**Direction(1-5): **What approximate value will come in place of question mark ‘?’ in the following questions.

- 79.008% of 799.998 + 42.99% of 499.999 – 53.93% of 699.92 = ?
400444356550469Option E

79.008% of 799.998 + 42.99% of 499.999 – 53.93% of 699.92 = ?

=> 79 * 800/100 + 43 * 500 / 100 – 54*700/100

=> 632 + 215 – 378 = 469 - 3263 × 246 – 18611 = ? + 5883
755750766430745369778204795547Option D

3263 × 246 – 18611 = ? + 5883

=> 3263 × 246 = 802698

=>802698 – (18611 + 5883) = 778204 -
(23.1)^2 + (48.6)^2 – (39.8)^2 = 163.84 + ?

11481563122519901425Option A

(23.1)^2 + (48.6)^2 – (39.8)^2 = 163.84 + ?

=> 533.61 + 2361.96 – 1584.04 = 163.84 + ?

=>1311.53 – 163.84 = 1147.69 == 1148 - (331 + 19)*(15 – 11)*(37 + 13) = ?
5000070000900004000080000Option B

(331 + 19)*(15 – 11)*(37 + 13) = ?

=> 350 * 4 * 50 = 70000

12.5% of 350 * 8.4% of 250 = ?

850889919930900Option C

12.5% of 350 * 8.4% of 250 = ?

=> 6.25 * 7 * 21 = 918.75 == 919

The marked price of a radio is Rs 480. The shopkeeper allows a discount of 10% and still gains 8%. If no discount is allowed, find his gain percent.

10%14%20%25%18%Option C

M. P. = Rs 480/-

Discount = 10%

S.P. = 90/100 × 480 = Rs 432

P% = 8%

C.P. = 100/108 × 432 = 400

If no discount is given then S.P. = M.P. i.e. S.P. = 480

(480 – 400)/400 × 100 = 80/400 × 100 = 20%

Pankaj sells a book to Mayank at a profit of 20% and Sunil sells this book to Varun at a profit of 25%. Now, Varun sells this book at a loss of 10% to Ram. At what percentage loss should Ram sells this book now so that his SP becomes equal to Pankaj’s CP?

30%15%20%24%26%Option E

Let initial CP of book is x.

CP to Ram = 120/100*125/100*90x/100 = 1.35x

Required % decrease = [1.35x – x ]/1.35x*100 = 25.92% == 26%- The difference between the sum of four consecutive odd numbers and three consecutive even numbers together is 20. Also, the largest even number is 5 more than the largest odd number. What is the sum of the smallest odd number and the smallest even number ?
6759839077Option E

Let the odd numbers be x, x + 2, x + 4, x + 6 and the even numbers be y, y + 2, y + 4.

Now (4x + 12) – (3y + 6) = 20 And (y + 4) – (x + 6) = 5

Solving them, we get x = 35 and y = 42

Required sum = 35 + 42 = 77

A, B and C can finish a work in 10, 12 and 15 days respectively. They start working together. If B stops after 2 days, how long would it take A and C to finish the remaining work?

54763Option E

A + B + C in 2 days.

2(1/10 + 1/12 + 1/15) = ½ work

B withdraws, A+C will do the whole work = 10*15/(10+15) = 6 days

SO, 6/2 = 3 more days- In one litre of mixture of alcohol and water, 30% is water. The amount of alcohol that must be added to the mixture, so that the part of water in the mixture becomes 15%, is:
3000 ml1000 ml5000 ml2000 ml4000 mlOption B

In 1000 ml of mixture, Alcohol = 700 ml

Water = 300 ml

Let x ml of alcohol is mixed.

300/(1000+x)*100 = 15

=1000 ml