- A bag contains 5 ruby balls and 7 black balls. Two balls are drawn at random without replacement, and then find the probability of that one is ruby and other is black?
35/6641/6936/6830/60None of theseOption A

(First ruby ball is drawn and then black ball is drawn) + (first black ball is drawn and then ruby ball is drawn)

(5/12)*(7/11)+(7/12)*(5/11) = 35/66 - A bag contains 3 ruby balls and 8 blue ball and another bag contains 5 ruby balls and 7 blue balls, one ball is drawn at random from either of the bag, find the probability that the ball is ruby?
85/26591/26470/25075/310None of theseOption B

Probability=Probability of selecting the bag and probability of selecting ruby ball

(1/2)*(3/11) + (1/2)*(5/12) =91/264 - X and Y are two persons standing in a circular arrangement with 10 more people. Find the probability that exactly 3 persons are seated between X and Y?
1/53/92/111/10None of theseOption C

Fix X at one point then number of places where Y can be seated is 11.

Now, exactly three persons can be seated between X and Y, soonly two places where Y can be seated.

So, X = 2/11 - 12 friends are seated at a circular table. Find the probability that 3 particular friends always seated together?
4/525/502/153/55None of theseOption D

Total probability=(12-1)! = 11!

Desired Probability = (10 – 1)! = 9!

So, Probability= (9! *3!) /11! =3/55 - Find the probability that in a leap year, the numbers of Wednesday are 53?
2/71/73/74/75/7Option A

In a leap year there are 52 complete weeks i.e. 364 days and 2 more days.

These 2 days can be SM, MT, TW, WT, TF, FS, and SS.

So Probablity of Wednesday = 2/7 - Study the following and answer the questions:

A carton contains 6 ruby balls and 8 grey balls. Two balls are drawn at random one after one with replacement. What is the probability that both the balls are grey?16/4915/4510/5014/48None of theseOption A

Probability = (8/14)*(8/14) = 64/196 =16/49 - If the first one is grey and second one is ruby,find the following?
15/4913/4910/4911/4912/49Option E

Probability = (8/14)*(6/14) =48/196=12/49 - If the both the balls are ruby,find the following?
10/499/4911/4913/49None of theseOption B

Probability = (6/14)*(6/14)=36/196=9/49 - A carton contains 6 beige, 5 grey and 4 ruby balls. Two balls are drawn at random. What is the probability that there is no ruby ball?
10/212/503/1511/21None of theseOption D

Total balls in carton = 15

Not ruby ball means grey or beige ball i.e. any of (5+6) = 11 balls

So probability = 11C2 / 15C2 =11/21 - There are 4 ruby balls, 5 white and 3 grey balls. 3 balls are chosen at random. What is the probability that there is at most 1 grey ball?
48/5540/5542/5450/82None of theseOption A