- In how many different ways the letter of ‘MORBID’ can be arranged ?
780720620680none of theseOption B

required no. of ways=6!=720 - When three coins are tossed simultaneously, then find the probability of getting at least one head.
7/81/83/106/155/8Option A

required no. of outcome= 3C1+ 3C2+ 3C3

=3+3+1=7

total no. of outcome=2^3=8

probability=7/8 - A bag contains 3 red balls, 4 black balls and 7 green balls. 3 balls are drawn randomly, then find the probability of getting all balls are of green colours.
5/529/5211/5215/5217/52Option A

required no. of outcome= 7C3

total no. of outcome= 14C3

probability=(7C3)/ 14C3

=7*6*5/14*13*12=5/52 - When two dice are thrown simultaneously, then find the probability that sum of the digits on both the faces is 8.
9/377/363/375/3611/36Option D

total no. of outcome=6^2=36

required no. of outcome=(3,5), (5,3), (6,2), (2,6), (4,4)=5

probability=5/36 - When two dice are thrown simultaneously, then find the probability that sum of the digits is a multiple of 4.
1/43/109/1013/3617/36Option A

total no. of outcome=6^2=36

required no. of outcome=(4,8,12)

4=(2,2), (3,1), (1,3)

8=(3,5), (5,3), (6,2), (2,6), (4,4)

12=(6,6)

probability=(3+5+1)/36

=9/36=1/4 - If 2 cards are picked randomly from a pack of 52 cards, then find the probability of getting both queen cards.
5/2211/2219/22137/22138/221Option B

required probability= (4C2)/(52C2)

=1/221 - How many 4 digit numbers can be formal by using (0,9), if repetition is not allowed such that unit digit of the number will always be 3 ?
628220548346448Option E

required number of 4 digit number=8*8*7=448 - Find the probability of selecting 2 green balls out of 4 green and 3 red balls.
5/76/74/72/71/7Option D

required probability=(4C2)/(7C2)

4*3/7*6=2/7 - A basket contains 4 blue balls, 3 red balls, 4 green balls and 5 green balls. If 4 balls are picked at randomly, then find the probability that 2 are blue and 2 are yellow ?
4/916/913/919/9611/96Option C

required probability=(4C2)*(5C2)/(16C4)

= (4*3/2*1)*(5*4/2*1)/(16*15*14*13)/(4*3*2*1)

=3/91

- A bag contains 4 yellow, 5 blue and 6 green balls. If 3 balls are drawn at randomly, then find the probability that all ball is not yellow ?
452/455454/4556/355451/4552/455Option D

required probability=(15C3)-(4C3)/15C3

=1-(4*3*2)/(15*14*13)=451/455

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