Average age of A and B is 5 years more than the present age of C. The age of D is 3 years less than the age of C and total age of A, B, C and D is 39 years. Find the sum of age of A and B.
26
28
32
24
20
Option A Let the age of C =x years ATQ, A+B/2 =x+5 A+B =2x+10 age of D =x-3 Total age of A, B, C and D =39 years. 2x+10+x+x-3 =39 4x+7= 39 x= 8years The sum of ages of A and B =2x+10 =26 years
Ratio of the present age of Deepak and Subham is 5:8. After 4 years ratio of their ages is 2:3, then find the age of Subham after 8 years.
45
48
40
30
35
Option C Let the present age of Deepak and Subham be 5x and 8x respectively. ATQ, 5x+4/8x+4 =2/3 16x+8 =15x+12 x=4 age of Subham after 8 years = 8x+8 =40 years.
The age of Vicky is 25% more than the age of Vikram. The age of Rashmi is 6 years more than the age of Vikram and difference between the age of Vicky and Rashmi is 2 years. What is the age of Vicky after 4 years ?
40
42
32
35
44
Option E let the age of Vicky=5x and the age of Vikram=4x the age of Rashmi=4x+6 difference between the age of Vicky and Rashmi=2 years 5x-(4x+6)=2 5x-4x-6=2 x=8 years Vicky after 4 years=5x+4=44 years
The average of the present age of mother and his son is 50% more than the present age of the son. If 5 years hence the sum of age of mother and his son is 70 years, then find the present age of the mother.
40
48
30
35
45
Option A let the present age of mother and son be x and y years respectively x+y/2=150/100x x+y/2=3x/2 y=2x also given that, x+5+2x+5=70 3x+10=70 x=20 years present age of mother=y=2x=2*20=40 years
Average age of B and C is 20 years. The age of A is 4 years more than B and total age of A,B and C is 60 years, then find the age of A before 4 years.
20
18
15
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24
Option D average age of B and C=20 years B+C/2=20 B+C=40 let the age of B=x age of C=40-x age of A=x+4 x+4+x+40-x=60 x+44=60 x=16 age of A before 4 years=x+4-2=16+4-4=16 years
Average of present age of P & Q is 24 years, average of present age of P & R is 20 years and average of present of Q & R is 16 years. Find the age of R after 8 years.
18
20
25
28
24
Option B average of present age of P & Q=24 P+Q/2=24 P+Q=48 average of present age of P & R=20 P+R/2=20 P+R=40 average of present age of Q & R=16 Q+R/2=16 Q+R=32 P+Q+P+R+Q+R=48+40+32 2(P+Q+R)=120 P+Q+R=60 P+Q=48 R=60-48=12 the age of R after 8 years=12+8=20 years
Present age of son is 30% of his father age and after 5 years the ratio of age of father and son will become 5:2. What is the sum of the present age of father and son ?
48
45
38
39
40
Option D let present age of father=10x and present age of son=3x after 5 years, 10x+5/3x+5=5/2 20x+10=15x+25 5x=15 x=3 sum=10x+3x=13x=13*3=39 years
A is 3 years older than B and after 2 years age of A will be 30 % more than that of B. Find the age of A after 5 years.
16
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28
Option A let age of B=x and age of A=x+3 after 2 years, x+3+2=130/100(x+2) x+5=13/10(x+2) 10x+50=13x+26 3x=24 x=8 age of A after 5 years =x+3+5=8+3+5=16 years
5 years ago, average age of a family of 6 members was 30 years. At present one family member who is a girl got married whose age is 30 years. What is the average age of remaining 5 members of family after 4 years ?
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26
Option B 5 years ago, average age of 6 members=30 years at present total age of 6 members=(30*6)+(6*5)=210 one member got married who is a girl whose age is 30 years remaining age of 5 members=180 after 4 years total age of 5 members =180+(5*4)=100 average age of 5 members after 4 years=100/5=20 years
Ratio of present age of P & Q is 4:3 and before 2 years ratio of their age is 3:2. The age of R is 12 years more than the present age of P, then find the age of R.
25
20
24
18
40
Option B let present age of P & Q be 4x and 3x respectively before 2 years, 4x-2/3x-2=3/2 8x-4=9x-6 x=2 present age pf P=4x=4*2=8 present age of R=8+12=20 years