 # Quantitative Aptitude: Data Interpretation Set 6 (Missing DI)

Directions (1 – 5):
The table shows the number of males (M) and females (F) in Five Companies A, B, C, D and E during Six years.
Some values are missing in the table. To answer each question, refer to data in table and respective question.

 Company/ Year A B C D E M F M F M F M F M F 2011 202 102 142 12 2012 112 105 136 20 2013 182 126 164 150 140 38 2014 122 106 118 104 100 85 2015 124 105 100 100 2016 138 142 128 186 124 125
1. If the average number of female workers in all the given companies in 2013 is 156 and the difference between average number of female workers in all the given companies in 2013 and average number of male workers in all the given companies in 2016 is ten, then what is the difference between the male workers in Company D in 2016 and female workers in company E in 2013?
A) 8
B) 6
C) 5
D) 4
E) 2
Option D
Solution:

Average number of female workers in all the given companies in 2013 = 156
Total female workers = 156 * 5 = 780
So the female workers in Company E in 2013 = 780 – 644 = 136
Average number of male workers in all the given companies in 2016 = 156-10 = 146
So total male workers = 146 * 5 = 730
The male workers in Company E in 2016 = 730 – 590 = 140
Difference = 140 – 136 = 4
2. If the total female workers in Company B is 830 and the average female workers in company C is 100 for the years 2012, 2013, 2014 and 2015, then the total number of female workers in Company B in 2012, 2013, 2014 and 2015 together is what percent more than the total number of female workers in Company C in the same years together?
A) 40%
B) 16%
C) 25%
D) 18%
E) 20%
Option C
Solution:

Average female workers in company C (2012, 2013, 2014 and 2015) = 100
Total female workers in company C (2012, 2013, 2014 and 2015) = 100*4 = 400
Total female workers in Company B = 830
Total female workers in company B (2012, 2013, 2014 and 2015) = 830 – (202+128) = 500
Required % = (500 – 400)/400 * 100 = 25%
3. If the average of total number of workers (male and female) in companies A, B and C together in 2013 is 220 and in the year 2014, the sum of male workers of company B and female workers of company C is 100, then what is the ratio of the total number of workers (male and female) in companies A, B and C together in 2013 to the total number of workers (male and female) in the same companies together in 2014?
A) 4:3
B) 6:5
C) 2:5
D) 8:5
E) 2:3
Option B
Solution:

Total number of workers (male and female) in companies A, B and C together in 2013 = 660
Total number of workers (male and female) in companies A, B and C together in 2014 = 100 + 122 + 106 + 104 +118 = 550
Ratio = 660 : 550 = 6:5
4. Total number of workers (male and female) in company D in the year 2011 is 280 and then decreased by 20 for every year. Total number of workers (male and female) in company E in the year 2011 is 20 and then doubled for every year. The total number of female workers in company E during all the given years together is what percent (approximately) of the total number of male workers in company D during all the given years together?
A) 40%
B) 56%
C) 65%
D) 68%
E) 70%
Option E
Solution:

For the year 2012, males = 260 -136 =124
For the year 2013, males = 240 – 140 =100
For the year 2015, males = 200 – 100 =100
Total number of male workers = 142 + 124 + 120 + 100 + 100 + 124 = 710
For the year 2011, females = 20 – 12 =8
For the year 2013, females = 80 – 38 =42
For the year 2015, females = 320 – 100 = 220
Total number of female workers = 8 + 20 + 42 + 85 + 220 + 125 = 500
Required % = (500/710)* 100 = 70.42%
5. Total number of workers (male and female) in company D in the year 2011 is 280 and then decreased by 20 for every year. Total number of workers (male and female) in company E in the year 2011 is 20 and then doubled for every year. The total number of female workers in company E during all the given years together is what percent (approximately) less than the total number of male workers in company D during all the given years together?
A) 14%
B) 16%
C) 25%
D) 29%
E) 18%
Option D
Solution:

