**Directions(1-5) :** Study the table carefully and answer the following questions.

- In how many hours pipe A can fill the tank alone, if pipe A, pipe C and pipe E , which takes time half of the pipe B, if all are open together for 6 hours?
4 hours8 hours3 hours5 hours7 hoursOption D

6/x + 6/15 – 6/10 = 1

=> 6[ 1/x +1/15 – 1/10] = 1

=> x = 5 hours - Pipe C and pipe F are opened together , pipe F works one –third of pipe C’s efficiency then in what time the tank will become empty ?
20(1/4) hours28(1/5) hours23(1/3) hours20(1/2) hours22(1/2) hoursOption E

Let x be the time taken to become the tank empty.

Then, x/15 – x/45 = 1

=> x = 22(1/2) hours - If two pipes B and C are opened simultaneously to fill the tank. In what time should pipe B be closed so that C alone can fill the tank in 8 hours?
4 hours6 hours3 hours5 hours2 hoursOption A

Let pipe B is opened for x hours.

Then, x/20 + x/15 + 8/15 = 1

=> x [1/20 + 1/15] = 1 – 8/15

=> x * 7/60 = 7/15

=> x = 4 hours - If pipe F takes half of the time taken by pipe E and pipe A takes half of the time taken by pipe B. If all the six pipes are opened together and empty the tank in 54 hours. Then what is the time taken by F to empty the tank ?
15(11/43) hours17(13/44) hours18(10/33) hours10(9/27) hours15(15/53) hoursOption E

54/20 + 54/15 + 54/10 – 54/x – 54/2x – 54 /10 = 1

=> 54 [1/20 + 1/15 + 1/10 – 1/2x – 1/x – 1/10] = 1

=> 7/60 – 1/54 = 3/2x

=> x = 15(15/53) hours - If pipe D and pipe F are open for 3 hours and then pipe F is replaced by pipe E for another 6 hours , to empty a completely filled tank. In how many hours pipe E take to empty the tank completely, if pipe F takes thrice the time taken by pipe E.
20 hours90 hours70 hours60 hours50 hoursOption C

3/10 + 3/3x + 6/x + 6/10 = 1

=> 9/10 + 7/x = 1

=> 7/x = 1 – 9/10

=> x = 70 hours - The selling price of C is what percent of the cost price of B?
320%100%250%110%50%Option C

Selling price of C

= (Cost price + Cost on transportation + Profit)

= 250 + 20 + 5 = 275

Cost price of B = Selling price + Loss = 100 + 10 = 110

Required % = 275 *100% / 110 = 250% - What is the difference between the selling price of E and that of C?
174.4110188.3191.4190.5Option D

Selling price of E

= Cost price of E + Cost on transportation + Profit = 400 + 40 + 440 *6/100

= 466.4

Selling price of X = 275

Difference = 466.4 – 275 = 191.4 - If the loss on A is 5%, then its selling price is what percentage less than the selling price of E ?
66.6%84.4%95.2%83.7%73.8%Option D

Selling price of A

= (Cost price + Cost of Transportation) = 95/100 = (50 + 30) × 95 /100 = 76

Selling price of E = 466.4

Required % = 466.4 – 76 /466.4 *100% = 83.7% - The percentage profit on A is 4%. Then what is its selling price?
Rs.65.3Rs.97.8Rs.83.2Rs.72.5Rs.78.3Option C

Cost price of A = 50

Transportation cost = 30

Total cost price = 50 + 30 = 80

Profit = 4%

Selling price = 80 × 104 /100 = 83.2 - What is the ratio of the loss on D to that on B ?
743: 344833 : 500741 : 453714 : 487653 : 100Option B

Loss on D = Cost price of D – Selling price of D

= 400* 100/96 – 400 = 416.66 – 400 = 16.66

Loss on B = 10

Required ratio = 16.66 : 10 = 833 : 500

**Directions(6-10) :** Study the given table carefully to answer the given questions.

Percentage profit or loss is based on the sum of cost price and transportation cost

in Missing Value .