Two friends A and B appeared for an selection . Let E1 be the event that A is selected and E2 is the event that B is selected. The probability of E1 is 2/5 and that of E2 is 3/7. Find the probability that both of them are selected.
Option C Given, E1 be the event that A is selected and E2 is the event that B is selected. P(E1)= 2/5 P(E2)=3/7 Let E3 be the event that both are selected. P(E1)=P(E1)×P(E2) as E1 and E2 are independent events: P(E3) = 2/5*3/7 P(E3) =6/35 The probability that both of them are selected is 6/35
A policeman forgot the last digit of an 11 digit land line phone number. If he randomly dials the final 2 digits after correctly dialing the first nine, then what is the chance of dialing the correct number
Option E It is given that last two digits are randomly dialed. Then each of the digits can be selected out of 10 digits in 10 ways. Hence required probability =(1/10)2 =1/100
Six boys and five girls stands in queue for buy a pizza in a shop. The probability that they stand in alternate positions is:
Option B Total number of possible arrangements for Six boys and five girls stand in queue =11! When they occupy alternate position the arrangement would be like: bgbgbgbgbgb Thus, total number of possible arrangements for boys, = 6*5*4*3*2 Total number of possible arrangements for girls, =5*4*3*2 Required probability =6*5*4*3*2*5*4*3*2/11*10*9*8*7*6*5*4*3*2 = 1/462
From 4 roses and 5 jasmines , the garland has to be formed with 5 flowers and it contain at least one rose. In how many ways the garland can be formed?
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