Boats and Streams Bank PO Questions

- Vimal can row a certain distance downstream in 14 hoursand return the same distance in 21 hours. If the speed of the stream is 6 kmph, Find the speed of Vimal in the still water?

A) 21 kmph

B) 15 kmph

C) 30 kmph

D) 35 kmph

E) None of these

View Answer

** Option C**

Solution:

Speed of Vimal in still water = x

Downstream Speed = (x + 6)

Upstream Speed = (x – 6)

Downstream Distance = Upstream Distance

14(x + 6) = 21(x – 6)

2x + 12 = 3x – 18

x = 30 kmph.

- Rahul can row a certain distance downstream in 12 hour and return the same distance in 18 hour. If the speed of Rahul in still water is 12 kmph, find the speed of the stream?

A) 2.1 kmph

B) 1.5 kmph

C) 4.4 kmph

D) 2.4 kmph

E) None of these

View Answer

** Option D**

Solution:

Let the speed of the stream be x kmph

Down stream = (12+x)

Up stream = (12−x)

suppose the distance traveled be y

y/(12+x) = 12 —(1)

y/(12−x)= 18 —-(2)

From eqn (1) and (2)

x= 2.4 kmph

- Anil can row 18 kmph in still water and he finds that it takes him twice as long to row up as to row down the river. Find the rate of stream?

A) 5 kmph

B) 6 kmph

C) 4 kmph

D) 3 kmph

E) None of these

View Answer

** Option B**

Solution:

Stream Speed = a kmph

Time Taken = x km

Downstream speed = (18 + a) kmph

Upstream speed = (18 – a) kmph

Time taken to travel downstream = 2 * Time taken to travel upstream

(18 + a) / x = 2(18 + a) / x

18 + a = 36 – 2a

3a = 18

a = 6 kmph

OR USE FORMULA

Speed of boat = [t_{u}+t_{d}]/[t_{u}-t_{d}] * Speed of stream

So 18 = [2x + x]/[2x – x] * Speed of stream

- Mr. Suresh can row to a place 48 km away and come back in 14 hours. He finds that he can row 4 km with the stream in the same time as 3 km against the stream. The rate of the stream is?

A) 1 kmph

B) 3 kmph

C) 4 kmph

D) 6 kmph

E) None of these

View Answer

** Option A**

Solution:

Downstream speed = 4/x kmph

upstream speed = 3/x kmph

48/(4/x) + 48/(3/x) = 14

Solving we get x = 1/2 kmph

So, Speed of downstream = 8 kmph, Speed of upstream = 6 kmph

Stream Speed = 1/2(8 – 6) kmph = 1 kmph

- Mr.Ramesh’s speed with the current is 20 kmph and the speed of the current is 5 kmph. Ramesh’s speed against the current is?

A) 15 kmph

B) 19 kmph

C) 17 kmph

D) 10 kmph

E) None of these

View Answer

** Option D**

Solution:

Ramesh’s speed with the current = 20 kmph

=> Ramesh’s speed + speed of the current = 20 kmph

Speed of the current = 5 kmph

Speed of Ramesh = 20 – 5 = 15 kmph

Ramesh’s speed against the current = speed of Ramesh – speed of the current = 15 – 5 = 10 kmph

- Ravi can row 12 kmph in still water when the river is running at 6 kmph it takes him 1 hour to row to a place and to come back. How far is the place?

A) 5.5 km

B) 4.5 km

C) 8.2 km

D) 4.2 km

E) None of these

View Answer

** Option B**

Solution:

Downstream Speed = 18 kmph

Upstream Speed = 6 kmph

Distance = x

x/18 + x/6 = 1

18x + 6x = 108

24x = 108

x = 4.5 km

OR USE FORMULA:

Distance = time [B^{2} – R^{2}]/2*B

So distance = 1 * [12^{2} – 6^{2}]/2*12

Distance = 108/24 = 4.5 km

- The different between downstream speed and upstream speed is 2 kmph and the total time taken during upstream and downstream is 2 hours. What is the upstream speed, if the downstream and upstream distance are 2 km each?

A) 5.2 kmph

B) 3.7 kmph

C) 2.8 kmph

D) 1.4 kmph

E) None of these

View Answer

** Option D**

Solution:

2/x + 2/(x+2) = 2.

x^{2} – 2 = 0

x = 1.414kmph

- Rani can row 8 kmph in still water. If the river is running at 4 kmph it takes 90 minutes to row to a place and back. How far is the place?

A) 4.5 km

B) 8.2 km

C) 4.2 km

D) 3.5 km

E) None of these

View Answer

** Option A**

Solution:

Speed in still water = 8 kmph

Speed of the stream = 4 kmph

Upstream Speed = (8-4) = 4 kmph

Downstream Speed = (8+4) = 12 kmph

Total time = 90 minutes = 90/60 = 3/2 hrs

Let x is the distance

x/12 + x/4 = 3/2

x = 4.5 km

- Sumi can swim 6 kmph in still water. If the velocity of the stream be 2 kmph, the time taken by her to swim to a place 24 km upstream and back, is?

A) 6 hours

B) 5 hours

C) 4 hours

D) 8 hours

E) 9 hours

View Answer

** Option E**

Solution:

Upstream speed = speed of man – speed of stream=6 – 2 = 4

Downstream speed = speed of man + speed of stream=6 + 2=8

Time taken to go upstream = distance/speed = 24/4 =6 hour

Time taken to go downstream = distance/speed =24/8 = 3 hour

Total time =6+3 = 9 hour

- Raghu can row 96 km downstream in 8 hours. If the speed of the current is 3 kmph, then find in what time will be able to cover 12 km upstream?

A) 6 hours

B) 5 hours

C) 4 hours

D) 8 hours

E) 2 hours

View Answer

** Option E**

Solution:

Downstream speed = 96/8 = 12 kmph

Speed of current = 3 kmph

Speed of kamal in still water = 12-3 = 9 kmph

Upstream speed = 9-3 = 6 kmph

Time taken to cover 12 km upstream 12/6 = 2 hours

#### Click here to go to Quantitative Aptitude Section

starting hi galat ans. se 🙁 mod ans is 48

Ohh. Yes

Take the second time as 21 hrs

plz upload some more questions

Where can we get DI based on Boats and streams and on other chapters as well?

check sets 34 to 43

http://aspirantszone.com/data-interpretation/

mam plz help me to clarify the 2nd question answer. i used to solve 2nd question same like 1st one but urs approaching was diff…y?

where is the approach different ?

Both are solved using downstream and upstream speeds

May be I am not getting your query

mam in 1st: 14(x + 6) = 21(x – 6) this approach..

2nd: 12(12+x) = 18(12-x)

i was used same approach for 2nd one..(i think in 2nd question suresh nd rahul two persons..).

ok ok

yes same approach can be followed

but i got wrong answer. mam

thanx upload more on boats and streams high level

1 & 2 No. Kaise kiya apne?

using suresh nd rahul’s speeds..

Mam in 10th question…

Current Ka speed diya he matlab”y” Ka speed 3 diya he and upstream means x-y =12 diya he ,so isse agar X ki value nikal no ho to equation

X-y=12

X-3=12

X=15 hoga…. Yaha iss equation se 12-3=9 kaise hua plz explain

And correct me where I’m wrong!

maam 7 ques me x and x-2 hoga shayd

thanku az ::)

again 😛

again 😛

thanks

okkk