Quant Test for SBI PO Prelims Exam set – 03

  1. A,B and C go for party, A’s meal costs 60% more than that of B while the cost of the meal of A was 3/5th of the meal of C. If B paid Rs.180 for his meal. Find the average expenses of the three persons.

    Rs.310
    Rs.330
    Rs.320
    Rs.316
    Rs.323
    Option D
    B’s paid = Rs.180
    A’s bill = 180*160/100 = Rs.288
    (3/5) of C = 288
    =>C = Rs.480
    Total bill = 288+180+480 =Rs.948
    Average expenses = 948/3 = Rs.316

     

  2. Two trains A and B of same length running in same direction with a speed of 66 km/hr and 93 km/hr resp. Find the time to cross each other, if train A crosses a standing man in 9 seconds?
    35 seconds
    44 seconds
    30 seconds
    32 seconds
    40 seconds
    Option B
    Length of train A = 66*(5/18)*9 = 165 m
    Time to cross each other = [(165+165)/(93-66)]*18/5
    = 44 seconds

     

  3. A sum put at a certain rate of simple interest for 4 years. If the interest would have been 5% higher than the previous rate Rs.4500 would have been earned more. Find the sum.
    28342
    25653
    22500
    21455
    23456
    Option C
    Let sum be x and rate be r%.
    (x*4*(r+5))/100 – (x*4*r)/100 = 4500
    =>x = 22500

     

  4. Three pipes A,B and C can fill a tank in 18 hours. After working at it together for 6 hours, C closed and A and B can fill the remaining part in 16 hours. How much time taken by C to fill the tank alone?
    72 hours
    70 hours
    65 hours
    77 hours
    66 hours
    Option A
    Three pipes 1 hour work = 1/18
    6 hours work = 1/3
    Remaining work = 1-1/3 = 2/3
    2/3*(A+B) = 16
    (A+B)’s work =24 hour
    (A+B)’s 1 hour work = 1/24
    Now,
    C’s 1 hour work = 1/18 – 1/24
    = 72 hours

     

  5. A box contains colourful marbles 5 yellow, 4 black and 6 green balls. If 3 balls are drawn at randomly. Find the probability of getting at least 1 yellow marble?
    61/97
    65/92
    57/93
    61/91
    67/91
    Option E
    Probability of getting non-yellow = 10C3/15C3
    Required Probability = 1 – 24/91 = 67/91

     
    Directions(6-10): Compare the values of x and y and select a correct option.

  6. I. x 2 + 2x – 15 = 0
    II. y2 + y – 56 = 0
    x > y
    x =< y
    x >= y
    x < y
    Can’t be determined
    Option E
    I. x 2 + 2x – 15 = 0
    (x + 5) (x – 3) = 0
    X = -5, 3
    II. y 2 + y – 56 = 0
    (y + 8) (y – 7) = 0
    Y = -8, 7
    Can’t be determined

     

  7. I. 5x^2 + 16x – 16 = 0
    II. 4y^2 + 3y – 22 = 0
    x >= y
    x > y
    x =< y
    x < y
    Can’t be determined
    Option E
    I. 5x^2 + 16x – 16 = 0
    5x^2 + 20x – 4x – 16 = 0
    5x(x + 4) – 4 (x + 4) = 0
    (5x – 4) (x + 4) = 0
    X = 4/5, -4 = 0.8, -4
    II. 4y^2 + 3y – 22 = 0
    4y^2 -8y + 11y – 22 = 0
    4y(y – 2) + 11 (y – 2) = 0
    (4y + 11) (y – 2) = 0
    Y = -11/4, 2 = -2.75, 2
    Can’t be determined

     

  8. I. x ^2 + 7x – 330 = 0
    II. y = (194481)^1/4
    x >= y
    x =< y
    x < y
    x > y
    Can’t be determined
    Option C
    I. x^2 + 7x – 330 = 0
    (x – 15) (x + 22) = 0
    X = 15, -22
    II. y = √441
    Y = 21
    x < y

     

  9. I. 4x^2 – 6x – 18 = 0
    II. 5y^2 + 6y – 27 = 0
    x > y
    x >= y
    x < y
    x =< y
    Can’t be determined
    Option E
    I. 4x^2 – 6x – 18 = 0
    4x^2 – 12x + 6x – 18 = 0
    4x(x – 3) + 6(x – 3) = 0
    (4x + 6) (x – 3) = 0
    X = -6/4, 3 = -3/2, 3 = -1.5,
    3 II. 5y2 + 6y – 27 = 0
    5y^2 + 15y – 9y – 27 = 0
    5y(y + 3) – 9(y + 3) = 0
    (5y – 9)(y + 3) = 0
    Y = 9/5, -3 = 1.8, -3
    Can’t be determined

     

  10. I. x ^2 – 12x + 36 = 0
    II. 5y^2 + 4y – 12 = 0
    x >= y
    x < y
    x > y
    x =< y
    Can’t be determined
    Option C
    I. x^ 2 – 12x + 36 = 0
    (x – 6)(x – 6) = 0
    X = 6, 6
    II. 5y^2 + 4y – 12 = 0
    5y^2 + 10y – 6y – 12 = 0
    5y (y + 2) – 6 (y + 2) = 0
    (5y – 6) (y + 2) = 0
    Y = 6/5, – 2 = 1.2, -2
    x > y

     

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