Hello Aspirants

**State Bank of India (SBI)** is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on **1st, 7th & 8th of July 2018. **Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.

**Directions(1-5):** Find the next term of the series.

- 4, ?, 14, 40, 88, 170
1061249Option B

4, ?, 14, 40, 88, 170

4 + 1² + 1= 6

6 + 3² – 1= 14

14 + 5² + 1= 40 - 888, 444, 222, 111, 55.5, ?
20.2130.1525.533.3327.75Option E

888, 444, 222, 111, 55.5, ?

888/2=444

444/2=222

222/2=111

111/2=55.5

55.5/2=27.75 - 5, 13, 58, 357, 2868, ?
2050428695255001860028000Option B

5, 13, 58, 357, 2868, ?

5*2+3=13

13*4+6=58

58*6+9=357

357*8+12=2868

2868*10+15=28695 - 0, 6, 24, 60, ? , 210
801009512075Option D

0, 6, 24, 60, ? , 210

1^3 – 1 =0

2^3 – 2=6

3^3 – 3=24

4^3 – 4=60

5^3 – 5=120

6^3 – 6 = 210 - 2, 2, 7, ?, 87, 342
2420302215Option D

2, 2, 7, ?, 87, 342

2 + 1² – 1 = 2

2 + 2² + 1= 7

7 + 4² – 1= 22 - 8 men and 4 women together can complete a piece of work in 6 days. Work done by a man in one day is double the work done by a woman in one day. If 8 men and 4 women started working and after 2 days, 4 men left and 4 new women joined, in how many more days will the work be completed ?
4 days8 days6 days5 days7 daysOption D

According to the question, 1 man = 2 women

8 men + 4 women = (16 + 4) women = 20 women

4 men + 8 women = 16 women

20 women’s 2 days’ work =2/6 = 1/3 part

Remaining work = 1 – (1/3) = (2/3)

=>20 women complete 1 work in 6 days.

=>16 women will do (2/3) work in (20*6)/10 *(2/3)

= 5 days - Ninad, Vikas and Manav enter into a partnership. Ninad invests some amount at the beginning. Vikas invests doublé the amount after 6 months and Manav invests thrice the amount invested by Ninad after 8 months. They eam a proflt of Rs. 45,000 at the end of the year. What is Manav’s share in the profit ?
Rs. 14000Rs. 10000Rs. 12000Rs. 18000Rs. 15000Option E

Let Ninad invest Rs.x

Vikas’s investment = Rs.2x

Manav’s investment = Rs. 3x

Ratio of the equivalent capital of Ninad, Vikas and Manav respectively

= x ×12 : 2x × 6 : 4 × 3x = 1 : 1 : 1

Clearly, the proflt will be shared equally Manav’s share

= Rs. (1/3)*45000

=Rs. 15000 - A contractor employed 25 labourers on a job. He was paid 275 for the work. After retaining 20% of this sum, he distributed the remaining amount amongst the labourers. If the number of men to women labourers was in the ratio 2 : 3 and their wages in the ratio 5 : 4, what wages did a woman labourer get ?
Rs.6Rs. 8Rs.10Rs.2Rs.5Option B

According to the question,

Number of men = (2/5) × 25 = 10

Number of women = (3/5) × 25 = 15

Amount distributed among men and women = 275 × 80% = Rs 220

Let the wages paid to a man by 5x and to a woman be 4x,

then 10 × 5x + 15 × 4x = 220

=> 50x + 60x = 220

=> x = 2

Hence,Wages received by a woman = 2 × 4 = Rs 8 - Vishwas borrowed a total amount of Rs. 30,000 part of it on simple interest, rate of 12 p.c.p.a. and remaining on simple interest rate of 10 p.c.p.a. If at the end of 2 years he paid in all Rs. 36,480 to settle the loan amount, what was the amount borrowed at 12 p.c.p.a.?
1785011500154001200012250Option D

Let the sum borrowed at the rate of 12 p.c.p.a. be Rs. x.

Sum borrowed at 10 p.c.p.a. = Rs. (30000 – x)

Simple interest = Rs. (36480 – 30000) = Rs. 6480

According to the question,

(x*2*12)/100 + (30000-x)*2*10/100 = 6480

=> 24x + 600000 – 20x = 648000

=> 4x = 648000 – 600000

=> 4x = 48000

=> x = 48000/4 = 12000 - There are 8 red balls and 6 yellow balls in a bag. Two balls are simultaneously drawn at random. What is the probability that both the balls are of the same colour?
43/9152/9120/9133/9140/91Option A

Total number of balls = 8+6 =14

n(S) = 14C2 = 91

Two balls are of same colour = 8C2 = 28

n(E) = 6C2 = 15

Required probability = (28+15)/91 = 43/91