Quantitative Aptitude: Problems on Ages Set 21

  1. Average age of A and B is 5 years more than the present age of C. The age of D is 3 years less than the age of C and total age of A, B, C and D is 39 years. Find the sum of age of A and B.
    26
    28
    32
    24
    20
    Option A
    Let the age of C =x years
    ATQ, A+B/2 =x+5
    A+B =2x+10
    age of D =x-3
    Total age of A, B, C and D =39 years.
    2x+10+x+x-3 =39
    4x+7= 39
    x= 8years
    The sum of ages of A and B =2x+10 =26 years

     

  2. Ratio of the present age of Deepak and Subham is 5:8. After 4 years ratio of their ages is 2:3, then find the age of Subham after 8 years.
    45
    48
    40
    30
    35
    Option C
    Let the present age of Deepak and Subham be 5x and 8x respectively.
    ATQ, 5x+4/8x+4 =2/3
    16x+8 =15x+12
    x=4
    age of Subham after 8 years = 8x+8 =40 years.

     

  3. The age of Vicky is 25% more than the age of Vikram. The age of Rashmi is 6 years more than the age of Vikram and difference between the age of Vicky and Rashmi is 2 years. What is the age of Vicky after 4 years ?
    40
    42
    32
    35
    44
    Option E
    let the age of Vicky=5x
    and the age of Vikram=4x
    the age of Rashmi=4x+6
    difference between the age of Vicky and Rashmi=2 years
    5x-(4x+6)=2
    5x-4x-6=2
    x=8 years
    Vicky after 4 years=5x+4=44 years

     

  4. The average of the present age of mother and his son is 50% more than the present age of the son. If 5 years hence the sum of age of mother and his son is 70 years, then find the present age of the mother.
    40
    48
    30
    35
    45
    Option A
    let the present age of mother and son be x and y years respectively
    x+y/2=150/100x
    x+y/2=3x/2
    y=2x
    also given that, x+5+2x+5=70
    3x+10=70
    x=20 years
    present age of mother=y=2x=2*20=40 years

     

  5. Average age of B and C is 20 years. The age of A is 4 years more than B and total age of A,B and C is 60 years, then find the age of A before 4 years.
    20
    18
    15
    16
    24
    Option D
    average age of B and C=20 years
    B+C/2=20
    B+C=40
    let the age of B=x
    age of C=40-x
    age of A=x+4
    x+4+x+40-x=60
    x+44=60
    x=16
    age of A before 4 years=x+4-2=16+4-4=16 years

     

  6. Average of present age of P & Q is 24 years, average of present age of P & R is 20 years and average of present of Q & R is 16 years. Find the age of R after 8 years.
    18
    20
    25
    28
    24
    Option B
    average of present age of P & Q=24
    P+Q/2=24
    P+Q=48
    average of present age of P & R=20
    P+R/2=20
    P+R=40
    average of present age of Q & R=16
    Q+R/2=16
    Q+R=32
    P+Q+P+R+Q+R=48+40+32
    2(P+Q+R)=120
    P+Q+R=60
    P+Q=48
    R=60-48=12
    the age of R after 8 years=12+8=20 years

     

  7. Present age of son is 30% of his father age and after 5 years the ratio of age of father and son will become 5:2. What is the sum of the present age of father and son ?
    48
    45
    38
    39
    40
    Option D
    let present age of father=10x
    and present age of son=3x
    after 5 years, 10x+5/3x+5=5/2
    20x+10=15x+25
    5x=15
    x=3
    sum=10x+3x=13x=13*3=39 years

     

  8. A is 3 years older than B and after 2 years age of A will be 30 % more than that of B. Find the age of A after 5 years.
    16
    20
    25
    24
    28
    Option A
    let age of B=x
    and age of A=x+3
    after 2 years, x+3+2=130/100(x+2)
    x+5=13/10(x+2)
    10x+50=13x+26
    3x=24
    x=8
    age of A after 5 years =x+3+5=8+3+5=16 years

     

  9. 5 years ago, average age of a family of 6 members was 30 years. At present one family member who is a girl got married whose age is 30 years. What is the average age of remaining 5 members of family after 4 years ?
    25
    20
    24
    28
    26
    Option B
    5 years ago, average age of 6 members=30 years
    at present total age of 6 members=(30*6)+(6*5)=210
    one member got married who is a girl whose age is 30 years
    remaining age of 5 members=180
    after 4 years total age of 5 members =180+(5*4)=100
    average age of 5 members after 4 years=100/5=20 years

     

  10. Ratio of present age of P & Q is 4:3 and before 2 years ratio of their age is 3:2. The age of R is 12 years more than the present age of P, then find the age of R.
    25
    20
    24
    18
    40
    Option B
    let present age of P & Q be 4x and 3x respectively
    before 2 years, 4x-2/3x-2=3/2
    8x-4=9x-6
    x=2
    present age pf P=4x=4*2=8
    present age of R=8+12=20 years

     

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