# Quantitative Aptitude: Percentage Questions Set 8

1. In a company, there are 75% skilled workers and remaining ones are unskilled. 80% of skilled workers and 20% of unskilled workers are permanent. If number of temporary workers is 126, then what is the number of total workers?
430
360
400
380
None
Option B
Let the number of total workers = X
Number of skilled workers = 75% of X =75X/100 = 3X/4
No. of unskilled workers = 25% of X = 25x/100 = X/4
No. of permanent workers,
= (80/100)*(3X/4) + (20/100)*(X/4)
= (3X/5) + (x/20)
= 13X/20
No. of temporary workers,
= X -(13X/20) = 7X/20
Now,
7X/20 = 126
X = 360.

2. In a school there are 50 more girls than boys. If the number of girls is increased by 20% and the number of boys is also increased by 50%, there would be 30 more girls than boys. What is the number of students in the school?
280
200
300
250
None
Option D Let the no of boys be x.
Girls be x+50.
(x+50)*120/100 = x*150/100 + 30
30=(150x-120x)/100
30=30x/100
X boys=100
Then girls =150
Total=250.

3. Three papers were set in an examination and the maximum marks per were in the ratio of 2 : 5 : 4, respectively. If a student obtained 50% in the first paper, 60% in the second, and 75% in the third, what percent did he obtain overall?
63 7/11%
45%
52 4/5%
62%
None
Option A Maximum mark ratio 2:5:4
Student mark ratio =(0. 5*2 + 0.6*5 +0.75*4)
=(1+3+3)=7
=(1+3+3) /(2+5+4) *100
=7/11 * 100=63 7/11%.

4. A bag contains 1000 Dairymilk chocolate and 1500 Milky bar chocolate. If 30% of Dairy milk and 10% of Milky bar are removed, then what is the approximately percentage of total chocolates removed from the bag?
26%
22%
18%
12%
None
Option C 1000 + 1500=2500
30% of 1000=300
10% of 1500=150
450/2500 Ã— 100=18%.

5. In an examination it is required to get 240 of the total maximum aggregate marks to pass. A student gets 210 marks and is declared failed. The difference of marks obtained by the student and that required to pass is 5%. What are the maximum aggregate marks a student can get?
460
400
550
600
None
Option D 240 -210= 30
5……..30
100 ? =600.

6. The sum of two numbers is 28/25 of the first number. The second number is what percent of the first?
20%
22%
12%
16%
None
Option C Let the 1st no be x. 2nd no be y.
x+y = 28 / 25 x
y=3x/25.
Percentage =3/25 * 100 =12%.

7. In how many years will a sum of Rs1000 at 20% per annum compounded semiannually become Rs1210?
5
1
2
4
None
Option B
1210= 1000*(1+10/100)2n
1210/1000= (11/10)2n
2n=2.
n = 1

8. 15% of the voters in an election did not cast their votes. In this election, there were only two candidates. The winner by obtaining 45% of the total votes defeated his contestant by 2500 votes. The total number of voters in the election was:
40000
30000
45000
50000
None
Option D Let the total votes be 100.
100-15=85.
Diff between two candidates
45 – 40= 2500
5——-2500
100—-? ==> 50000.

9. What is the percentage change in the result when we add 45 to a certain number x, instead of subtracting 45 from the same number x?
8
15
10
Cannot be determined
None
Option D Cannot be determined.

10. A book consist of 30 pages, 25 line on each page and 35 characters on each line. If this content is written in another note book consisting 30 lines and 28 characters per line then the required no. of pages will how much percent greater than previous pages?
6.66%
4.35%
5%
5.32%
None
Option A Let the required number of pages be X.
30*25*35 = X*30*28
X = 31.25 â‰ˆ 32
% increase in number of pages,
= (2/30)*100 = 6.66%.

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