- A,B and C go for party, A’s meal costs 60% more than that of B while the cost of the meal of A was 3/5th of the meal of C. If B paid Rs.180 for his meal. Find the average expenses of the three persons.
Rs.310Rs.330Rs.320Rs.316Rs.323Option D

B’s paid = Rs.180

A’s bill = 180*160/100 = Rs.288

(3/5) of C = 288

=>C = Rs.480

Total bill = 288+180+480 =Rs.948

Average expenses = 948/3 = Rs.316 - Two trains A and B of same length running in same direction with a speed of 66 km/hr and 93 km/hr resp. Find the time to cross each other, if train A crosses a standing man in 9 seconds?
35 seconds44 seconds30 seconds32 seconds40 secondsOption B

Length of train A = 66*(5/18)*9 = 165 m

Time to cross each other = [(165+165)/(93-66)]*18/5

= 44 seconds - A sum put at a certain rate of simple interest for 4 years. If the interest would have been 5% higher than the previous rate Rs.4500 would have been earned more. Find the sum.
2834225653225002145523456Option C

Let sum be x and rate be r%.

(x*4*(r+5))/100 – (x*4*r)/100 = 4500

=>x = 22500 - Three pipes A,B and C can fill a tank in 18 hours. After working at it together for 6 hours, C closed and A and B can fill the remaining part in 16 hours. How much time taken by C to fill the tank alone?
72 hours70 hours65 hours77 hours66 hoursOption A

Three pipes 1 hour work = 1/18

6 hours work = 1/3

Remaining work = 1-1/3 = 2/3

2/3*(A+B) = 16

(A+B)’s work =24 hour

(A+B)’s 1 hour work = 1/24

Now,

C’s 1 hour work = 1/18 – 1/24

= 72 hours - A box contains colourful marbles 5 yellow, 4 black and 6 green balls. If 3 balls are drawn at randomly. Find the probability of getting at least 1 yellow marble?
61/9765/9257/9361/9167/91Option E

Probability of getting non-yellow = 10C3/15C3

Required Probability = 1 – 24/91 = 67/91

**Directions(6-10):**Compare the values of x and y and select a correct option. - I. x 2 + 2x – 15 = 0

II. y2 + y – 56 = 0

x > yx =< yx >= yx < yCan’t be determinedOption E

I. x 2 + 2x – 15 = 0

(x + 5) (x – 3) = 0

X = -5, 3

II. y 2 + y – 56 = 0

(y + 8) (y – 7) = 0

Y = -8, 7

Can’t be determined - I. 5x^2 + 16x – 16 = 0

II. 4y^2 + 3y – 22 = 0

x >= yx > yx =< yx < yCan’t be determinedOption E

I. 5x^2 + 16x – 16 = 0

5x^2 + 20x – 4x – 16 = 0

5x(x + 4) – 4 (x + 4) = 0

(5x – 4) (x + 4) = 0

X = 4/5, -4 = 0.8, -4

II. 4y^2 + 3y – 22 = 0

4y^2 -8y + 11y – 22 = 0

4y(y – 2) + 11 (y – 2) = 0

(4y + 11) (y – 2) = 0

Y = -11/4, 2 = -2.75, 2

Can’t be determined - I. x ^2 + 7x – 330 = 0

II. y = (194481)^1/4

x >= yx =< yx < yx > yCan’t be determinedOption C

I. x^2 + 7x – 330 = 0

(x – 15) (x + 22) = 0

X = 15, -22

II. y = √441

Y = 21

x < y - I. 4x^2 – 6x – 18 = 0

II. 5y^2 + 6y – 27 = 0

x > yx >= yx < yx =< yCan’t be determinedOption E

I. 4x^2 – 6x – 18 = 0

4x^2 – 12x + 6x – 18 = 0

4x(x – 3) + 6(x – 3) = 0

(4x + 6) (x – 3) = 0

X = -6/4, 3 = -3/2, 3 = -1.5,

3 II. 5y2 + 6y – 27 = 0

5y^2 + 15y – 9y – 27 = 0

5y(y + 3) – 9(y + 3) = 0

(5y – 9)(y + 3) = 0

Y = 9/5, -3 = 1.8, -3

Can’t be determined - I. x ^2 – 12x + 36 = 0

II. 5y^2 + 4y – 12 = 0

x >= yx < yx > yx =< yCan’t be determinedOption C

I. x^ 2 – 12x + 36 = 0

(x – 6)(x – 6) = 0

X = 6, 6

II. 5y^2 + 4y – 12 = 0

5y^2 + 10y – 6y – 12 = 0

5y (y + 2) – 6 (y + 2) = 0

(5y – 6) (y + 2) = 0

Y = 6/5, – 2 = 1.2, -2

x > y