 # Quant Test for SBI PO 2018 Prelim Exam Set – 16

Hello Aspirants

State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on 1st, 7th & 8th of July 2018. Details of the exam are as under: Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.

Directions(1-5): Find the next term of the series.

1. 4, ?, 14, 40, 88, 170
10
6
12
4
9
Option B
4, ?, 14, 40, 88, 170
4 + 1² + 1= 6
6 + 3² – 1= 14
14 + 5² + 1= 40

2. 888, 444, 222, 111, 55.5, ?
20.21
30.15
25.5
33.33
27.75
Option E
888, 444, 222, 111, 55.5, ?
888/2=444
444/2=222
222/2=111
111/2=55.5
55.5/2=27.75

3. 5, 13, 58, 357, 2868, ?
20504
28695
25500
18600
28000
Option B
5, 13, 58, 357, 2868, ?
5*2+3=13
13*4+6=58
58*6+9=357
357*8+12=2868
2868*10+15=28695

4. 0, 6, 24, 60, ? , 210
80
100
95
120
75
Option D
0, 6, 24, 60, ? , 210
1^3 – 1 =0
2^3 – 2=6
3^3 – 3=24
4^3 – 4=60
5^3 – 5=120
6^3 – 6 = 210

5. 2, 2, 7, ?, 87, 342
24
20
30
22
15
Option D
2, 2, 7, ?, 87, 342
2 + 1² – 1 = 2
2 + 2² + 1= 7
7 + 4² – 1= 22

6. 8 men and 4 women together can complete a piece of work in 6 days. Work done by a man in one day is double the work done by a woman in one day. If 8 men and 4 women started working and after 2 days, 4 men left and 4 new women joined, in how many more days will the work be completed ?
4 days
8 days
6 days
5 days
7 days
Option D
According to the question, 1 man = 2 women
8 men + 4 women = (16 + 4) women = 20 women
4 men + 8 women = 16 women
20 women’s 2 days’ work =2/6 = 1/3 part
Remaining work = 1 – (1/3) = (2/3)
=>20 women complete 1 work in 6 days.
=>16 women will do (2/3) work in (20*6)/10 *(2/3)
= 5 days

7. Ninad, Vikas and Manav enter into a partnership. Ninad invests some amount at the beginning. Vikas invests doublé the amount after 6 months and Manav invests thrice the amount invested by Ninad after 8 months. They eam a proflt of Rs. 45,000 at the end of the year. What is Manav’s share in the profit ?
Rs. 14000
Rs. 10000
Rs. 12000
Rs. 18000
Rs. 15000
Option E
Vikas’s investment = Rs.2x
Manav’s investment = Rs. 3x
Ratio of the equivalent capital of Ninad, Vikas and Manav respectively
= x ×12 : 2x × 6 : 4 × 3x = 1 : 1 : 1
Clearly, the proflt will be shared equally Manav’s share
= Rs. (1/3)*45000
=Rs. 15000

8. A contractor employed 25 labourers on a job. He was paid 275 for the work. After retaining 20% of this sum, he distributed the remaining amount amongst the labourers. If the number of men to women labourers was in the ratio 2 : 3 and their wages in the ratio 5 : 4, what wages did a woman labourer get ?
Rs.6
Rs. 8
Rs.10
Rs.2
Rs.5
Option B
According to the question,
Number of men = (2/5) × 25 = 10
Number of women = (3/5) × 25 = 15
Amount distributed among men and women = 275 × 80% = Rs 220
Let the wages paid to a man by 5x and to a woman be 4x,
then 10 × 5x + 15 × 4x = 220
=> 50x + 60x = 220
=> x = 2
Hence,Wages received by a woman = 2 × 4 = Rs 8

9. Vishwas borrowed a total amount of Rs. 30,000 part of it on simple interest, rate of 12 p.c.p.a. and remaining on simple interest rate of 10 p.c.p.a. If at the end of 2 years he paid in all Rs. 36,480 to settle the loan amount, what was the amount borrowed at 12 p.c.p.a.?
17850
11500
15400
12000
12250
Option D
Let the sum borrowed at the rate of 12 p.c.p.a. be Rs. x.
Sum borrowed at 10 p.c.p.a. = Rs. (30000 – x)
Simple interest = Rs. (36480 – 30000) = Rs. 6480
According to the question,
(x*2*12)/100 + (30000-x)*2*10/100 = 6480
=> 24x + 600000 – 20x = 648000
=> 4x = 648000 – 600000
=> 4x = 48000
=> x = 48000/4 = 12000

10. There are 8 red balls and 6 yellow balls in a bag. Two balls are simultaneously drawn at random. What is the probability that both the balls are of the same colour?
43/91
52/91
20/91
33/91
40/91
Option A
Total number of balls = 8+6 =14
n(S) = 14C2 = 91
Two balls are of same colour = 8C2 = 28
n(E) = 6C2 = 15
Required probability = (28+15)/91 = 43/91