**Directions (1–5): Study the bar graph and answer the questions given below.**

- The ratio of the average income of all the years to the average profit is
8:312:510:36:1NoneOption C

Solution:

Average income =(40+30+60+50+70)/5

=250/5=50.

Average profit=[(40-25) +(30-20) +(60-45) +(50-30) + (70-55)] /5

=(15+10+15+20+15)/5

=75/5=15.

Required ratio 50:15

=10:3.

- Percentage increase in profit in 2009 over 2008 is
20%12 1/2%25%33 1/3%NoneOption D

Solution:

Profit in 2008=60-45=15

Profit in 2009=50-30=20

Increase in profit=20-15=5.

%ge increase=5/15 *100

=33 1/3%.

- The total income exceeds the total expenditure over the year by
75Lakh60Lakh45Lakh80LakhNoneOption A

Solution:

Total income= 40+30+60+50+70

=250

Total Expenditure=25+20+45+30+55

=175

The total income exceeds the total expenditure by 250-175

=75Lakh.

- What is the difference in profit between 2010 and 2006
10LakhEqual profit15Lakh5LakhNoneOption B

Solution:

Profit in 2010 =70-55

=15.

Profit in 2006=40-25

=15.

Both are equal.

- The number of years in which the income is more than the average income of the given year is
200720092008, 20102006, 2007NoneOption C

Solution:

Average income =(40+30+60+50+70)/5

=250/5=50.

Both 2008 and 2010, the income increases more than its average.

**Directions (6-10): The following line graph gives the percentage of the number of candidates who qualified an examination out of the total number of candidates who appeared for the examination over a period of six years from 2000 to 2005.**

- In which pair of years was the number of candidates qualified the same?
2000 and 20052003 and 20042001 and 2005Data InadequateNoneOption D

Solution:

Data Inadequate.

- If the number of candidates qualified in 2004 was 14000, what was the number of candidates appeared in the same year?
25000200003000018000NoneOption B

Solution:

The number of candidates appeared in 2004 be x.

70% of x = 14000

x = (14000 *100)/(70)

x=20,000.

- The difference between the percentages of candidates qualified to appear was maximum in which of the following pairs of years?
2000 and 20042001 and 20022005 and 20032002 and 20002001 and 2004Option E

Solution:

Check from options

2000 and 2004= 70-40=30

2001 and 2002=60-30=30

2005 and 2003=50-40=10

2002 and 2000=60-40=20

2001 and 2004=70-30=40.

The maximum difference is between the years 2001 and 2004.

- If the total number of candidates appeared in 2000 and 2003 together was 32500, then the total number of candidates qualified in these two years together was?
220001800024500Data InadequateNoneOption D

Solution:

Data Inadequate.

- The total number of candidates qualified in 2003 and 2005 together was 37000 and the number of candidates appeared in 2003 was 42000. What was the number of candidates in 2005?
35000520004000044000NoneOption C

Solution:

The number of candidates qualified in 2003

= 50% of 42000

= 21000.

Number of candidates qualified in 2005

= 37000 – 21000

= 16000.

Let the number of candidates appeared in 2005 be x.

Then 40% of x = 16000

x=40000.