**Quadratic Equation Questions** for IBPS PO/RRB, SBI, RBI, NICL, NIACL, LIC, UIIC, OICL, Bank of Baroda and other competitive exams.

**Directions:** In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-

- I. 2x
^{2}– 21x – 55 = 0

II. 3y^{2}– 14y – 5 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption C

Solution:

x = 5, 11/2

y = -1/3, 5

Put all values on number line and analyze the relationship

-1/3………5……..11/2 - I. 3x
^{2}– 13x + 14 = 0

II. 3y^{2}– 19y + 28 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption D

Solution:

x = 2, 7/3

y = 7/3, 4

Put all values on number line and analyze the relationship

2………..7/3……4 - I. 3x
^{2}+ 2x – 21 = 0

II. 3y^{2}– 13y + 14 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption E

Solution:

x = -3, 7/3

y = 2, 7/3

Put all values on number line and analyze the relationship

-3………..2……7/3 - I. 3x
^{2}– 11x – 4 = 0

II. 3y^{2}+ 14y + 16 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption A

Solution:

x = -1/3, 4

y = -8/3, -2

Put all values on number line and analyze the relationship

-8/3………..-2……6 - I. 3x
^{2}– 8x + 4 = 0

II. 3y^{2}– 19y + 30 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption B

Solution:

x = 2/3, 2

y = 3, 10/3

Put all values on number line and analyze the relationship

2/3……2……..3……10/3 - I. 3x
^{2}– 11x + 6 = 0

II. 3y^{2}– 16y + 20 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption E

Solution:

x = 2/3, 3

y = 2, 10/3

Put all values on number line and analyze the relationship

2/3……2……..3……10/3 - I. 3x
^{2}– 4x – 32 = 0

II. 3y^{2}+ 14y + 16 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption E

Solution:

x = -8/3, 4

y = -8/3, -2

Put all values on number line and analyze the relationship

-8/3………..-2……….4 - I. 2x
^{2}+ 13x + 20 = 0

II. 2y^{2}+ 5y – 12 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption E

Solution:

x = -4, -5/2

y = -4, 3/2

Put all values on number line and analyze the relationship

-4……….-5/2……..3/2 - I. 3x
^{2}– 17x + 20 = 0

II. 3y^{2}+ y – 10 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption C

Solution:

x = 5/3, 4

y = -2, 5/3

Put all values on number line and analyze the relationship

-2………5/3……..4 - I. 4x
^{2}– 15x + 9 = 0

II. 2y^{2}– 13y + 21 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption D

Solution:

x = 3, 7/2

y = 3/4, 3

Put all values on number line and analyze the relationship

3/4………..3……..7/2

Madam , question no. 1 in wrong. please maintain the dignity as you provide good set of question.

QUES NO 1 AS PER SIGN RULE…AND OTHERWISE ALSO IS NOT CORRECT …..PLEASE MAKE CORRECTION…THANK YOU TEAM az

ty AZ