Quantitative Aptitude: Data Interpretation Questions Set 115

Directions(1-5): Study the following table and answer the questions that follow.

  1. What is the average invalid votes for village A for the given years(approximate)?
    800
    600
    300
    200
    400
    Option E
    Required average = [250+550+400]/3 = 400

     

  2. If total vote polled in village B in year 2000 ,25% polled by females and total valid-female-votes are 1875 then find the number of valid votes polled by males ?
    5110
    5005
    5151
    5725
    5500
    Option D
    Votes polled by females = 25 100 × 8000 = 2000
    Votes polled by males = 6000
    Valid female votes = 1875 Valid male votes = 7600 − 1875
    = 5725

     

  3. Total votes of village A in 2000 is what percent of valid votes polled in village C in 2010?
    33%
    44%
    37%
    30%
    41%
    Option C
    Required percentage = 2500/6750 × 100 == 37%

     

  4. What is the average of valid votes polled in year 2000?
    4554
    4141
    3850
    4000
    4700
    Option E
    Required average = [2250+7600+4250]/3 = 4700

     

  5. Valid votes polled in village C in 2005 is by what percent less than total votes polled in village B in 2000?
    30.9%
    42.5%
    2.82%
    33.3%
    40.1%
    Option B
    Required percentage = [8000−4600]/8000 × 100
    ≈ 42.5%

     

  6. Directions(6-10): Study the following table and answer the questions that follow.
    Given line graph shows the number of students appeared from state A and state B in an examination.

  7. Number of students appeared from state B in 2009 is about what percent of total students appeared from state A?
    23%
    22%
    29%
    25%
    20%
    Option C
    Required percent = 760/2640 × 100
    = 28.78% == 29%

     

  8. What is the difference between the total number of students from state A in 2004 and 2005 together and those of state B in 2008 and 2009 together?
    610
    630
    620
    660
    640
    Option C
    Total students from state A in 2004 and 2005
    = 260 + 320 = 580
    Total students from state B in 2008 and 2009 = 440 + 760 = 1200
    Difference = 1200 − 580 = 620

     

  9. What is the difference between average number of students from state A and state B?
    90
    80
    60
    50
    40
    Option B
    Difference = 3120/6 – 2640/6
    = 520 −440 = 80

     

  10. If in 2010 the number of students appeared from state A is increase by 10%and those from state B increased by 15% as compared to the number of students from respective states in year 2009,then what is the ratio of number of students from state A and state B in 2010?
    293/435
    211/400
    222/433
    242/437
    241/413
    Option D
    Required ratio = [110×440/100]/[115×760/100] = 484/874 = 242/437

     

  11. What is the ratio of number of students appeared in examination from state B in 2004 ,2006 and 2008 to the number of students appeared from state A in 2005,2007 and 2009?
    50/73
    53/68
    51/70
    55/71
    52/73
    Option D
    Required Ratio = [340+320+440]/[320+660+440] = 1100/1420 = 55/71

     


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