# Quantitative Aptitude: Mixture and Alligation Questions Set 7

1. A shopkeeper sells two types of books national books and international books .He sells national books at Rs. 18 / bookÂ  and incurs at loss of 10% whereas on selling the international books at Rs. 30 / book ,he gains 20 % .Find the ratio of the national and international books such that he can gain a profit ofÂ  25% by selling the combined books at 27.5/ book ?
A)Â  5:6
B) Â 5:2
C) Â 4:5
D) Â 2:3
E) Â 4:7

Option Â B
Solution:
Loss at national books = Â 10% = 1/10
SP -> 9 = 18
1 = 2
CP -> 10 = 20
Gain atÂ  international books = 20 % = 1/5
SP -> 6 = 30
1 = 5
CP ->5 = 25
CP = 4 *5.5Â  = 22
National Books Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â International Books
20 Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â 25
Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â Â
. Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  22
5 Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â 2
2. One test Â tube contains some acid and another test tube contains an equal quantity of water .To prepare a solution , 20 g of the acid is poured into the second test tube .Then , two â€“third of the so- formed solution is poured from the second tube into the first .If the fluid in the first test tube is four times that in the second ,what quantity of water was taken initially ?
A)Â  90 g
B)Â  70 g
C)Â  Â 154 g
D) Â 100g
E) Â Â 180 g

Option Â D
Solution:
Let x g of water was taken initially .
1st process
First test tube (x- 20)
second test tube (x +20)
2nd process
First test tube = [(x-20) +2/3 (x+20)]
Second test tube = 1/3(x+20)
Now ,
(x -20 ) + 2/3(x+20) = 4* (1/3)(x+20)
=> x = 100 g
Â
3. Two brands of detergents are to be combined . DetergentÂ  A containsÂ  40 % bleach and 60 % soap . While detergent Â B contains Â 25 % bleach andÂ  75%Â  soap . If the combined mixture is to be 35 % bleach .What % of the final mixture should be detergent A?
A)Â  30%
B)Â 45.64%
C)Â Â  20%
D) Â 32.5%
E) Â 66.67%

Option E
Solution:
A Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â  B
40Â Â Â Â Â Â Â Â Â Â  Â Â Â Â Â Â Â  Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â  Â Â Â Â Â Â Â Â Â Â Â  25
. Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  35
10Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â  Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 52 Â  : Â  Â 1
Therefore ,
% of detergent in A = (2 /3) *100 =
4. A thief has stolenÂ  15 L of beer from a container and replaced with the same quantity of water .He again repeated this process 3 times .Thus the ratio of the beer become 343 :169 .Find the initial amount of beer in the container .
A)Â  90 L
B)Â 120 L
C) 140 L
D) Â 110 L
E) Â 80 L

Option B
Solution:
The initial amount of beer in the container was =343 + 169 = 512 L
Initial amt. of beerÂ  : After mixed with water
512 : 343
Taking cube roots on both the sides,
8 :7
For 1 unit of beer -> 15 L
For 8 units of beer -> 120 L
5. A tank which contains a mixture of syrup and water in ratio 15:6. 25.5 litres of mixture is taken out from the tank and 2.5 litres of pure water and 5 litres of syrup is added to the mixture. If resultant mixture contains 25% water, what was the initial quantity of mixture in the tank before the replacement in litres?
A)Â  77.7

B)Â  70.78
C) 75.6
D) Â 80.5
E) Â 76

Option Â A
Solution:
Quantity of Syrup = 15x

Quantity of water =6x
Total = 21x
Resultant Mixture = 21x â€“ 25.5 + 2.5 + 5 = 21x â€“ 18
Resultant water = 6x â€“ 25.5 * (6/21) + 2.5 = 6x â€“ 7.28
Resultant mixture contains 25% water
(21x â€“ 18)*25/100 = 6x â€“ 7.28
x = 3.7
Initial quantity = 21*3.7 = 77.7
6. Ram covered a distance of 200kmÂ  in 10 hrs . The first part of his journey is covered by auto ,then he hired a car Â .The speed of the auto and car isÂ  15 km/hr andÂ  30 km /hr resp. Find the ratio of distance covered by auto and car .
A)Â  3 : 4
B)Â  2 : 1
C) Â 1 : 1
D) Â 2: 3
E) Â None of these

Option C
Solution:
Speed of the Ram = 200 /10 = 20 km/hrAuto Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â  Car
15km/hrÂ Â Â Â Â Â Â Â Â Â Â Â Â  30km/hr. Â  Â  Â  Â  Â  Â  Â  Â  Â  Â 20

10Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â  :Â Â Â Â Â Â Â Â Â Â Â Â Â Â  Â 5
2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â  :Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â  1

Now ,
Ratio ofÂ  distance covered :
AutoÂ Â Â Â Â  Â Â Â Â Â Â Â Â Â Â Â Â :Â Â Â Â Â Â Â Â Â  Â Â Car
2 * 15Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â  Â :Â Â Â Â Â Â Â Â Â Â Â Â  1 *30
30Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â  :Â Â Â Â Â Â Â Â Â Â Â  30
1Â  Â Â Â Â Â Â Â Â Â : Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  Â  1

7. 9 L Â are drawn from a cask full of water and it isÂ  then filled with milk , 9 L of mixture are drawn and the cask is again filled with milk .The quantity of water now left in the cask to that of the milk in it is 16 : 9 .How much does the cask hold ?
A)Â  30 L
B)Â  45 L
C)Â  35 L
D) Â 50 L
E) Â 42 L

