# Quantitative Aptitude: Problems on Ages Set 7

Problem on Ages Bank PO Questions for SBI PO, IBPS PO, NIACL, NICL, LIC, Dena Bank PO PGDBF, BOI, Bank of Baroda and other competitive exams

1. Father is aged three times more than his son Arun. After 8 years, he would be two and a half times of Arun’s age. After further 8 years, how many times would he be of Arun’s age?
A) 2 1/2
B) 2
C) 3
D) 3 1/2
E) None
Option B
Solution:

Let Arun’s present age be x years. Then, father’s present age =(x + 3 x) years = 4x years.
Then (4x+8)=5/2(x+8)
8x+16=5x+40
3x=24
X=8.
Required ratio, (4x+16)/(x+16) =48/24=2.
2. In a family, a couple has a son and daughter. The age of the father is four times that of his daughter and the age of the son is half of his mother. The wife is ten years younger to her husband and the brother is six years older than his sister. What is the age of the mother?
A) 34
B) 40
C) 38
D) 42
E) None
Option A
Solution:

Let the daughter’s age be x years.
Then, father’s age = 4x.
Mother’s age = 4x – 10; Son’s age = x + 6.
So, x + 6 = (4x-10)/2 ==> x=11.
Therefore Mother’s age = 4X – 10= 44 – 10 = 34 years.
3. Thomasâ€™s present age is three times his sonâ€™s present age and half of his fatherâ€™s present age. The average of the present ages of all of them is 33 1/3 years. What is the difference between the Thomasâ€™s sonâ€™s present age and Thomasâ€™s fatherâ€™s present age?
A) 45
B) 55
C) 50
D) 40
E) None
Option C
Solution:
Present age of Thomasâ€™s son = x years
Thomasâ€™s present age = 3x years
Thomasâ€™s fatherâ€™s present age = 3x*2=6x
X+3x+6x=33 1/3 *3
10x=100/3*3==>x=10
Then diff between Thomas sonâ€™s and fatherâ€™s age is
60-10=50yrs
4. My brother is 3 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 4 years of age when my brother was born, then what was the age of my father when my brother was born?
A) 30
B) 35
C) 40
D) 32
E) None
Option D
Solution:

Father’s age was 28 years when my sister was born.
My sister’s age was 4 years when my brother was born.
Therefore, father’s age was 28+4=32 years when my brother was born.
5. P is as much younger than Q and he is older than R. If the sum of the ages of Q and R is 60 years, what is definitely the difference between Q and P’s age?
A) 4
B) 5
C) 2
D) Canâ€™t be determined
E) None
Option D
Solution:

Canâ€™t be determined
6. If 10 years are subtracted from the present age of Shyam and the remainder is divided by 7, then the present age of his grandson Santhosh is obtained. If Santhosh is 2 years younger to Madan whose age is 7 years, then what is Shyam ‘s present age ?
A) 45
B) 48
C) 36
D) 35
E) None
Option A
Solution:

Santhosh’s age = (7 – 2) years = 5 years.
Let Shyam’s age be x years.
Then (x-10)/7 =5
X=45yrs.
7. Aâ€™s age Is 120% of what it was 15 years ago, But 75 % of what it will be after 15 years. What is his present age?
A) 50
B) 45
C) 65
D) 56
E) None
Option C
Solution:

120% of (x-15)=75% of (x+15)
6/5*(x-15) = 3/4 *(x+15)
8x *(x-15) =5x *(x+15)
3x =195
x=65.
8. The ratio of the ages of M and N is 6 : 5. The total of their ages is 7.7 decades. The proportion of their ages after 1.5 decades will be [1 Decade = 10 years]
A) 43:55
B) 50:57
C) 44:47
D) 57:50
E) None
Option D
Solution:

(6+5)11x =77
x=7
Mâ€™s age = 42 years
and Nâ€™s age = 35 years
Proportion of their ages after 15 is = (42 + 15) : (35 + 15)
= 57 : 50
9. The average age of a group of 10 students is 20 years. When 5 more students join the group, the average age increase by 2 year. The average age of the new students is?
A) 24
B) 26
C) 25
D) 28
E) None
Option B
Solution:

Total age of 10 students = (10*20) 200
Total age of 15 students = (15*22) 330
Total age of 5 new students = 330 – 200 = 130 years
Then average age of 5 new students = 130/5= 26 years
10. The average age of a couple was 26 years at the time of marriage. After 11 years of marriage, the average age of the family with 3 children become 19 years. The average age of the children is
A) 8
B) 6
C) 10
D) 7
E) None
Option D
Solution:

The average age of a couple = 26 years.
Total age of couples = 26 x 2 = 52 years
Total age of couple after 11 years = (52 + 2 * 11 ) = 74 years
If average age of 3 children after 11 years is 3x years.
(74+3x)/5=19
X=7
The average age of children is 7 years.

## 3 Thoughts to “Quantitative Aptitude: Problems on Ages Set 7”

1. karthik

thanks

2. NiL A sTRugGLeR @@==

Statements:
All papers are books.
All pencils are pens.
No paper is pencil.
No stationary is book.

Conclusion:
Some papers can be stationary.
Some pens can be books as well as papers.

plz…..explain that

1. Anonymous

only 2