- The present age of A and B are 29 and 32 years respectively, after how many years ratio of ages of B and A becomes 14 : 13 ?
5 years8 years12 years10 years14 yearsOption D

Let after x years ratio of ages of A and B becomes 13 : 14

29 + x/32 + x = 13/14

x = 10 years. - The ratio of present ages of A and B is 3 : 2 and ratio of present ages of C and B is 5 : 4. If total present age of A, B and C is 120 years then, what the age of B before 6 years.
2818322926Option E

Ratio of age A and B = 3 : 2

ratio of B and C = 4 : 5

A : B : C = 6 : 4 : 5

Let total ages of A, B and C = 15x

15x = 120

x = 8

present age of B = 8 * 4 = 32 years.

before 5 years age of B = 32 – 5 = 26 years. - The ratio of present age of Papu and Sipu is 4 : 5. The ratio of age of Papu after 4 years and Sipu before 8 years is 9 : 8, then find the age of Papu after 14 years.
45 years35 years28 years46 years52 yearsOption D

Let present age of Papu and Sipu are 4x and 5x respectively.

4x + 4/5x – 8 = 9/8

45x – 72 = 32x + 32

13x = 104

x = 8

the age of Papu after 14 years = 4x + 14 = 46 years - The present age of father is two times more than the present age of son. If after 6 years the ratio of age of father and son is 7 : 3, then find the age of son after 5 years.
1518172028Option C

Let present age of son = x

present age of father = 3x

3x + 6/ x + 6 = 7/3

9x + 18 = 7x + 42

x = 12

age of son after 5 years = 12 + 5 = 17 years. - The age of brother is four times of his sister and after 18 years the ratio of age of brother and sister is 2 : 1. What is age of brother after 4 years ?
2028464052Option D

Let the age of sister = x

the age of brother = 4x

4x + 18/x + 18 = 2/1

4x + 18 = 2x + 36

2x = 18

x = 9

The age of brother after 4 years = 4x + 4 = 40 years. - A is as much younger to B as he is elder to C and the sum of the age of B and C is 52 years, then what is the age of A ?
1417282326Option E

Total age of B and C = 52

B – A = A – C

2A = B + C

2A = 52

A = 26 years. - The ratio of the present age of A and B is 8 : 5. If the A’s present age is 5 years more than B’s age after 10 years, then what is the sum of age A and B after 5 years ?
8075606482Option B

Let present age of A and B are 8x and 5x respectively.

8x – (5x + 10) = 5

8x – 5x – 10 = 5

3x = 15

x = 5

age of A after 5 years = 8x + 5 = 45

age of B after 5 years = 5x + 5 = 30

sum = 45 + 30 = 75 years. - The ratio between the present ages of A and B is 5 : 6. If the ratio between the one – third age of A and half that of B is 5 : 9, then what is the present age of A ?
45386254can not determined.Option E

Let the present age of A and B are 5x and 6x respectively.

(5x/3)/(6x/2) = 5/9

5x/3 * 9 = 6x/2 * 5

Here, we can not calculate the present age of A. - Two years ago, the age of mother was four times as old as her daughter. After four years, difference between the age of mother and the age of daughter is 18 years. Find the age of mother after 8 years.
3834425648Option B

Two years ago let age of daughter = x

age of mother = 4x

present age of mother and daughter = (4x + 2), (x + 2)

After 4 years, the age of mother = 4x + 2 + 4 = 4x + 6

the age of daughter = x + 2 + 4 = x + 6

difference = 20

4x + 6 – (x + 6) = 18

4x + 6 – x – 6 = 18

3x = 18

x = 6

the age of mother after 8 years = 4x + 2 + 8 = 24 + 10 = 34 years. - The ratio between the present ages of P and Q is 4 : 5. If the ratio between their ages 4 years hence, becomes 14 : 17. What is Q’s age of present ?
4530325726Option B

Let present age of P and Q are 4x and 5x respectively.

4x + 4/5x + 4 = 14/17

70x + 56 = 68x + 68

2x = 12

x = 6

Q’s present age = 5x = 30 years.

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