Option B
Solution:
16 – > water
25 – > milk
=> âˆš(16/25) = 4/5
If 1 -> 9
then 5 = 45 litres
8. If Â 2 kg metal , of which (1/3) is zinc and the rest is copper , be mixed with 3 kg of metal , of which (1/4) is zinc and the rest is copper . What is the ratio of zinc to copper in the mixture ?
A)Â  11 : 43
B)Â  15 : 37
C) 17 : 43
D) 23 : 74
E) Â 18 : 52

Option C
Solution:
Quantity of zinc in the mixture = 2 (1/3) + 3 (1/4) = ( 2/3) + (3/4)
=17/12
Quantity of copper in the metal = Â (3+2) â€“ (17/12) =Â  43/12
Therefore , 17 / 12 : 43 /12 = 17 : 43
9. VesselsÂ  A and B contain mixtures of milk and waterÂ  in the ratios 4 : 5 and 5 : 1 resp .In what ratio should quantities of mixture be taken from A and B to form a mixture in which milk to water is in the ratio 5 : 4 ?
A)Â  5 : 2
B)Â  7 : 5
C) Â 6 : 11
D) Â 8 : 5
E) Â 9 : 4

Option A
Solution:
Quantity of milk in vessel A = 4 / (4+5) = 4/9
Quantity of milk in vessel B = 5/(5+1) = 5/6
Quantity of milk in resultant mixture = 5 /( 5+4) = 5/9
A Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â  B

4/9Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â  5/6
. Â  Â  Â  Â  Â  Â  Â  Â 5/9
5/18Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â  1/9
Required ratio=Â 5:2
10. Two barrels conatin a mixture of ethanol and gasoline is 60%Â  in the first barrel and 30% in the second barrel .In what ratio must the mixtures from the first and the second barrels be taken to form a mixture containing 50% alcohol ?
A)Â  3:4
B)Â  5:8
C) Â 1:2
D) Â 5:4
E) Â 2 :1

Option E
Solution:
Mix. IÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â  Mix. II
3/5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â  3/10
. Â  Â  Â  Â  Â  Â  Â  Â  Â 1/2
1/5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â  1/10
Required ratio = 2 : 1

## 27 Thoughts to “Quantitative Aptitude: Mixture and Alligation Questions Set 7”

1. _/_

A shopkeeper sells two types of books national books and international books .He sells national books at Rs. 18 / book and incurs at loss of 10% whereas on selling the international books at Rs. 30 / book ,he gains 20 % .Find the ratio of the national and international books such that he can gain a profit of 25% by selling the combined books at 27.5/ book ?
A) 5:6
B) 5:2
C) 4:5
D) 2:3
E) 4:7
ans :3:2 hona chaiye mod
check that
…………..

2. _/_

A tank which contains a mixture of syrup and water in ratio 15:6. 25.5 litres of mixture is taken out from the tank and 2.5 litres of pure water and 5 litres of syrup is added to the mixture. If resultant mixture contains 25% water, what was the initial quantity of mixture in the tank before the replacement in litres?
A) 77.7
B) 70.78
C) 75.6
D) 80.5
E) 76
qs wrong hai kya?

3. _/_

the income of a trader increases in the ratio of 4:5 in the first year and 5:7 in the second year but reduction in the third year in the ratio 14:15. Find out the ratio of his income in the beginning and at the end

1. thinker

Solution plz

1. thinker

Third year bhi increase hi show Ho rha h question me .8:15 is answer. Am I right

2. sneha

8:5?

4. Jellyfish

8/10 ty az
Que 1 ans should be 3:2
Que 6 alternate method
X/15+(200-x)/30=10
X=100
Ratio of dist 1:1

1. thinker

Question 2 ka koi shortcut h kya?

1. Jellyfish

Nahi hai Maine waise hi kiya

5. thinker

8/10

6. thinker

Mam question 5 dusre formule se alg answer show Kr rha .is this question wrong

1. Oliver Queen

haan

7. Oliver Queen

ma’am que 1 mein 3:2 hona chahie ye 5:2 kaise hua?

1. Hungry for success

typo ho gya hoga

2. cActi?

Yes..
Ans. is 3:2

8. Hungry for success

A thief has stolen 15 L of beer from a container and replaced with the same quantity of water .He again repeated this process 3 times .Thus the ratio of the beer become 343 :169 .Find the initial amount of beer in the container .
total 4 time nai hua kya sir/mam
@subra mam

1. cActi?

Three times hoga..

1. Hungry for success

again 3 times plus 1 time phle b kiya?=4 times hua na?

9. Hungry for success

6th question me 2;1 kya h speed k ratio ya distance ki ratio??
samj nai aaya .i think distance ki h bki sir plz conform

1. In the END

2:1 is time ratio. You have to multiply it by their respective speed to get the distance ratio.

1. Hungry for success

Okk thanx bro

10. jaga

Niranjan and Prabhat are working in PMO. They are working together and take 9.5 days to finish a project. When Niranjan and Prabhat are working individually to finish half of the same project then the sum of the number of days taken by them individually is 20 days. If Niranjan is more efficient than Prabhat, how long will Prabhat alone take to do the job?

11. jaga

thank u

12. jaga

q1=ans 3:2

1. Bishwas Choubey

yo right

13. ~lonely~hanker~nitrous oxide~

A tank which contains a mixture of syrup and water in ratio 15:6. 25.5 litres of mixture is taken out from the tank and 2.5 litres of pure water and 5 litres of syrup is added to the mixture. If resultant mixture contains 25% water, what was the initial quantity of mixture in the tank before the replacement in litres?
mam dekhna kha galat hai
15x+5/6x+2.5=3/1
15x+5==18x+7.5
3x==2.5 ??
x===2.5*21/3
initai;la ===
2.5*21/3+25.5

14. ~lonely~hanker~nitrous oxide~

tq ,mam