# Quantitative Aptitude: Profit and Loss Set 7

1. Raman calculates his profit % on the selling price whereas Rajeev calculates his on the cost price. They find that the difference of their profits Rs.150. If the selling price of both the m are the same and both of them get 50% profit. Find their selling price.
A) Rs. 620
B) Rs. 900
C) Rs.870
D) Rs.750
E) Rs.550
Option B
Solution:
selling price = [Diff. * 100 * (100 + 50)]/(50)^2
=  [150 * 100 * 150 ]/ 2500 = 900
2. A trader has 600kgs of rice ,  a part of which he sells at 15% profit and the remaining quantity at 20% loss. On the whole , he incurs an overall loss of 6% .What is the quantity of rice he sold at 20% loss?
A) 300kg
B) 410kg
C) 360kg
D) 210kg
E) 500kg
Option C
Solution:
Quantity  of rice sold at 20% loss = x kg (let)
Quantity of rice sold at 15% gain  = (600 – x ) kg
(600 – x) * (115/100) + (x*80)/100 = (600 * 94)/100
=> x = 12600/35 = 360 kg
3. A camel and a cart together cost Rs. 5000.If  by selling the camel at a profit of 10% and the cart at a loss of 10% a total profit of 2.5% is made ,then what is the cost price of the camel ?
A) Rs.4500
B) Rs. 3125
C) Rs. 3000
D) Rs.2100
E) Rs.3800
Option B
Solution:
Let the cp of the camel and the cart be x and (8000-x) resp.
sp of camel = 1.1x
sp of cart = 0.9(5000-x)
Therefore ,
1.1x * 0.9(5000 – x) = 5000 * 1.025
=> x = Rs. 3125
4. If there is a loss of  40% when a good is sold at (2/5)th of its earlier selling price. Find the profit%  after selling the good at a certain price.
A) 24.15%
B) 31.3%
C) 47%
D 35%
E) 50%
Option E
Solution:
CP = (2/3) of SP
SP = (100+P) / 100 of CP
Equating both the above equations,
Profit = 50%
5. There are two watches of cost Rs. 800. One is sold at a profit of 16% and the other at a loss of 8%. If there is no loss  or no gain in the whole transaction, the cost price of the watch on which the shopkeeper gains is?
A) Rs. 400
B) Rs.740
C) Rs.504
D) Rs.450
E) Rs.645
Option  A
Solution:
profit …………….loss
+16 …………….. -8
———–0
8……………16
1 : 2
Therefore ,
price of watch sold at profit = (1/2) * 800 =  Rs. 400
price of watch sold at loss = 2 * 800 = Rs. 1600
6. Niel bought 30kg rice at the rate of Rs.9.50/kg and 40kg of rice at the rate of Rs. 8.50/kg and mixed them. She told the mixture at the rate of Rs. 8.90/kg. Find the total profit or loss in the whole transaction.
A) Rs.4 profit
B) Rs.2 loss
C) Rs.2 profit
D) Rs.4 loss
E) None of these
Option B
Solution:
Total CP = 30 *9.50 + 40 * 8.50 =625
Total SP = 8.9(30+40) =623
Loss = Rs.2
7. If a shopkeeper sell a TV at 15% profit and a DVD at 12% loss then he earns Rs. 540 as total profit but if he sells the TV at 12% loss and the DVD at 15% proft then there is no loss or profit.Find the price of the TV and the DVD ?
A) Rs.11,000 and Rs. 2000
B) Rs.15,000 and Rs. 3000
C) Rs.11,000 and Rs. 6000
D) Rs.10,000 and Rs.8000
E) Rs.17,000 and Rs. 4000
Option D
Solution:
.             TV ……………… DVD
CP—–500…………….400
SP—–+15%…………   -12%
P = 75……………  L = -48
Total profit  = 75 – 48 = Rs. 27
27 *20 = Rs. 540
CP of TV = 500 * 20 = Rs . 10,000
CP of DVD = 400 * 20 = Rs. 8000
8. A cloth merchant uses 120cm scale while buying,instead a meter scale ,but uses an 80 cm scale while selling the same cloth. If he offers a discount of 20% on cash payment. Find the profit percent.
A) 40%
B) 35%
C) 20%
D) 15%
E) 30%
Option C
Solution:
After discount = (80 * 120)/100 = 96
Profit = 96 – 80 = 16
Therefore , Profit% = (16*100)/80 = 20%
9. An article is marked 50% over its cost price.Two successive discounts of 12% and 13(1/2)% are allowed on the marked price of the article.Find the profit or loss percent after selling at discount.
A) 8%
B) 10%
C) 13%
D) 14.18%
E) 7.4%
Option D
Solution:
Let the CP be Rs. 100
SP = 150 * (88/100) * (86.5/100) = Rs. 114.18
Therefore ,
= (14.18/100)*100 =14.18%
10. A trader marked his goods at such a price that after allowing a discount of 12(1/2) % for cash payment, he makes a profit of 20% . What is the marked price of the good which costs Rs. 210 ?
A) Rs.300
B) Rs.210
C) Rs.470
D) Rs. 288
E) Rs.200
Option D
Solution:
Required MP = [210 * (100+20)]/(100-12.5) = (210 *120)/87.5 = Rs. 288

