# Quantitative Aptitude: Data Interpretation Questions Set 141

Directions (1-5): The given bar graph shows the rate of interest per year by 4 various chit companies for deposits under three different plan (A, B and C). 1. Raj invested an amount in plan A of finance S for two years and he also invests the same amount in plan C of finance T for two years. If the total amount of simple interest accrued from the two plans is Rs.880, then what is the principal amount?
1000
1500
2000
2500
3000
Option C
x * 12 * 2/100 + x * 10 * 2/100 = 880
24x + 20x = 88000
x = Rs. 2000

2. The finance U offers compound interest under plan B and finance V offer simple interest under plan B. What is the difference between the interests earned under these plans in two years, if the principal amount is Rs.8400?
543
445
924
876
456
Option C
SI = 5 * 8400 * 2/100
SI = Rs. 840
CI = 8400 * (1 + 10/100)2 – 8400
CI = Rs. 1764
Required Difference = 1764 – 840 = Rs. 924

3. Sam invested his amount Rs.4500 for eight years with finance T under plan B which is offering simple interest and Prem invested Rs.6000 for three years with finance V under plan C which is offering compound interest. What is the difference between the interest earned by Sam and Prem?
2112
2008
2432
2002
2080
Option A
Interest amount earned by Sam = 4500 * 18 * 8/100 = Rs. 6480
Interest amount earned by Prem = 6000 * (1 + 20/100)3 – 6000
= Rs. 4368
Required Difference = 6480 – 4368 = Rs. 2112

4. Krupa invested Rs.3000 in finance S under plan C which is offering simple interest for 5 years and Rs.2000 in finance V under plan A which is also offering simple interest for 4 years, What is the total interest earned by Krupa?
3000
3210
3120
3222
3111
Option B
Total interest = 3000 * 15 * 5/100 + 2000 * 12 * 4/100
= 2250 + 960
= Rs. 3210

5. The finance T offers compound interest under plan C and finance U offer simple interest under plan B. What is the difference between the interests earned under these plans in three years, if the principal amount is Rs.4800?
123
134.4
148.8
112.7
126.9
Option C
Difference = P * r * r/100 * 100 * 100 * (300 + r)
= 4800 * 10 * 10/100 * 100 * 100 * (300 + 10)
= 48 * 310/100
= Rs. 148.8

6. Directions (6-10): The bar graph shows the no. of Red, Blue and Pink color cars in a garage A, B, C, D and E Line graph shows the probability of a green color car taken from each garage. 7. If 25% of red car taken from garage A and added to garage E, then find the probability of taken two car both are pink colour in garage E
105/1378
10/1378
105/137
105/378
16/1378
Option A
Garage A:
Let us take the no. of green colour car be x
Probability = xc1/(32+x)c1
9/25 = x/(32+x)
32*9 +9x = 25x
16x = 32*9=> x= 18 green colour car
Garage B:
Let us take the no. of green colour car be x
Probability = xc1/(34+x)c1
3/20 = x/(34+x)
3*34+ 3x = 20x
=>3*34= 17x
X= 6 green colour car
Garage C:
Let us take the no. of green colour car be x
Probability = xc1/(40+x)c1
1/5 = x/(40+x)
=>40+x= 5x
=>4x=40 =>x= 10 green colour car
Garage D:
Let us take the no. of green colour car be x
Probability = xc1/(26+x)c1
2/15 = x/(26+x)
52+2x= 15x
=>13x= 52
=> x= 4 green colour car
Garage E:
Let us take the no. of green colour car be x
Probability = xc1/(40+x)c1
1/5 = x/(40+x)
=>40+x= 5x
=>4x=40 =>x= 10 green colour car

Total number of balls in garage E = [(12*25/100)+15] +10+15+10
= 18+10+15+10
= 53
Required probability = 15c2/53c2 = (15*14)/(53*52)
= 105/1378

8. If the total no of red colour car and pink colour car from all the garages (A, B, C, D and E) are taken out and filled in a new garage P, then 2 car taken out from garage P find the probability of different colours
3869/78
386/7875
3869/7875
369/7875
318/7875
Option C
Total number of red colour cars in garage P = (12+8+10+8+15) = 53
Total number of pink colour cars in garage P = (12+16+18+12+15) = 73
Required probability = (53*73)/(53+73)c2
= 53*73/(126*125/1*2) = 3869/7875

9. Four car taken from garage C, then find the probability of different colour
216/2303
216/230
516/2303
216/303
200/2303
Option A
Required probability = (10*12*18*10)/50c4
= (10*12*18*10)/(50*49*48*47/1*2*3*4)
= (24*9)/(49*47)
= 216/2303

10. Total number of balls in garage B and D together is approximately what percentage of the total number of balls in garage C and E together?
40%
70%
60%
75%
80%
Option B
Required percentage
= [(8+10+16+6+8+6+12+4)/(10+12+18+10+15+10+15+10)]*100
= 70/100 * 100 = 70%

11. Two cars took randomly from garage B. What is the probability of at least one pink colour car?
42/65
42/63
42/61
42/67
39/65
Option A
Required probability = 1- 24c2/40c2
= 1 – (24*23/40*39)
= 1- 23/65
= 42/65