# Quantitative Aptitude: Data Interpretation Questions Set 64

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Number of books published by six companies and percentage of books distributed among distributors working with the company

1. What was the difference between the number of books received by each distributor working with company B and the number of books received by each distributor working with company F?
A)Â 324
B)Â 300
C) 264
D) 220
E) 315
Â Â Option C
Solution:
Number of books received by each distributor:
Company B = (6400*90)/(100*10) = 576
Company F = (7200*70)/(100*6) = 840
Required difference = 840 â€“ 576 = 264
2. Among the total number of books distributed by company D the respective ratio of academic and non-academic books was 5:4 . What was the number of non-academic books distributed by the company D?
A)Â 900
B)Â 1400
C) 1550
D) 1010
E) 1200
Â Â Option Â B
Solution:
Number of books distributed by company D = (3500*90)/100 = 3150
Number of non-academic books = 3150*(4/9) = 1400
3. The number of books distributed by company B is what percent of the number of books distributed by company E?
A)Â 155%
B)Â 110%
C) 115%
D)129%
E) 130%
Â Â Option D
Solution:
Number of books distributed by company B = (6400*90)/100 = 5760
company E = (5600*80)/100 = 4480
Required % = (5760 *100)/4480 = 129%(approx.)
4. What was the respective ratio between total number of books distributed Company B and the total number of books distributed by Company C?
A)Â  36:29
B)Â  25:46
C)Â  42:47
D) Â 33:25
E) Â 41:35
Â Â Option A
Solution:

Required ratio = (6400*90)/100: (5800*80)/100 Â = 64*90 : 58*80 = 36 : 29
5. What is the average number of books published by companies A,C and D together?
A)Â 7800
B)Â 4500
C) 4600
D) 5460
E) 7520
Â Â Option C
Solution:
(4500+5800+3500)/3 = 4600
Directions(6-10): In the following bar diagram the number of engineers employed in various companies has been given. Study the bar diagram carefully to answer the questions.
6. If the number of all the engineers in the company V, company X and companyY be increased by 30%, 35% and 40% Â respectively, what will be the overall percentage increase in the number of all engineers of all the companies taken together?
A)18%
B)Â 22%
C) 30%
D) 35%
E) 42%
Â Â Option B
Solution:
Increase in the number of engineers:
Company V = (400*130)/100 = 520
Company X = (700*135)/100 = 945
Company Y = (950*140)/100 = 1330
Total engineers = 520 + 650+ 945 + 1330 + 750 = 4195
Total original number of engineers = 400 + 650 + 700 + 950 + 750 = 3450
% increase = [(4195 – 3450)/3450]*100 = 22%(approx.)
7. What is the average number of junior engineers employed in all the companies?
A)Â 150
B)Â 110
C) 170
D) 200
E) 190
Â Â Option C
Solution:
The average number of junior engineers = 850/5 = 170
8. If the number ofÂ  assistant engineers employed in all the companies be increased by 37% and the number of post graduate engineers employed in all the companies be decreased by 20% by what per cent will the number of assistant engineers be less than that of post graduate engineers?
A)Â 13.52%
B)Â 17.72%
C) 19.87%
D) 22.15%
E) Â 15.42%
Â Â Option C
Solution:
Number of assistant engineers after 37% increase = (1050*137)/100 = 1438.5
Number of post graduate engineers after 20% decrease = (1500*80)/100 = 1200
Required % = [(1438.5 â€“ 1200)/1200]*100 = 19.87%
9. What is the ratio between the number of assistant engineers employed in company V and company X ?
A)Â 5 : 6
B)Â 3 : 4
C) 5 : 7
D) 2 : 3
E) 1 : 2
Â Â Option B
Solution:
Required ratio = 150:200 = 3 : 4
10. What is the difference between the average number of junior engineers and assistant engineers taking all the companies together?
A)Â 10
B)Â 50
C) 30
D) 20
E) 40
Â Â Option B
Solution:
The average number of junior engineers = 850/5 = 170
The average number of assistant engineers = 1100/5 = 220
Difference = 50

## 15 Thoughts to “Quantitative Aptitude: Data Interpretation Questions Set 64”

1. Mission RRB PO

check question no 7 and 10th
total junior engg. == 850

1. Banya

yes .. it should be 850 .

2. Diya

in Q6.

Increase in the number of engineers:
Company V = (400*130)/100 = 520
Company X = (700*135)/100 = 945
Company Y = (950*140)/100 = 1330
Total engineers = 520 + 650+ 945 + 1330 + 750 = 4195
Total original number of engineers = 400 + 650 + 700 + 950 + 750 = 3450
% increase = [(4195 â€“ 3450)/3450]*100 = 22%(approx.)

how to find how to find total engineers and original no. of engineers?

1. Banya

we need to take engineers from all the companies .

1. Diya

ok ty ma’am

3. Diya

in q 10
total number of assistant engineers = 1050 or 1100??

1. Banya

yes dear .. its 1100 ty ðŸ™‚

1. Diya

ok ðŸ™‚

2. Navyaaaa

uhu 8th mai bhi 1100, i calculated correct pr thought I m wrong.. lack of confidence ;(

4. Navyaaaa

5th mai over-smartness ho gyi farzi mai sbki % calculate kr li, bad m dekha oho published pucha h.. Bhakk ðŸ˜› ðŸ˜›

6th m meko lga puri calculation V X Y pr hi krni h uhu uhu

1. Tapan

madam AZ ki di accha hai??

10-10:)

6. à¸„à¸£Ñ’

Thanks Banya mam ðŸ™‚

7. Ap

Sol for Ques is given wrong no of assistant engi is 1100 of which 137 percentage bcms 1507 while graduate engi after decreasing bcms 1200 so 307/1200%=25â„…aprx

8. Wikki Waran

Thank you mam