Hello Aspirants

**State Bank of India (SBI)** is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on **1st, 7th & 8th of July 2018. **Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.

**Directions(1-5):** Find the relationship between x and y and choose a required option.

- I. x^2 – 87x -270 = 0

II. 7y^2 – 11y -18 = 0y>xx>yx=y or relation cannot be established.y>=xx>=yOption C

I. x^2 – 87x -270 = 0

x^2 -90x + 3x – 270 =0

=> x = 90,-3

II. 7y^2 – 11y -18 = 0

7y^2 -18y +7y -18=0

=> y = 18/7, -1

x=y or relation cannot be established. - I. 4x^2 + 23x + 15 = 0

II. 4y^2 – 11y + 6 = 0y>xy>=xx>yx>=yx=y or relation cannot be established.Option A

I. 4×2 + 23x + 15 = 0

4x^2 + 20x + 3x + 15 = 0

=> x = -5, -3/4

II. 4y2 – 11y + 6 = 0

4y^2 – 8y – 3y + 6 = 0

=> y= 3/4, 2

y>x - I. 55x^2 – 495x +1100 = 0

II. 5y^2 + 10y -120 = 0x=y or relation cannot be established.y>=xx>=yx>yy>xOption C

I. 55x^2 – 495x +1100 = 0

55x^2 – (220+275)x – 1100 = 0

=> x = 4,5

II. 5y^2 + 10y -120 = 0

5y^2 +30y – 20y – 120 = 0

=> y = -6,4

x>=y - I. x^2 – 87x -270 = 0

II. 7y^2 – 11y -18 = 0x>=yy>xx=y or relation cannot be established.x>yy>=xOption C

I. x^2 – 87x -270 = 0

x^2 -90x + 3x – 270 =0

=> x = 90,-3

II. 7y^2 – 11y -18 = 0

7y^2 -18y +7y -18=0

=> y = 18/7, -1

x=y or relation cannot be established. - I. 9x^2 – 94.5x + 243 = 0

II. 4.5 y^2 – 13.5y – 486=0y>xy>=xx>yx=y or relation cannot be established.x>=yOption D

I. 9x^2 -94.5x + 243 = 0

9x^2 – (54+40.5)x + 243 =0

=> x = 6,4.5

II. 4.5 y^2 – 13.5y -486=0

4.5y^2 – 54y + 40.5y – 486=0

=> y = 12, -9

x=y or relation cannot be established. - What is the percentage rise in the population of City C from 2010 to 2012?
41.2%30.5%25.12%33.33%50.12%Option D

Required %

= [(6.4-4.8)/4.8]*100 = 33.33% - The literate population of City E in the year 2012 is approximately what percentage more than its literate population in 2010?
15.5%22.5%40.2%37.3%20.5%Option D

City E (2010) = 5.5*(67.7/100) = 3.7235 lakh

City E(2012) = 7.2*(71/100) = 5.112 lakh

Required % = [(5.112 – 3.7235)/3.7235]*100 = 37.3% - What is the difference between the Literate population and illiterate population of City D in the year 2010? (in lakh)
1.500 lakh1.250 lakh2.115 lakh1.508 lakh5.002 lakhOption D

Total population = 5.2 lakh

Percentage of literate population = 64.5%

Percentage of illiterates = 100-64.5 = 35.5%

Difference = 64.5 – 35.5 = 29%

Required answer = 5.2*(29/100) = 1.508 lakh - What is the difference between the total illiterate population of City G and City F in the year 2010? (in lakh)
0.1700 lakh0.1437 lakh0.4300 lakh0.7500 lakh0.1220 lakhOption B

Required difference

= 7.5*(100-68.9)/100 – 6.4*(100-65.8)/100 = 0.1437 lakh - What is the total literate population of City A in the year 2010 and 2012 together (in lakh)?
5.445 lakh3.450 lakh5.000 lakh6.444 lakh5.005 lakhOption A

Literate population of City A in 2010

= 3.6*(57.8/100) = 2.0808 lakh

Literate population of City A in 2012 = 5.4*(62.3/100)

= 3.3642 lakh

Total = 2.0808 + 3.3642 = 5.445 lakh

**Directions(6-10):** Following line-graph shows the population of seven cities (in lakh) and the table shows the percentage of literate population in these cities.