x=25 , 30
    y-30 , 30

     

  2. 2 , 4 , 12 , 44 , 176 , 890 .Find the wrong number?
    44
    4
    12
    176
    890
    Option A
    2*1+2=4
    4*2+4=12
    12*3+6=42

     

  3. 10 , 11 , 15 , 42 , 296 , 3423.Find the wrong number?
    10
    11
    296
    15
    3423
    Option C
    10+1^1=11
    11+2^2=15
    15+3^2=42
    42+4^2=298

     

  4. The number is increased by 8% and then decreased by 6%.Then the number so obtained is 91.2 more than original number.What is the original number?
    5000
    9000
    8000
    6000
    7500
    Option D
    Let it be y.
    Effective percentae=8-6-8*6/100=1.520%
    Therefore,original number=91.20/1.52 * 100

     

  5. X,Y and Z are partners.X’s money was used for 6 months and Y’s money was used for 8 months.Z had invested Rs 11900 for the whole year.At end of year,the profit among X,Y and Z was divided in ratio of 15:16:42.The total amount of money invested by X and Y together was which of the following?
    Rs 12000
    Rs 12500
    Rs 15300
    Rs 14700
    Rs 15100
    Option C
    Let money invested by X be Rs p and money invested by Y be Rs q
    p*6/(11900*12)=15/42
    p=Rs 8500
    Also,q * 8/(11900*12)=16/42
    q=Rs 6800
    Total=Rs 15300

     

  6. Ramesh borrowed Rs 4000 at rate of 8% p.a compunded annually.He paid Rs 500 at end of one year and Rs 1000 at end of second year.How much should he pay at end of 3rd year to finish his deal with lender?
    Rs 3375.648
    Rs 3385.540
    Rs 2541.105
    Rs 4514.100
    None of these
    Option A
    Amount due after one year=108% of 4000-500=Rs 3820
    Amount due after two years=108% of 3820 – 1000= Rs 3125.60
    Amount due after three years=108% of 3125.60=Rs 3375.648

     

  7. What is permieter of circle whose area is equal to area of rectangle of lenght 84 cm and breadth 66 cm ?
    250 cm
    264 cm
    275 cm
    280 cm
    None of these
    Option B
    Let radius be r.
    Pie r^2 =84*66
    r^2=84*66*7/22
    r=42 cm
    Therefore,Perimeter=2*22/7/42=264 cm

     

  8. The average of family of four memebers 7 years ago was 20 years.A child,having been born,the average age of family now is 22 years.What is the present age of child?
    2 years
    1 years
    4 years
    5 years
    None of these
    Option A
    Total age =20*4=80 years
    Total present age of all 4 member=80+28=108
    Total age of all 5 memebers=22*5=110 years
    Therefore,age of child=110-108=2 years

     

  9. Total number of candidates in a college is 840 and ratio number of males to females is 13:8.Few females and 50 males joined the college due to which ratio of males to females becomes 3:2.The number of females who joined the college are which of the folliwng?
    50
    40
    60
    75
    None of these
    Option C
    Number of males in college-840/21*13=520
    Number of females in college=840/21*8=320
    Let the number of females who joined the college be x.
    Then,(520+50)/(320+x)=3/2
    x=60

     

  10. Length of rectangle is incresed by 50 percent.By what percent should the width be reduced to maintain same area?
    25%
    100/3%
    100%
    50%
    75/3%
    Option B
    Let width reduced be x%.
    Effective chnage=50-x-50 * x /100 = 50 – 3x/2
    3x/2=50
    x=100/3%

     


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