Direction(1-5): What approximate value will come in place of question mark ‘?’ in the following questions.
- 79.008% of 799.998 + 42.99% of 499.999 – 53.93% of 699.92 = ?
400444356550469Option E
79.008% of 799.998 + 42.99% of 499.999 – 53.93% of 699.92 = ?
=> 79 * 800/100 + 43 * 500 / 100 – 54*700/100
=> 632 + 215 – 378 = 469 - 3263 × 246 – 18611 = ? + 5883
755750766430745369778204795547Option D
3263 × 246 – 18611 = ? + 5883
=> 3263 × 246 = 802698
=>802698 – (18611 + 5883) = 778204 -
(23.1)^2 + (48.6)^2 – (39.8)^2 = 163.84 + ?
11481563122519901425Option A
(23.1)^2 + (48.6)^2 – (39.8)^2 = 163.84 + ?
=> 533.61 + 2361.96 – 1584.04 = 163.84 + ?
=>1311.53 – 163.84 = 1147.69 == 1148 - (331 + 19)*(15 – 11)*(37 + 13) = ?
5000070000900004000080000Option B
(331 + 19)*(15 – 11)*(37 + 13) = ?
=> 350 * 4 * 50 = 70000
12.5% of 350 * 8.4% of 250 = ?
850889919930900Option C
12.5% of 350 * 8.4% of 250 = ?
=> 6.25 * 7 * 21 = 918.75 == 919
The marked price of a radio is Rs 480. The shopkeeper allows a discount of 10% and still gains 8%. If no discount is allowed, find his gain percent.
10%14%20%25%18%Option C
M. P. = Rs 480/-
Discount = 10%
S.P. = 90/100 × 480 = Rs 432
P% = 8%
C.P. = 100/108 × 432 = 400
If no discount is given then S.P. = M.P. i.e. S.P. = 480
(480 – 400)/400 × 100 = 80/400 × 100 = 20%
Pankaj sells a book to Mayank at a profit of 20% and Sunil sells this book to Varun at a profit of 25%. Now, Varun sells this book at a loss of 10% to Ram. At what percentage loss should Ram sells this book now so that his SP becomes equal to Pankaj’s CP?
30%15%20%24%26%Option E
Let initial CP of book is x.
CP to Ram = 120/100*125/100*90x/100 = 1.35x
Required % decrease = [1.35x – x ]/1.35x*100 = 25.92% == 26%- The difference between the sum of four consecutive odd numbers and three consecutive even numbers together is 20. Also, the largest even number is 5 more than the largest odd number. What is the sum of the smallest odd number and the smallest even number ?
6759839077Option E
Let the odd numbers be x, x + 2, x + 4, x + 6 and the even numbers be y, y + 2, y + 4.
Now (4x + 12) – (3y + 6) = 20 And (y + 4) – (x + 6) = 5
Solving them, we get x = 35 and y = 42
Required sum = 35 + 42 = 77
A, B and C can finish a work in 10, 12 and 15 days respectively. They start working together. If B stops after 2 days, how long would it take A and C to finish the remaining work?
54763Option E
A + B + C in 2 days.
2(1/10 + 1/12 + 1/15) = ½ work
B withdraws, A+C will do the whole work = 10*15/(10+15) = 6 days
SO, 6/2 = 3 more days- In one litre of mixture of alcohol and water, 30% is water. The amount of alcohol that must be added to the mixture, so that the part of water in the mixture becomes 15%, is:
3000 ml1000 ml5000 ml2000 ml4000 mlOption B
In 1000 ml of mixture, Alcohol = 700 ml
Water = 300 ml
Let x ml of alcohol is mixed.
300/(1000+x)*100 = 15
=1000 ml