Quantitative Aptitude: Data Interpretation Questions Set 64

Time Speed Distance Questions for NICL, SBI PO, IBPS PO, NIACL, LIC, Dena Bank PO PGDBF, BOI, Bank of Baroda and other competitive exams
Directions (1-5): Read the table carefully and answer the following questions.

Number of books published by six companies and percentage of books distributed among distributors working with the company

What was the difference between the number of books received by each distributor working with company B and the number of books received by each distributor working with company F?
A) 324
B) 300
C) 264
D) 220
E) 315

View Answer
Option C
Solution:
Number of books received by each distributor:
Company B = (6400*90)/(100*10) = 576
Company F = (7200*70)/(100*6) = 840
Required difference = 840 – 576 = 264
Among the total number of books distributed by company D the respective ratio of academic and non-academic books was 5:4 . What was the number of non-academic books distributed by the company D?
A) 900
B) 1400
C) 1550
D) 1010
E) 1200

View Answer
Option B
Solution:
Number of books distributed by company D = (3500*90)/100 = 3150
Academic : Non-academic books = 5:4
Number of non-academic books = 3150*(4/9) = 1400
The number of books distributed by company B is what percent of the number of books distributed by company E?
A) 155%
B) 110%
C) 115%
D)129%
E) 130%

View Answer
Option D
Solution:
Number of books distributed by company B = (6400*90)/100 = 5760
company E = (5600*80)/100 = 4480
Required % = (5760 *100)/4480 = 129%(approx.)
What was the respective ratio between total number of books distributed Company B and the total number of books distributed by Company C?
A) 36:29
B) 25:46
C) 42:47
D) 33:25
E) 41:35

View Answer
Option A
Solution:
Required ratio = (6400*90)/100: (5800*80)/100 = 64*90 : 58*80 = 36 : 29
What is the average number of books published by companies A,C and D together?
A) 7800
B) 4500
C) 4600
D) 5460
E) 7520

View Answer
Option C
Solution:
(4500+5800+3500)/3 = 4600

Directions(6-10): In the following bar diagram the number of engineers employed in various companies has been given. Study the bar diagram carefully to answer the questions.
If the number of all the engineers in the company V, company X and companyY be increased by 30%, 35% and 40% respectively, what will be the overall percentage increase in the number of all engineers of all the companies taken together?
A)18%
B) 22%
C) 30%
D) 35%
E) 42%

View Answer
Option B
Solution:
Increase in the number of engineers:
Company V = (400*130)/100 = 520
Company X = (700*135)/100 = 945
Company Y = (950*140)/100 = 1330
Total engineers = 520 + 650+ 945 + 1330 + 750 = 4195
Total original number of engineers = 400 + 650 + 700 + 950 + 750 = 3450
% increase = [(4195 – 3450)/3450]*100 = 22%(approx.)
What is the average number of junior engineers employed in all the companies?
A) 150
B) 110
C) 170
D) 200
E) 190

View Answer
Option C
Solution:
The average number of junior engineers = 850/5 = 170
If the number of assistant engineers employed in all the companies be increased by 37% and the number of post graduate engineers employed in all the companies be decreased by 20% by what per cent will the number of assistant engineers be less than that of post graduate engineers?
A) 13.52%
B) 17.72%
C) 19.87%
D) 22.15%
E) 15.42%

View Answer
Option C
Solution:
Number of assistant engineers after 37% increase = (1050*137)/100 = 1438.5
Number of post graduate engineers after 20% decrease = (1500*80)/100 = 1200
Required % = [(1438.5 – 1200)/1200]*100 = 19.87%
What is the ratio between the number of assistant engineers employed in company V and company X ?
A) 5 : 6
B) 3 : 4
C) 5 : 7
D) 2 : 3
E) 1 : 2

View Answer
Option B
Solution:
Required ratio = 150:200 = 3 : 4
What is the difference between the average number of junior engineers and assistant engineers taking all the companies together?
A) 10
B) 50
C) 30
D) 20
E) 40

View Answer
Option B
Solution:
The average number of junior engineers = 850/5 = 170
The average number of assistant engineers = 1100/5 = 220
Difference = 50

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Mission RRB PO

September 14, 2017 at 3:27 pm

check question no 7 and 10th
total junior engg. == 850

Reply
1. Banya
  
  September 14, 2017 at 3:49 pm
  
  yes .. it should be 850 .
  
  Reply
Diya

September 14, 2017 at 3:48 pm

in Q6.

Increase in the number of engineers:
Company V = (400*130)/100 = 520
Company X = (700*135)/100 = 945
Company Y = (950*140)/100 = 1330
Total engineers = 520 + 650+ 945 + 1330 + 750 = 4195
Total original number of engineers = 400 + 650 + 700 + 950 + 750 = 3450
% increase = [(4195 – 3450)/3450]*100 = 22%(approx.)

how to find how to find total engineers and original no. of engineers?

Reply
1. Banya
  
  September 14, 2017 at 4:00 pm
  
  we need to take engineers from all the companies .
  
  Reply
  1. Diya
    
    September 14, 2017 at 4:02 pm
    
    ok ty ma’am
    
    Reply
Diya

September 14, 2017 at 3:55 pm

in q 10
total number of assistant engineers = 1050 or 1100??

Reply
1. Banya
  
  September 14, 2017 at 3:59 pm
  
  yes dear .. its 1100 ty 🙂
  
  Reply
  1. Diya
    
    September 14, 2017 at 4:03 pm
    
    ok 🙂
    
    Reply
2. Navyaaaa
  
  September 14, 2017 at 11:27 pm
  
  uhu 8th mai bhi 1100, i calculated correct pr thought I m wrong.. lack of confidence ;(
  
  Reply
Navyaaaa

September 14, 2017 at 11:09 pm

5th mai over-smartness ho gyi farzi mai sbki % calculate kr li, bad m dekha oho published pucha h.. Bhakk 😛 😛

6th m meko lga puri calculation V X Y pr hi krni h uhu uhu

Reply
1. Tapan
  
  September 17, 2017 at 7:15 pm
  
  madam AZ ki di accha hai??
  
  Reply
the walking dead

September 15, 2017 at 1:00 am

10-10:)

Reply
ครђ

September 15, 2017 at 6:14 am

Thanks Banya mam 🙂

Reply
Ap

September 27, 2017 at 12:27 am

Sol for Ques is given wrong no of assistant engi is 1100 of which 137 percentage bcms 1507 while graduate engi after decreasing bcms 1200 so 307/1200%=25℅aprx

Reply
Wikki Waran

October 2, 2017 at 11:59 am

Thank you mam

Reply