Hello Aspirants

**State Bank of India (SBI)** is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled onÂ **1st, 7th & 8th of July 2018. **Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.Â

**Directions(1-5):** Find the relation between x and y and choose a correct option accordingly.

- I. (17)^2 + 144 /18 = x

II. (26)^2 – 18*21 = yx>=yx>yy>=xy>xx=y or relation cannot be established.Option D

I. (17)^{2}+ 144 /18 = x

=> x = 297

II. (26)^{2}– 18*21 = y

=>y = 298

y>x - I. 16x
^{2}-106x +13=0

II. 8y^{2}+ 47y â€“ 6 = 0y>xy>=xx=y or relation cannot be established.x>yx>=yOption E

I. 16x^{2}-106x +13=0

16x^{2}â€“ 104x â€“ 2x + 13 =0

=> (2x – 13)(8x – 1)=0

=> x= 13/2 , 1/8

II. 8y^{2}+ 47y â€“ 6 = 0

8y^{2}+ 48y -1y â€“ 6 =0

=> (y+6)(8y – 1) = 0

=> y = -6, 1/8

x>=y - I. x
^{2}â€“ 529 = 0

II. y^{3}-19683 = 0x>yx=y or relation cannot be established.x>=yy>=xy>xOption E

I. x^{2}â€“ 529 = 0

=> x = +23, -23

II. y^{3}-19683 = 0

=> y = 27

y>x - I. 40x
^{2}-101x +12 =0

II. 40y^{2}â€“ 13y + 1 =0x>=yy>=xy>xx>yx=y or relation cannot be established.Option A

I. 40x^{2}-101x +12 =0

40x^{2}â€“ 96x â€“ 5x + 12 =0

=> (5x – 12)(8x – 1) = 0

=> x = 12/5, 1/8

II. 40y^{2}â€“ 13y + 1 =0

40y^{2}– 8y â€“ 5y + 1 =0

=> (8y – 1)(5y – 1) = 0

=> y = 1/8, 1/5

x>=y - I. 55x
^{2}â€“ 495x + 1100 =0

II. 5y^{2}+ 10y – 120 = 0y>=xy>xx>=yx=y or relation cannot be established.x>yOption C

I. 55x^{2}â€“ 495x + 1100 =0

55x^{2}â€“ 220x â€“ 275x + 1100 =0

=> x = 4,5

II. 5y^{2}+ 10y – 120 = 0

5y^{2}+ 30y â€“ 20y â€“ 120 =0

=> y = -6,4

x>=y - The number of appeared candidates from State B increased by 100% from 2010 to 2011. If the total number of qualified candidates from State B in 2010 and 2011 together is 408, what is the number of appeared candidates from State B in 2010?
300280340330310Option C

Let the number of appeared candidates form State B in 2010 be x.

Then number of appeared candidates in 2012 = x + (x*100)/100 = 2x

Now, (x*30)/100 + (2x*45)/100 = 408

=>12x = 408*10

=> x= 340 - If the ratio of the number of qualified candidates from State A in 2013 to that in 2014 is 14:9, what is the number of qualified candidates from State A in 2014?
150200188216110Option D

In 2013, number of qualified candidates

= (480*70)/100 = 336

Let the number of qualified candidates from State A in 2013 be 14x and that in 2014 be 9x.

Then,

14x = 336

=> x = 24

So, the number of qualified candidates from State A in 2014

= 9*24 = 216 - What is the difference between the number of qualified candidates from State A in 2010 and that in 2011?
121081520Option A

Required difference

= (450*60)/100 â€“ (600*43)/100

=270-258 = 12 - If the average number of qualified candidates from State B in 2012, 2013 and 2014 is 210, what is the number of qualified candidates from State B in 2014?
125187170154136Option B

Let the percentage of candidates who qualify from State B in 2014 be x%.

Average

=> [(280*60)/100 + (550*50)/100 + 400*x%]/3= 210

=> x = 46.75%

Number of qualified candidates from State B in 2014 = (400*46.75)/100

= 187 - Out of the number of qualified candidates from State A in 2012, the ratio of male to female candidates is 11:7. If the number of female qualified candidates from State A in 2012 is 126, what is the number of appeared candidates (both male and female) from State A in 2012?
400480380520540Option E

Let the number of male and female qualified candidates be 11x and 7x respectively.

Then, 7x = 126

=> x = 18

Males = 18*11 = 198

Total number of qualified candidates = 198+126 = 324

Let the number of appeared candidates be y.

Then , y * 60% = 324

=> y = (324*100)/60 = 540

**Directions(6-10):** Study the following table carefully and answer the questions that follow.

Few values are missing in the table. A candidate is expected to calculate the missing value, if it is required to answer the given questions on the basis of the given information.

I believe that avoiding refined foods may be the first step so that you can lose weight. They might taste beneficial, but highly processed foods possess very little nutritional value, making you take in more simply to have enough vigor to get with the day. Should you be constantly ingesting these foods, moving over to whole grain products and other complex carbohydrates will help you have more power while eating less. Thanks alot : ) for your blog post.

It’s appropriate time to make some plans for the long run and it is

time to be happy. I have read this publish and if I may I wish to recommend you some interesting issues or suggestions.

Perhaps you can write subsequent articles regarding this article.

I want to read even more things approximately it!

If you desire to obtain a great deal from this piece of writing

then you have to apply such methods to your won webpage.

Hey! I could have sworn I’ve been to this blog before but after reading through some of the post I realized it’s new to me.

Anyways, I’m definitely delighted I found it and I’ll be bookmarking and checking back frequently!