Quantitative Aptitude: Data Interpretation Questions – Set 87

Directions (1–5): Study the bar graph and answer the questions given below.

  1. The ratio of the average income of all the years to the average profit is
    8:3
    12:5
    10:3
    6:1
    None
    Option C
    Solution:
    Average income =(40+30+60+50+70)/5
    =250/5=50.
    Average profit=[(40-25) +(30-20) +(60-45) +(50-30) + (70-55)] /5
    =(15+10+15+20+15)/5
    =75/5=15.
    Required ratio 50:15
    =10:3.
  2. Percentage increase in profit in 2009 over 2008 is
    20%
    12 1/2%
    25%
    33 1/3%
    None
    Option D
    Solution:
    Profit in 2008=60-45=15
    Profit in 2009=50-30=20
    Increase in profit=20-15=5.
    %ge increase=5/15 *100
    =33 1/3%.
  3. The total income exceeds the total expenditure over the year by
    75Lakh
    60Lakh
    45Lakh
    80Lakh
    None
    Option A
    Solution:
    Total income= 40+30+60+50+70
    =250
    Total Expenditure=25+20+45+30+55
    =175
    The total income exceeds the total expenditure by 250-175
    =75Lakh.
  4. What is the difference in profit between 2010 and 2006
    10Lakh
    Equal profit
    15Lakh
    5Lakh
    None
    Option B
    Solution:
    Profit in 2010 =70-55
    =15.
    Profit in 2006=40-25
    =15.
    Both are equal.
  5. The number of years in which the income is more than the average income of the given year is
    2007
    2009
    2008, 2010
    2006, 2007
    None
    Option C
    Solution:
    Average income =(40+30+60+50+70)/5
    =250/5=50.
    Both 2008 and 2010, the income increases more than its average.

Directions (6-10): The following line graph gives the percentage of the number of candidates who qualified an examination out of the total number of candidates who appeared for the examination over a period of six years from 2000 to 2005.

  1. In which pair of years was the number of candidates qualified the same?
    2000 and 2005
    2003 and 2004
    2001 and 2005
    Data Inadequate
    None
    Option D
    Solution:
    Data Inadequate.
  2. If the number of candidates qualified in 2004 was 14000, what was the number of candidates appeared in the same year?
    25000
    20000
    30000
    18000
    None
    Option B
    Solution:
    The number of candidates appeared in 2004 be x.
    70% of x = 14000
    x = (14000 *100)/(70)
    x=20,000.
  3. The difference between the percentages of candidates qualified to appear was maximum in which of the following pairs of years?
    2000 and 2004
    2001 and 2002
    2005 and 2003
    2002 and 2000
    2001 and 2004
    Option E
    Solution:
    Check from options
    2000 and 2004= 70-40=30
    2001 and 2002=60-30=30
    2005 and 2003=50-40=10
    2002 and 2000=60-40=20
    2001 and 2004=70-30=40.
    The maximum difference is between the years 2001 and 2004.
  4. If the total number of candidates appeared in 2000 and 2003 together was 32500, then the total number of candidates qualified in these two years together was?
    22000
    18000
    24500
    Data Inadequate
    None
    Option D
    Solution:
    Data Inadequate.
  5. The total number of candidates qualified in 2003 and 2005 together was 37000 and the number of candidates appeared in 2003 was 42000. What was the number of candidates in 2005?
    35000
    52000
    40000
    44000
    None
    Option C
    Solution:
    The number of candidates qualified in 2003
    = 50% of 42000
    = 21000.
    Number of candidates qualified in 2005
    = 37000 – 21000
    = 16000.
    Let the number of candidates appeared in 2005 be x.
    Then 40% of x = 16000
    x=40000.


 

Related posts

Leave a Comment