## 24 Thoughts to “Quantitative Aptitude: Profit and Loss Set 7”

1. Bagad_Billa

In Ques 5 it should be 2:3 not 1:2

1. cActi

now check ..

2. Sneha

Ques. 5 pls clear … Ans I think wrong

1. cActi

yes…
check again ..

2. thinker

I also think wrong

3. Sneha

Ques. 10th me apne 200 cp diya hai… Ans me 210 liya hai

1. Bagad_Billa

Yes it has also mistake

1. cActi

refresh the page ..

2. cActi

yes done …ab check karo ..

1. In the END

Q.8. Please successive method diye koro na amar asche na. :/

1. \$~\$PrAdeEP\$K\$~\$~\$

by successive method…:)
cp—————-sp
100————120 => p(1)% =20%
now again
cp—————sp
80————–100 =>p(2) =25%
now he also gives discount of 20%
so net profit on selling =p(n) =25-20-5 =0%
now totl profit on whole process=>
p(t) =20%+0%+(20*0)/100 =20%

1. In the END

4. thinker

Question 7 explain Kr do koi plz

1. \$~\$PrAdeEP\$K\$~\$~\$

cp———–p/l——-sp
+20———+3——+23
+25———(-3)—–+22
now make sp equal
=>100——-+15——-115
100——-(-12)——88
now 3 ratio =540 => 100 ratio =cp(t) =18000
now by alligation v hav
-12%——————-+15%
————-0%————
15%———————12% => ratio =5:4
now cp(1) =5/9*18000=10000
& cp(2) =4/9*18000=8000

1. thinker

Thanks

5. Jellyfish

7/10 ty az

6. Oliver Queen

7. IBPS RRB PO-2018

Q.2 115 80
94
14 21
2:3
3/5*600=360 Ans

8. jaga

Q1 samjha do koi

1. cActi

kya problm h ?

1. jaga

Samjh mai nahi ata ..koi alag method hai to bata diyo

1. Dream BIG :))Pappa's Dream❤

Raman on sp……..rajeev on cp..
Sp is same for both..nd profit is 50%..diffrnce of profit is 150
Find s.p.
Now profit % is 50/100 means in 1st case whn ranan calculate profit on sp.
Means 100 is s.p nd profit is 50.
Means c.p is 50.
Now 2nd case whn rajeev calculate on c.p means 100 is c.p ..nd 50 is profit ..so s.p is 150
Means 1st case s.p 100 ..nd case s.p 150..humko equal krna hai..
S.p 100×3 s.p 150×2
Profit 50×3 c.p 100×2
C.p 50×3 p 50×2
150 – 100…….=150
Means 150/50 = 3
3×300=900

2. ron(honey)..

let jisne cp pe profit calculate kia hai his cp=100x ..now 50% profit so his sp=150x..as sp of both the persons r same so nd he calculate prof on sp so 150x his prof =75x ..now diff in prof=25x=150 ..150x=sp =150*6=900

9. Dream BIG :))Pappa's Dream❤

Ty az :))