# Quant Test for SBI PO Prelims Exam set – 09

1. A can do a piece of work in 8 days which B can destroy in 3 days. A has worked for 6 days, during the last 2 days of which B has been destroying. How many days must A now work alone to complete the work?
9(1/2) days
4(1/6) days
7(1/3) days
8(1/2) days
3(1/5) days
Option C
In 6 days part of the work done by A = 6/8 = Â¾
During 2 days, part of the work destroyed by B = 2/3
Work done = Â¾ â€“ 2/3 = 1/12
Remaining work = 1 â€“ 1/12
Required no of days = 11/12*8 = 7(1/3) days

2. Out of his total income, Mr. Kapoor spends 20% on house rent and 70% of the rest on house hold expenses. If he saves Rs 1,800 what is his total income (in rupees)?
Rs.8100
Rs.7500
Rs.9000
Rs.6200
Rs.7000
Option B
Saving % = 100 â€“ (20 + 56) = 24%
24% = 1800
100% = 1800/24*100 = Rs.7500

3. A and B are partners in a business. They invest in the ratio 5 : 6, at the end of 8 months A withdraws. If they receive profits in the ratio of 5 : 9, find how long Bâ€™s investment was used?
14
8
10
16
12
Option E
5x : 6x, Let B investment was used for y months
8*5 x : 6x *y = 5 : 9
=>y= 12

4. A train is moving at a speed at a speed of 132 km/hour. If the length of the train is 110 metres, how long will it take to cross a railway platform 165 metres long?
7.5 seconds
9.1 seconds
8.6 seconds
3.3 seconds
4.2 seconds
Option A
132*5/18 = (100+165)/x
=>x = 7.5 seconds

5. A committee of 3 members is to be selected out of 3 men and 2 women. What is the probability that the committee has atleast one woman?
5/14
9/10
6/13
7/12
8/11
Option B
Probability = (2C1*3c2 + 2c2*3c1)/5c3 = 9/10

6. Directions(6-10): Find the values of x and y and then compare them and choose a correct option.

7. I. 4x + 7y = 42
II. 3x â€“ 11y = â€“ 1

y >x
y>=x
x>=y
x > y
No relation
Option D
On solving both the equations, we get x = 7
y = 2
x > y

8. I. 3x^2 â€“ 19x â€“ 14 = 0
II. 2y^2 + 5y + 3 = 0

x>=y
x > y
y >x
No relation
y>=x
Option B
I. 3x^2 â€“ 19x â€“ 14 = 0
=>3x^2 -21 x + 2x â€“ 14 = 0
=>3x (x -7) +2(x -7) = 0
=>(x-7)(3x+2) = 0
=>x = 7, -3/2
II. 2y^2 + 5y + 3 = 0
=>2y^2 +2y +3y + 3 = 0
=>2y (y+1) + 3(y+1) = 0
=>(y+1)(2y+3) = 0
=>y = -1, -3/2
x > y

9. I. x^2 + 14x + 49 = 0
II. y^2 + 9y = 0

x>=y
y>=x
No relation
x > y
y >x
Option C
I. x^2 + 14x + 49 = 0
=>X^2 + 7X+7X + 49 = 0 =>x(x+7)+7(x+7) = 0
=>(x+7)(x+7) = 0
=>x = -7,-7
II. y^2 + 9y = 0
=>y = -9,0
No relation

10. I. 3x^2 â€“ 4x â€“ 32 = 0
II. 2y^2 â€“ 17y + 36 = 0

x>=y
No relation
y>=x
y >x
x > y
Option C
I. 3x^2 â€“ 4x â€“ 32 = 0
=>3x^2 – 12x + 8x – 32 = 0
=> 3x(x – 4) + 8(x -4) = 0
=>(x-4)(3x+8) = 0
=>x = 4,-8/3
II. 2y^2 â€“ 17y + 36 = 0
=>2y^2 – 8y – 9y + 36 = 0
=>2y(y- 4) -9(y-4) = 0
=>(y-4)(2y-9) = 0
=>y = 4,4.5
y>=x

11. I. 9x^2 â€“ 29x + 22 = 0
II. y^2 â€“ 7y + 12 = 0

No relation
x > y
y>=x
y >x
x>=y
Option D
I. 9x^2 â€“ 29x + 22 = 0
=>9x^2 â€“ 18x â€“ 11 x + 22 = 0
=>9x (x-2) -11(x-2) = 0
=>(x-2)(9x-11) = 0
=>x = 2,11/9
II. y^2 â€“ 7y + 12 = 0
=>y^2 -4y -3y + 12 = 0
=>y(y-4) -3 (y -4) = 0
=>(y-4)(y-3) = 0
=>y = 4,3
y >x