- Average age of A and B is 5 years more than the present age of C. The age of D is 3 years less than the age of C and total age of A, B, C and D is 39 years. Find the sum of age of A and B.
2628322420Option A

Let the age of C =x years

ATQ, A+B/2 =x+5

A+B =2x+10

age of D =x-3

Total age of A, B, C and D =39 years.

2x+10+x+x-3 =39

4x+7= 39

x= 8years

The sum of ages of A and B =2x+10 =26 years - Ratio of the present age of Deepak and Subham is 5:8. After 4 years ratio of their ages is 2:3, then find the age of Subham after 8 years.
4548403035Option C

Let the present age of Deepak and Subham be 5x and 8x respectively.

ATQ, 5x+4/8x+4 =2/3

16x+8 =15x+12

x=4

age of Subham after 8 years = 8x+8 =40 years. - The age of Vicky is 25% more than the age of Vikram. The age of Rashmi is 6 years more than the age of Vikram and difference between the age of Vicky and Rashmi is 2 years. What is the age of Vicky after 4 years ?
4042323544Option E

let the age of Vicky=5x

and the age of Vikram=4x

the age of Rashmi=4x+6

difference between the age of Vicky and Rashmi=2 years

5x-(4x+6)=2

5x-4x-6=2

x=8 years

Vicky after 4 years=5x+4=44 years - The average of the present age of mother and his son is 50% more than the present age of the son. If 5 years hence the sum of age of mother and his son is 70 years, then find the present age of the mother.
4048303545Option A

let the present age of mother and son be x and y years respectively

x+y/2=150/100x

x+y/2=3x/2

y=2x

also given that, x+5+2x+5=70

3x+10=70

x=20 years

present age of mother=y=2x=2*20=40 years - Average age of B and C is 20 years. The age of A is 4 years more than B and total age of A,B and C is 60 years, then find the age of A before 4 years.
2018151624Option D

average age of B and C=20 years

B+C/2=20

B+C=40

let the age of B=x

age of C=40-x

age of A=x+4

x+4+x+40-x=60

x+44=60

x=16

age of A before 4 years=x+4-2=16+4-4=16 years - Average of present age of P & Q is 24 years, average of present age of P & R is 20 years and average of present of Q & R is 16 years. Find the age of R after 8 years.
1820252824Option B

average of present age of P & Q=24

P+Q/2=24

P+Q=48

average of present age of P & R=20

P+R/2=20

P+R=40

average of present age of Q & R=16

Q+R/2=16

Q+R=32

P+Q+P+R+Q+R=48+40+32

2(P+Q+R)=120

P+Q+R=60

P+Q=48

R=60-48=12

the age of R after 8 years=12+8=20 years - Present age of son is 30% of his father age and after 5 years the ratio of age of father and son will become 5:2. What is the sum of the present age of father and son ?
4845383940Option D

let present age of father=10x

and present age of son=3x

after 5 years, 10x+5/3x+5=5/2

20x+10=15x+25

5x=15

x=3

sum=10x+3x=13x=13*3=39 years - A is 3 years older than B and after 2 years age of A will be 30 % more than that of B. Find the age of A after 5 years.
1620252428Option A

let age of B=x

and age of A=x+3

after 2 years, x+3+2=130/100(x+2)

x+5=13/10(x+2)

10x+50=13x+26

3x=24

x=8

age of A after 5 years =x+3+5=8+3+5=16 years - 5 years ago, average age of a family of 6 members was 30 years. At present one family member who is a girl got married whose age is 30 years. What is the average age of remaining 5 members of family after 4 years ?
2520242826Option B

5 years ago, average age of 6 members=30 years

at present total age of 6 members=(30*6)+(6*5)=210

one member got married who is a girl whose age is 30 years

remaining age of 5 members=180

after 4 years total age of 5 members =180+(5*4)=100

average age of 5 members after 4 years=100/5=20 years - Ratio of present age of P & Q is 4:3 and before 2 years ratio of their age is 3:2. The age of R is 12 years more than the present age of P, then find the age of R.
2520241840Option B

let present age of P & Q be 4x and 3x respectively

before 2 years, 4x-2/3x-2=3/2

8x-4=9x-6

x=2

present age pf P=4x=4*2=8

present age of R=8+12=20 years