- A bag contains 12 white and 18 black balls. Two balls are drawn in succession without replacement.
37/14535/14233/14136/14531/140Option D

Required probability,

=(2/5)×(18/29)

=36/145 - There are four hotels in a town. If 3 men check into the hotels in a day then what is the probability that each checks into a different hotel?
1/42/53/84/92/7Option C

Required probability

=24/4^3

=3/8 - A card is drawn from a pack of 52 cards. The card is drawn at random. What is the probability that it is neither a spade nor a Jack?
8/115/74/59/138/13Option D

Probability of getting spade or a jack

=(13+3)/52

=4/13

So probability of getting neither spade nor a jack

=1−4/13

=9/13 - A bag contains 5 red and 3 green balls. Another bag contains 4 red and 6 green balls. If one ball is drawn from each bag. Find the probability that one ball is red and one is green.
17/4221/4019/4420/4319/41Option B

Required probability = 3/8+3/20 = 21/40 - Two brother X and Y appeared for an exam. The probability of selection of X is 1/7 and that of B is 2/9. Find the probability that both of them are selected.
4/652/632/653/622/61Option B

Probability =(1/7)*(2/9)

=2/63 - Two brothers appeared for an exam. The probability of each of them getting selected is 1/4 and 1/6 respectively. Find the probability that only one of the two are selected.
1/71/51/41/21/3Option E

Probability that only of the two are selected

= [(1/4)*(5/6)]+[(3/4)*(1/6)]= [5/24]+[3/24]= 8/24

= 1/3 - A card is selected at random from a pack of cards. After replacing it, another draw is made. Find the probability that the first card is a spade and the second is a club.
1/181/161/171/131/15Option B

P(drawing a spade) = 13/52 = 1/4

P(drawing a club) = 1/4

Probability = (1/4)*(1/4) = 1/16 - A bag contains 2 red, 4 blue and 6 green balls. If one ball is drawn from the bag, what is the probability that it is red or green?
2/35/65/93/72/5Option A

Required Probability = 8/12 = 2/3 - Two friends appear for an interview. The probability of each of them getting selected is 1/5 and 1/6 respectively. Find the probability that both are selected.
1/351/331/301/311/29Option C

P(both being selected)

= (1/5)*(1/6)

= 1/30 - Three unbiased coins are tossed. What is the probability of getting at most two heads ?
6/73/58/97/84/5Option D

Probability = 7/8