Quantitative Aptitude: Data Interpretation Questions Set 121

Directions(1-5): Refer to the table given below and answer the given questions. Data related to the number of students in 5 different collages in the year of 2016. Note: In each college, there are only three branches viz Art, Commerce and Science.

  1. Total number of students in college Christ Church increased by 20% from 2016 to 2017. If 20% of the total number of students in college Christ Church in 2017 was science and commerce graduate, then what was the total number of science and commerce graduate students in college Christ Church in 2017?
    220
    250
    270
    240
    200
    Option D
    Required students = 20/100 × 1000 × 120/100 = 240

     

  2. What is the ratio of Science and commerce graduates together from college Christ Church to the arts graduates from college D.V.S.?
    81 ∶ 20
    85 ∶ 21
    87 ∶ 27
    85 ∶ 22
    81 ∶ 23
    Option B
    Required ratio = 68×1000:28×600 = 85 ∶ 21

     

  3. If the respective ratio between the number of science graduate and commerce graduate students in college Christ Church was 2 : 3. What was the number of commerce graduate students in Christ Church?
    420
    400
    408
    410
    415
    Option C
    Commerce graduate college in Christ Church = 3/5 × 68/100 × 1000 = 6 × 68 = 408

     

  4. The average number of Arts and commerce graduates in collage P.P.N.is 300 then find the number of Arts graduates in college P.P.N.?
    988
    800
    cannot be determined
    1000
    785
    Option
    Total number of Arts and commerce graduates in college P.P.N. = 600 Since percentage distribution is not given.
    Therefore, Arts graduates in collage P.P.N. cannot be determined.

     

  5. What is the difference between the number of commerce graduate students and Arts graduate students in collage D.V.S.?
    16
    18
    14
    12
    10
    Option D
    Percentage of Arts graduate = 28%
    Required difference = (30 − 28) /100 × 600 = 2/100 × 600 = 12

     

  6. Directions(6-10): The following bar graph shows the percentage of voters of different age group from five different cities of India who casted their votes in Parliament election in 2014. The total no. of voters is also mentioned with each city. Study the bar graph carefully to answer the questions that follow.

  7. If 20% votes from each city were declared invalid, then find the total no. of valid votes casted by the voters in Parliament election.
    3,15,000
    2,00,000
    1,15,000
    2,08,000
    1,00,000
    Option D
    Required answer = 80/100 × (50,000 + 75,000 + 35,000 + 40,000 + 60,000)
    = 2,08,000

     

  8. Find the total no. of voters of age group above 40 years who casted their votes from all the cities together.
    80,000
    92,600
    91,500
    88,600
    90,000
    Option B
    Required answer = (40 × 500 + 28 × 750 + 56 × 350 + 50 × 400 + 20 × 600) = 92,600

     

  9. Total no. of voters of age group (20-25) years from Bihar and Delhi together is what percent more or less than the total no. of voters of age group (20-25) years from UP and Rajasthan together who catsed their votes in the election (approximately)?
    48%
    50%
    56%
    44%
    40%
    Option D
    Total no. of voters from Bihar and Delhi of age group (20–25) years
    = 24/100 × 50,000 + 20/100 × 35000 = 19,000
    Total no. of voters from UP and Rajasthan of age group (20–25) years
    = 30/100 × 75,000 + 28/100 × 40,000 = 33,700
    Required percentage = [33,700 − 19,000]/33,700 × 100 ≃ 44%

     

  10. What is the ratio of no. of voters of age group (30–40) years who casted their votes from UP and Rajasthan together to the total no. of voters of same age group from Delhi and Maharashtra together who casted their votes in the election?
    403:240
    400:247
    413:243
    410:221
    400:241
    Option A
    Required ratio = [42 × 750 + 22 × 400]/[ 24 × 350 + 26 × 600] = 40,300:24,000 = 403:240

     

  11. Find the average no. voters of age groups (30-40) years from all cities together.
    17,000
    15,500
    17,650
    16,460
    19,000
    Option D
    Required average = 1/5 × (36 × 500 + 42 × 750 + 24 × 350 + 22 × 400 + 26 × 600)
    = 1/5 × 82,300 = 16,460

     


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