Quantitative Aptitude: Problems on Ages Set 4

Problem on Ages Bank PO Questions for SBI PO, IBPS PO, NIACL, NICL, LIC, Dena Bank PO PGDBF, BOI, Bank of Baroda and other competitive exams

  1. Ratio of present age of A and B is 7 : 9 and ratio of ages of A 5 years back and age of B 5 years later is 3:5. Find the present age of B.
    A) 35 years
    B) 45 years
    C) 30 years
    D) 50 years
    E) 40 years
    View Answer
    Option B
    Solution
    :
    A/B=7/9
    (A-5)/(B+5)=3/5
    solve both and get A=35 and B=45
  2. 5 years ago the ratio of ages of A and B are 5:7 and 10 years hence from now ratio will become 4:5. Find the average of present age of A and B.
    A) 30 years
    B) 40 years
    C) 35 years
    D) 45 years
    E) None of these
    View Answer
    Option C
    Solution
    :
    —————————–A ———— B
    5 years ago ————- 5 ———-  7
    10 years hence ——–  4 ———–5
    Difference =      ——– (-1)——– (-2)
    to make these two difference equal multiply the second equation with (7-5)=2
    So we get
    —————————–A ———— B
    5 years ago ————- 5  ———-  7
    10 years hence ——–  8 ———–10
    Difference =      ——– (+3)——– (+3)
    3=15 years (5 ago + 10 hence)
    1=5 years
    => 5 = 25 years (5 years ago of A)
    =>7=35 years (5 years ago of B)
    Hence A=25+5=30
    B=35+5=40 years
    Avg=70/2=35
  3. The present age of a son is 40% of his father age. And the age of his mother is 220% of his age. The average age of three members is 38. Find the present age of mother.
    A) 50 years
    B) 22 years
    C) 10 years
    D) 44 years
    E) None of these
    View Answer
    Option D
    Solution
    :
    Son= 40% of father.
    F:S=5:2
    Mother=220% of son=11/5
    M:S=11:5
    make F:M:S =25:22:10
    avg=(25+22+10)/3=19
    19=38
    1=2
    =>22=44
  4. Rama got married 8 years ago. Her present age is 1 (1/3) times of her age at the time of marriage. She has a son who is one eighth of her present age. Then find the age of her son.
    A) 4 years
    B) 3 years
    C) 2 years
    D) 5 years
    E) None of these
    View Answer
    Option A
    Solution
    :
    1 (1/3)=4/3
    Ratio of present age of Rama and her age at time of marriage=4:3 ——– difference =1
    1=8 years
    4=32
    age of son=32/8=4 years
  5. A says to B “I am thrice as old as you are when I was as old as you were”. If age of B is 20 years find the age of A
    A) 60 years
    B) 30 years
    C) 45 years
    D) 36 years
    E) None of these
    View Answer
    Option B
    Solution
    :
    A                B
    3x              y
    y                x
    3x-y = y-x (difference is same)
    4x=2y
    x/y=1/2
    2=20
    1=10
    3x=30
  6. The fathers age is four times as much as the sum of the age of his three children but 6 years hence his age will be thrice as the sum of their age. The present age of father is?
    A) 60 years
    B) 54 years
    C) 42 years
    D) 48 years
    E) None of these
    View Answer
    Option D
    Solution
    :
    Let sum of children age=x ; hence father =4x
    (4x+6)/x+6 = 3/1
    x=12;
    father=48
  7. In a class of 20 students the average of all the students is 18 years. If the age of their teacher is added then the average becomes 19 years. Find the age of teacher after 5 year.
    A) 44 years
    B) 39 years
    C) 43 years
    D) 38 years
    E) None of these
    View Answer
    Option A
    Solution
    :
    Let age of teacher=x
    (total age)/ total people=19
    360+x/21=19
    x=39
    hence age after 5 years=44
  8. In a family there are 5 brothers in a gap of 2 years. If therir average age is 22 find the sum of eldest and youngest brother.
    A) 42 years
    B) 40 years
    C) 38 years
    D) 44 years
    E) None of these
    View Answer
    Option D
    Solution
    :
    44
    difference is same, hence 22 i.e is average is the age of middle son i.e
    18,20,22,24,26 : age of 5 son
    18+26=44
  9. Four years ago the ratio of ages of A and B is 3:5. After four years from now the ratio will be 5:7. Then find the ratio of their present age.
    A) 5:7
    B) 5:3
    C) 2:3
    D) 7:5
    E) None of these
    View Answer
    Option C
    Solution
    :
    .                               A                       B
    4 years ago    =        3                        5
    4 years after  =        5                        7
    Difference     =        2                        2
    2=8 (4 ago + 4 hence)
    1=4
    present age A= 3*4 + 4=16
    B=5*4 +4=24
    16/24=2:3
  10. The average age of a couple at the time of their marriage was 22. Two years after the marriage their child was born. Now he is 4 years old. Find the average age of their present age.
    A) 24 years
    B) 22 years
    C) 18 years
    D) 20 years
    E) None of these
    View Answer
    Option D
    Solution
    :
    Sum of couples age at time of marriage=2*22=44
    when son was born, total age=44+2+2=48
    After 4 years total age=48+4+4+4=60
    avg=60/3=20

 

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3 Thoughts to “Quantitative Aptitude: Problems on Ages Set 4”

  1. sachin shukla@ my turn 2017

    ty

  2. Ati

    thanku mam 🙂

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