Quantitative Aptitude: Data Interpretation Set 5

Directions (1-5): Study the following table and answer the following:

Products Sales (in lakhs)
in 2012
Percentage growth in the sales
over the previous years
2013 2014 2015
A 2 5 10 10
B 3 8 10 20
C 3.6 10 10 12
D 3 9 10 12
  1. Find the difference between the sales of products A and B in the year 2015.
    A) 154320
    B) 173580
    C) 143420
    D) 185280
    E) 165890
    View Answer
    Option B
    Explanation:

    Sales of A in 2015 = 2 lacs × 105/100 × 110/100 × 110/100 = 254100
    Sales of B in 2015 = 3 lacs × 108/100 × 110/100 × 120/100 = 427680
    So difference = 427680 – 254100 = 173580
  2. Find the ratio of sales of product C in 2014 to the sales of product D in 2015.
    A) 875 : 654
    B) 825 : 763
    C) 962 : 744
    D) 796 : 733
    E) None of these
    View Answer
    Option B
    Explanation:

    Sales of C In 2014 = 3.6 lacs × 110/100 × 110/100
    Sales of D In 2015 = 3 lacs × 109/100 × 110/100 × 112/100
    So ratio = 3.6 lacs × 110/100 × 110/100 : 3 lacs × 109/100 × 110/100 × 112/100
  3. What is the percentage increase in sales of all the four products in 2014 as compared to 2012?
    A) 14.22
    B) 15.67
    C) 20.97
    D) 18.35
    E) 19.19%
    View Answer
    Option E
    Explanation:

    Sales of A in 2014 = 2 lacs × 105/100 × 110/100 = 231000
    Sales of B in 2014 = 3 lacs × 108/100 × 110/100 = 356400
    Sales of C in 2014 = 3.6 lacs × 110/100 × 110/100 = 435600
    Sales of D in 2014 = 3 lacs × 109/100 × 110/100 = 359700
    So total sales in 2014 = 1382700
    Total sales in 2012 = 1160000
    So % increase = (1382700 – 1160000)/1160000 * 100 = 19.19%
  4. Of all the products, which product showed the highest percentage increase in total sales at the of 2015 in four years?
    A) A
    B) B
    C) C
    D) D
    E) None of these
    View Answer
    Option B
    Explanation:

    Sales of A in 2015 = 2 lacs × 105/100 × 110/100 × 110/100 = 254100
    Sales of B in 2015 = 3 lacs × 108/100 × 110/100 × 120/100 = 427680
    Sales of C in 2015 = 3.6 lacs × 110/100 × 110/100 × 112/100 = 487872
    Sales of D in 2015 = 3 lacs × 109/100 × 110/100 × 112/100 = 402864
    So
    % increase in sales of product A = (254100-200000)/200000 * 100 = 27.05%
    % increase in sales of product B = (427680-300000)/300000 * 100 = 42.56%
    % increase in sales of product C = (487872-360000)/360000 * 100 = 35.52%
    % increase in sales of product D = (402864-300000)/300000 * 100 = 34.28%
    So maximum for B
  5. If the ratio of defective to non-defective A products is 2 : 3 in 2012 while that of products C is 4 : 5 in same year, then what is the ratio of defective A products to non-defective B products in 2012?
    A) 1 : 4
    B) 4 : 7
    C) 3 : 7
    D) 2 : 5
    E) 2 : 7
    View Answer
    Option D
    Explanation:

    Number of defective A products in 2012 = 2/5 * 2,00,000 = 80,000
    Number of non-defective C products in 2012 = 5/9 * 3,60,000 = 2,00,000
    So required ratio = 80,000 : 2,00,000 = 2 : 5

Directions (6- 10): Study the following chart carefully and answer the questions that follow:
The chart shows the number of students in six 6 classes of 2 different schools ABC and XYZ.

  1. What is the difference between the students of class II and IV in school ABC and the students of class I and V in school XYZ?
    A) 90
    B) 120
    C) 80
    D) 50
    E) 110
    View Answer
    Option C
    Explanation:

    II and IV in ABC = 280+620 = 900
    I and V in XYZ = 320+660 = 980
  2. What is the ratio of number of students in classes I and IV in school ABC to number of students in classes II and VI in school XYZ?
    A) 23 : 56
    B) 45 : 59
    C) 43 : 55
    D) 25 : 41
    E) None of these
    View Answer
    Option C
    Explanation:

    24+62 : 36+74
    86 : 110
    43: 55
  3. Students in school ABC are approximately what percent lesser than students in school XYZ?
    A) 15%
    B) 27%
    C) 33%
    D) 12%
    E) 22%
    View Answer
    Option E
    Explanation:

    In ABC = 2280
    In XYZ = 2920
    Required % = (2920-2280)/2920 * 100
  4. If from school ABC, 5% and 10% of students of classes IV and I respectively gets shifted to same respective classes in school XYZ, then find the average number of students in classes I and IV in school XYZ.
    A) 429
    B) 553
    C) 467
    D) 429
    E) 534
    View Answer
    Option C
    Explanation:

    From D = 5/100 * 620 = 31
    From A = 10/100 * 240 = 24
    So now in A and D in XYZ = 320+24 + 560+31 = 935
    So average = 935/2 = 467.5
  5. Students in class V in school ABC is what percent of the number of students in classes II and III together in school XYZ?
    A) 64.78%
    B) 68.75%
    C) 75.75%
    D) 99.35%
    E) 102.55%
    View Answer
    Option B
    Explanation:

    440/(360+280) * 100

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