Quant Test for SBI PO 2018 Prelim Exam Set – 14

Hello Aspirants

State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on 1st, 7th & 8th of July 2018. Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam. 

Directions(1-5): Find the next term of the series.

1. 1401, 1402, 705, ?, 77
   200
   150
   244
   250
   300
   Option C
   1401, 1402, 705, ?, 77
   1401/1+1² = 1402
   1402/2+2² =705
   705/3+3² =244
   244/4+4²= 77

    

2. 10, 6, 12, 35, ?, 591.75
   129.5
   105.6
   112.5
   135.2
   100.5
   Option A
   10, 6, 12, 35, ?, 591.75
   10*0.5+1 = 6
   6*1.5+3=12
   12*2.5+5=35
   35*3.5+7=129.5
   129.5*4.5+9=591.75

    

3. 390, 198, ?, 54, 30, 18
   80
   120
   100
   98
   102
   Option E
   390, 198, ?, 54, 30, 18
   390-192=198
   198-96=102
   102-48=54
   54-24=30
   30-12=18

    

4. 10, 77, 474, ?, 9556, 28683
   2300
   2050
   1590
   2385
   2045
   Option D
   10, 77, 474, ?, 9556, 28683
   10*7+7*1=77
   77*6+6*2=474
   474*5+5*3=2385
   2385*4+4*4=9556
   9556*3+3*5=28683

    

5. 150, 50, 131, 67, 116, ?, 105
   70
   80
   60
   40
   50
   Option B
   150, 50, 131, 67, 116, ?, 105
   150 – 10² = 50
   50 + 9² = 131
   131 – 8²= 67
   67 + 7² = 116
   116 – 6²= 80
   80 + 5²=105

    

6. A car covers a distance of 528 km. in a certain time at a speed of 66 km./hr. How much distance would a truck cover at an average speed which is 24 km hr. less than that of the speed of the car in time which is 7 hours more than that taken by the car ?
   400 km
   630 km
   350 km
   450 km
   300 km
   Option B
   Time taken by car = 528/66 = 8 hours
   Time =15 hours (given) Speed = 66 – 24 = 42 kmph
   Distance covered by truck = Speed × Time
   = 15 × 42 = 630 km

    

7. A water tank in the form of a cuboid has its base 20 m long, 7 m wide and 10 m deep. Initially, the tank is full but later when water is taken out of it, the level of water in the tank reduces by 2 m. Find the volume of the water left in the tank.
   1335 cu. cm
   1100 cu. cm
   1450 cu. cm
   1120 cu. cm
   1200 cu. cm
   Option D
   Given that,
   Volume of the tank = l × b × h = 20 × 7 × (10 – 2) = 1120 cm^3

    

8. Mixture of milk and water has been kept in two separate containers. Ratio of milk to water in one of the containers is 5 : 1 and that in the other container is 7 : 2. In that ratio the mixture of these two containes should be added together, so that the quantity of milk in the new mixture may become 80% ?
   6:7
   1:3
   2:3
   4:5
   8:9
   Option C
   
   Percentage of milk in first mixture = (5/6)*100 = (250/3)%
   Percentage of milk in second mixture = (7/9)*100 = (700/9)%
   Using Alligation method,
   (250/3)———–(700/9)
   ———–80
   (20/9)————–(10/3)
   Required ratio = 2:3

    

9. The population of a variety of tiny bush in an experimental field increased by 10% in the first year, increased by 8% in the second year but decreased by 10% in the third year. If the present number of bushes in the experimental field is 26730, then what was the number of variety of bushes in the beginning ?
   20000
   23500
   21200
   24500
   25000
   Option E
   Let the beginning of the year variety of bushes is x, then x × 1.1 × 1.08 × 0.9 = 26730
   => x = 26730/(1.1*1.08*0.9)
   = 25000

    

10. Ravi borrowed some money at the rate of 4 p.c.p.a. for the first three years, at the rate of 8 p.c.p.a. for the next two years and at the rate of 9 p.c.p.a. for the period beyond 5 years. If he pays a total simple interest of Rs 19,550 at the end of 7 years, how much money did he borrow ?
    Rs. 40000
    Rs. 42500
    Rs. 62320
    Rs. 22400
    Rs. 50500
    Option B
    If the amount borrowed be Rs. x,
    then (x*4*3)/100 + (x*8*2)/100 + (x*9*2)/100 = 19550
    => 12x + 16x + 18x = 1955000
    => 46x = 1955000
    => x = 1955000/46
    => Rs. 42500