**Directions (1-5): The given bar graph shows the rate of interest per year by 4 various chit companies for deposits under three different plan (A, B and C).**

- Raj invested an amount in plan A of finance S for two years and he also invests the same amount in plan C of finance T for two years. If the total amount of simple interest accrued from the two plans is Rs.880, then what is the principal amount?
10001500200025003000Option C

x * 12 * 2/100 + x * 10 * 2/100 = 880

24x + 20x = 88000

x = Rs. 2000 - The finance U offers compound interest under plan B and finance V offer simple interest under plan B. What is the difference between the interests earned under these plans in two years, if the principal amount is Rs.8400?
543445924876456Option C

SI = 5 * 8400 * 2/100

SI = Rs. 840

CI = 8400 * (1 + 10/100)2 – 8400

CI = Rs. 1764

Required Difference = 1764 – 840 = Rs. 924 - Sam invested his amount Rs.4500 for eight years with finance T under plan B which is offering simple interest and Prem invested Rs.6000 for three years with finance V under plan C which is offering compound interest. What is the difference between the interest earned by Sam and Prem?
21122008243220022080Option A

Interest amount earned by Sam = 4500 * 18 * 8/100 = Rs. 6480

Interest amount earned by Prem = 6000 * (1 + 20/100)3 – 6000

= Rs. 4368

Required Difference = 6480 – 4368 = Rs. 2112 - Krupa invested Rs.3000 in finance S under plan C which is offering simple interest for 5 years and Rs.2000 in finance V under plan A which is also offering simple interest for 4 years, What is the total interest earned by Krupa?
30003210312032223111Option B

Total interest = 3000 * 15 * 5/100 + 2000 * 12 * 4/100

= 2250 + 960

= Rs. 3210 - The finance T offers compound interest under plan C and finance U offer simple interest under plan B. What is the difference between the interests earned under these plans in three years, if the principal amount is Rs.4800?
123134.4148.8112.7126.9Option C

Difference = P * r * r/100 * 100 * 100 * (300 + r)

= 4800 * 10 * 10/100 * 100 * 100 * (300 + 10)

= 48 * 310/100

= Rs. 148.8

If 25% of red car taken from garage A and added to garage E, then find the probability of taken two car both are pink colour in garage E105/137810/1378105/137105/37816/1378Option A

Garage A:

Let us take the no. of green colour car be x

Probability = xc1/(32+x)c1

9/25 = x/(32+x)

32*9 +9x = 25x

16x = 32*9=> x= 18 green colour car

Garage B:

Let us take the no. of green colour car be x

Probability = xc1/(34+x)c1

3/20 = x/(34+x)

3*34+ 3x = 20x

=>3*34= 17x

X= 6 green colour car

Garage C:

Let us take the no. of green colour car be x

Probability = xc1/(40+x)c1

1/5 = x/(40+x)

=>40+x= 5x

=>4x=40 =>x= 10 green colour car

Garage D:

Let us take the no. of green colour car be x

Probability = xc1/(26+x)c1

2/15 = x/(26+x)

52+2x= 15x

=>13x= 52

=> x= 4 green colour car

Garage E:

Let us take the no. of green colour car be x

Probability = xc1/(40+x)c1

1/5 = x/(40+x)

=>40+x= 5x

=>4x=40 =>x= 10 green colour car1) Answer: c)

Total number of balls in garage E = [(12*25/100)+15] +10+15+10

= 18+10+15+10

= 53

Required probability = 15c2/53c2 = (15*14)/(53*52)

= 105/1378- If the total no of red colour car and pink colour car from all the garages (A, B, C, D and E) are taken out and filled in a new garage P, then 2 car taken out from garage P find the probability of different colours
3869/78386/78753869/7875369/7875318/7875Option C

Total number of red colour cars in garage P = (12+8+10+8+15) = 53

Total number of pink colour cars in garage P = (12+16+18+12+15) = 73

Required probability = (53*73)/(53+73)c2

= 53*73/(126*125/1*2) = 3869/7875 - Four car taken from garage C, then find the probability of different colour
216/2303216/230516/2303216/303200/2303Option A

Required probability = (10*12*18*10)/50c4

= (10*12*18*10)/(50*49*48*47/1*2*3*4)

= (24*9)/(49*47)

= 216/2303 - Total number of balls in garage B and D together is approximately what percentage of the total number of balls in garage C and E together?
40%70%60%75%80%Option B

Required percentage

= [(8+10+16+6+8+6+12+4)/(10+12+18+10+15+10+15+10)]*100

= 70/100 * 100 = 70% - Two cars took randomly from garage B. What is the probability of at least one pink colour car?
42/6542/6342/6142/6739/65Option A

Required probability = 1- 24c2/40c2

= 1 – (24*23/40*39)

= 1- 23/65

= 42/65

**Directions (6-10): The bar graph shows the no. of Red, Blue and Pink color cars in a garage A, B, C, D and E **

**Line graph shows the probability of a green color car taken from each garage.**