# Quant Test for SBI PO Prelims Exam set – 03

1. A,B and C go for party, A’s meal costs 60% more than that of B while the cost of the meal of A was 3/5th of the meal of C. If B paid Rs.180 for his meal. Find the average expenses of the three persons.

Rs.310
Rs.330
Rs.320
Rs.316
Rs.323
Option D
B’s paid = Rs.180
A’s bill = 180*160/100 = Rs.288
(3/5) of C = 288
=>C = Rs.480
Total bill = 288+180+480 =Rs.948
Average expenses = 948/3 = Rs.316

2. Two trains A and B of same length running in same direction with a speed of 66 km/hr and 93 km/hr resp. Find the time to cross each other, if train A crosses a standing man in 9 seconds?
35 seconds
44 seconds
30 seconds
32 seconds
40 seconds
Option B
Length of train A = 66*(5/18)*9 = 165 m
Time to cross each other = [(165+165)/(93-66)]*18/5
= 44 seconds

3. A sum put at a certain rate of simple interest for 4 years. If the interest would have been 5% higher than the previous rate Rs.4500 would have been earned more. Find the sum.
28342
25653
22500
21455
23456
Option C
Let sum be x and rate be r%.
(x*4*(r+5))/100 – (x*4*r)/100 = 4500
=>x = 22500

4. Three pipes A,B and C can fill a tank in 18 hours. After working at it together for 6 hours, C closed and A and B can fill the remaining part in 16 hours. How much time taken by C to fill the tank alone?
72 hours
70 hours
65 hours
77 hours
66 hours
Option A
Three pipes 1 hour work = 1/18
6 hours work = 1/3
Remaining work = 1-1/3 = 2/3
2/3*(A+B) = 16
(A+B)’s work =24 hour
(A+B)’s 1 hour work = 1/24
Now,
C’s 1 hour work = 1/18 – 1/24
= 72 hours

5. A box contains colourful marbles 5 yellow, 4 black and 6 green balls. If 3 balls are drawn at randomly. Find the probability of getting at least 1 yellow marble?
61/97
65/92
57/93
61/91
67/91
Option E
Probability of getting non-yellow = 10C3/15C3
Required Probability = 1 – 24/91 = 67/91

Directions(6-10): Compare the values of x and y and select a correct option.

6. I. x 2 + 2x – 15 = 0
II. y2 + y – 56 = 0
x > y
x =< y
x >= y
x < y
Can’t be determined
Option E
I. x 2 + 2x – 15 = 0
(x + 5) (x – 3) = 0
X = -5, 3
II. y 2 + y – 56 = 0
(y + 8) (y – 7) = 0
Y = -8, 7
Can’t be determined

7. I. 5x^2 + 16x – 16 = 0
II. 4y^2 + 3y – 22 = 0
x >= y
x > y
x =< y
x < y
Can’t be determined
Option E
I. 5x^2 + 16x – 16 = 0
5x^2 + 20x – 4x – 16 = 0
5x(x + 4) – 4 (x + 4) = 0
(5x – 4) (x + 4) = 0
X = 4/5, -4 = 0.8, -4
II. 4y^2 + 3y – 22 = 0
4y^2 -8y + 11y – 22 = 0
4y(y – 2) + 11 (y – 2) = 0
(4y + 11) (y – 2) = 0
Y = -11/4, 2 = -2.75, 2
Can’t be determined

8. I. x ^2 + 7x – 330 = 0
II. y = (194481)^1/4
x >= y
x =< y
x < y
x > y
Can’t be determined
Option C
I. x^2 + 7x – 330 = 0
(x – 15) (x + 22) = 0
X = 15, -22
II. y = √441
Y = 21
x < y

9. I. 4x^2 – 6x – 18 = 0
II. 5y^2 + 6y – 27 = 0
x > y
x >= y
x < y
x =< y
Can’t be determined
Option E
I. 4x^2 – 6x – 18 = 0
4x^2 – 12x + 6x – 18 = 0
4x(x – 3) + 6(x – 3) = 0
(4x + 6) (x – 3) = 0
X = -6/4, 3 = -3/2, 3 = -1.5,
3 II. 5y2 + 6y – 27 = 0
5y^2 + 15y – 9y – 27 = 0
5y(y + 3) – 9(y + 3) = 0
(5y – 9)(y + 3) = 0
Y = 9/5, -3 = 1.8, -3
Can’t be determined

10. I. x ^2 – 12x + 36 = 0
II. 5y^2 + 4y – 12 = 0
x >= y
x < y
x > y
x =< y
Can’t be determined
Option C
I. x^ 2 – 12x + 36 = 0
(x – 6)(x – 6) = 0
X = 6, 6
II. 5y^2 + 4y – 12 = 0
5y^2 + 10y – 6y – 12 = 0
5y (y + 2) – 6 (y + 2) = 0
(5y – 6) (y + 2) = 0
Y = 6/5, – 2 = 1.2, -2
x > y