For the year 2012 = 260 -136 =124
For the year 2013 = 220 – 120 =100
For the year 2015 = 200 – 100 =100
Total number of male workers = 142 + 124 + 120 + 100 + 100 + 124 = 710
For the year 2011 = 20 – 12 =8
For the year 2013 = 80 – 38 =42
For the year 2015 = 320 – 100 = 220
Total number of female workers = 8 + 20 + 42 + 85 + 220 + 145 = 500
Required % = (710 – 500/710)* 100 = 29.57%

Directions (6 – 10):
The table shows the number of marks secured by each student in different subjects. The marks are out of total 150 marks in each subject.
Some values are missing in the table. To answer each question, refer to data in table and respective question.

 Student/Subject English Maths Physics Chemistry Biology Statistics (150) (150) (150) (150) (150) (150) Ravi ___ 140 ___ 120 ___ 140 Pavi ___ ___ 115 126 140 ___ Suresh 80 ___ 64 100 ___ 120 Ramesh ___ 150 120 ___ ___ 130 Geeta 88 ___ ___ 112 ___ 142 Sita 104 132 138 ___ 132 ___
1. If the average marks of Pavi and Suresh is 105 and the marks scored by Pavi & Suresh in Maths is 60 less than that of marks scored by Ramesh & Suresh in Biology. Find the respective ratio of the total marks obtained by Pavi and Suresh in Maths and that scored by Suresh and Ramesh in Biology?
A) 1 : 3
B) 3 : 5
C) 7 : 5
D) 7 : 9
E) None of these
Option D
Solution:

Average marks of Pavi and Suresh = 105
Marks of Pavi and Suresh = 210
Marks of Suresh and Ramesh = 270
Ratio = 210 : 270 = 7 : 9
2. Total marks obtained by six students in Maths is 700 and average marks of Pavi and Suresh in Maths is 105. If 40% of mark is required to pass each subject then what is the difference between the minimum pass marks and marks scored by Geeta?
A) 3
B) 5
C) 8
D) 7
E) None of these
Solution:
Option C
Maths marks of Geeta = 700 – (140 + 150 + 132 + 210) = 68
Minimum pass marks = 40/100 * 150 = 60
Difference = 8
3. If the average marks of Ravi in English, Physics and Biology is 120 and the sum of the marks obtained by Ravi in Maths, Chemistry and Statistics is same as the marks obtained by Ramesh in English, Physics and Chemistry then the total marks scored by Ravi in all subjects together is what % of total marks obtained by Ramesh in all the subjects together?
A) 65%
B) 95%
C) 85%
D) 75%
E) None of these
Option B
Solution:

Average marks of Ravi in English, Physics and Biology = 120
Total marks of Ravi in English, Physics and Biology = 360
Marks obtained by Ravi in Maths, Chemistry and Statistics = 400
Total marks scored by Ravi in all subjects together = 360 + 400 = 760
Total marks scored by Ramesh in all subjects together = 400 + 400 = 800
Required % = 760/800 * 100 = 95%
4. If Marks scored by Sita in Chemstry and Statistics is 30 less than the marks scored by herself in Maths then find the overall % of marks obtained by Sita in Maths, Chemistry and Statistics?
A) 63%
B) 55%
C) 84%
D) 62%
E) 52%
Option E
Solution:

Marks obtained by Sita in Maths, Chemistry and Statistics = 102 + 132 = 234
% of marks obtained by Sita in Maths, Chemistry and Statistics = 234/450 * 100 = 52%
5. Pavi’s marks in Statistics equals to 50% of the marks scored by herself in Biology while Sita’s Marks in Statistics is 10 less than the marks scored by herself in Physics. Then what is the average marks scored by students in Statistics?
A) 112.3
B) 121.7
C) 184.5
D) 162.4
E) 152.4
Option B
Solution:

Pavi’s marks in Statistics = 50% of 140 = 70
Sita’s Marks in Statistics = 138 – 10 = 128
Average = ( 140 + 70 + 120 + 130 + 142 + 128)/6

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