Quantitative Aptitude: Probability Questions – Set 18

  1. In how many different ways the letter of ‘MORBID’ can be arranged ?
    780
    720
    620
    680
    none of these
    Option B
    required no. of ways=6!=720

     

  2. When three coins are tossed simultaneously, then find the probability of getting at least one head.
    7/8
    1/8
    3/10
    6/15
    5/8
    Option A
    required no. of outcome= 3C1+ 3C2+ 3C3
    =3+3+1=7
    total no. of outcome=2^3=8
    probability=7/8

     

  3. A bag contains 3 red balls, 4 black balls and 7 green balls. 3 balls are drawn randomly, then find the probability of getting all balls are of green colours.
    5/52
    9/52
    11/52
    15/52
    17/52
    Option A
    required no. of outcome= 7C3
    total no. of outcome= 14C3
    probability=(7C3)/ 14C3
    =7*6*5/14*13*12=5/52

     

  4. When two dice are thrown simultaneously, then find the probability that sum of the digits on both the faces is 8.
    9/37
    7/36
    3/37
    5/36
    11/36
    Option D
    total no. of outcome=6^2=36
    required no. of outcome=(3,5), (5,3), (6,2), (2,6), (4,4)=5
    probability=5/36

     

  5. When two dice are thrown simultaneously, then find the probability that sum of the digits is a multiple of 4.
    1/4
    3/10
    9/10
    13/36
    17/36
    Option A
    total no. of outcome=6^2=36
    required no. of outcome=(4,8,12)
    4=(2,2), (3,1), (1,3)
    8=(3,5), (5,3), (6,2), (2,6), (4,4)
    12=(6,6)
    probability=(3+5+1)/36
    =9/36=1/4

     

  6. If 2 cards are picked randomly from a pack of 52 cards, then find the probability of getting both queen cards.
    5/221
    1/221
    9/221
    37/221
    38/221
    Option B
    required probability= (4C2)/(52C2)
    =1/221

     

  7. How many 4 digit numbers can be formal by using (0,9), if repetition is not allowed such that unit digit of the number will always be 3 ?
    628
    220
    548
    346
    448
    Option E
    required number of 4 digit number=8*8*7=448

     

  8. Find the probability of selecting 2 green balls out of 4 green and 3 red balls.
    5/7
    6/7
    4/7
    2/7
    1/7
    Option D
    required probability=(4C2)/(7C2)
    4*3/7*6=2/7

     

  9. A basket contains 4 blue balls, 3 red balls, 4 green balls and 5 green balls. If 4 balls are picked at randomly, then find the probability that 2 are blue and 2 are yellow ?
    4/91
    6/91
    3/91
    9/96
    11/96
    Option C
    required probability=(4C2)*(5C2)/(16C4)
    = (4*3/2*1)*(5*4/2*1)/(16*15*14*13)/(4*3*2*1)
    =3/91

     

  10. A bag contains 4 yellow, 5 blue and 6 green balls. If 3 balls are drawn at randomly, then find the probability that all ball is not yellow ?
    452/455
    454/455
    6/355
    451/455
    2/455
    Option D
    required probability=(15C3)-(4C3)/15C3
    =1-(4*3*2)/(15*14*13)=451/455

     

 

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