# Quantitative Aptitude: Problems on Ages Set 21

1. Average age of A and B is 5 years more than the present age of C. The age of D is 3 years less than the age of C and total age of A, B, C and D is 39 years. Find the sum of age of A and B.
26
28
32
24
20
Option A
Let the age of C =x years
ATQ, A+B/2 =x+5
A+B =2x+10
age of D =x-3
Total age of A, B, C and D =39 years.
2x+10+x+x-3 =39
4x+7= 39
x= 8years
The sum of ages of A and B =2x+10 =26 years

2. Ratio of the present age of Deepak and Subham is 5:8. After 4 years ratio of their ages is 2:3, then find the age of Subham after 8 years.
45
48
40
30
35
Option C
Let the present age of Deepak and Subham be 5x and 8x respectively.
ATQ, 5x+4/8x+4 =2/3
16x+8 =15x+12
x=4
age of Subham after 8 years = 8x+8 =40 years.

3. The age of Vicky is 25% more than the age of Vikram. The age of Rashmi is 6 years more than the age of Vikram and difference between the age of Vicky and Rashmi is 2 years. What is the age of Vicky after 4 years ?
40
42
32
35
44
Option E
let the age of Vicky=5x
and the age of Vikram=4x
the age of Rashmi=4x+6
difference between the age of Vicky and Rashmi=2 years
5x-(4x+6)=2
5x-4x-6=2
x=8 years
Vicky after 4 years=5x+4=44 years

4. The average of the present age of mother and his son is 50% more than the present age of the son. If 5 years hence the sum of age of mother and his son is 70 years, then find the present age of the mother.
40
48
30
35
45
Option A
let the present age of mother and son be x and y years respectively
x+y/2=150/100x
x+y/2=3x/2
y=2x
also given that, x+5+2x+5=70
3x+10=70
x=20 years
present age of mother=y=2x=2*20=40 years

5. Average age of B and C is 20 years. The age of A is 4 years more than B and total age of A,B and C is 60 years, then find the age of A before 4 years.
20
18
15
16
24
Option D
average age of B and C=20 years
B+C/2=20
B+C=40
let the age of B=x
age of C=40-x
age of A=x+4
x+4+x+40-x=60
x+44=60
x=16
age of A before 4 years=x+4-2=16+4-4=16 years

6. Average of present age of P & Q is 24 years, average of present age of P & R is 20 years and average of present of Q & R is 16 years. Find the age of R after 8 years.
18
20
25
28
24
Option B
average of present age of P & Q=24
P+Q/2=24
P+Q=48
average of present age of P & R=20
P+R/2=20
P+R=40
average of present age of Q & R=16
Q+R/2=16
Q+R=32
P+Q+P+R+Q+R=48+40+32
2(P+Q+R)=120
P+Q+R=60
P+Q=48
R=60-48=12
the age of R after 8 years=12+8=20 years

7. Present age of son is 30% of his father age and after 5 years the ratio of age of father and son will become 5:2. What is the sum of the present age of father and son ?
48
45
38
39
40
Option D
let present age of father=10x
and present age of son=3x
after 5 years, 10x+5/3x+5=5/2
20x+10=15x+25
5x=15
x=3
sum=10x+3x=13x=13*3=39 years

8. A is 3 years older than B and after 2 years age of A will be 30 % more than that of B. Find the age of A after 5 years.
16
20
25
24
28
Option A
let age of B=x
and age of A=x+3
after 2 years, x+3+2=130/100(x+2)
x+5=13/10(x+2)
10x+50=13x+26
3x=24
x=8
age of A after 5 years =x+3+5=8+3+5=16 years

9. 5 years ago, average age of a family of 6 members was 30 years. At present one family member who is a girl got married whose age is 30 years. What is the average age of remaining 5 members of family after 4 years ?
25
20
24
28
26
Option B
5 years ago, average age of 6 members=30 years
at present total age of 6 members=(30*6)+(6*5)=210
one member got married who is a girl whose age is 30 years
remaining age of 5 members=180
after 4 years total age of 5 members =180+(5*4)=100
average age of 5 members after 4 years=100/5=20 years

10. Ratio of present age of P & Q is 4:3 and before 2 years ratio of their age is 3:2. The age of R is 12 years more than the present age of P, then find the age of R.
25
20
24
18
40
Option B
let present age of P & Q be 4x and 3x respectively
before 2 years, 4x-2/3x-2=3/2
8x-4=9x-6
x=2
present age pf P=4x=4*2=8
present age of R=8+12=20 years