**Directions: In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-**

- I. 3x
^{2}– 25x + 52 = 0

II. 3y^{2}– 17y + 20= 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption

x = y = - I. 3x
^{2}– 14x + 15 = 0

II. 3y^{2}– 20y + 25= 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption

x = y = - I. 3x
^{2}+ 16x + 20= 0

II. 3y^{2}– 2y – 40 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption

x = y = - I. 3x
^{2}+ 5x – 50= 0

II. 3y^{2}– 22y + 40= 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption

x = y = - I. 2x
^{2}– 13x + 20= 0

II. 2y^{2}+ 7y – 15 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption

x = y = - I. 2x
^{2}– 7x – 15= 0

II. 2y^{2}+ 17y + 30= 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption

x = y = - I. 2x
^{2}– 7x – 49 = 0

II. 2y^{2}+ 17y + 35= 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption

x = y = - I. 2x
^{2}+ 15x + 27= 0

II. 3y^{2}+ 4y – 15 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption

x = y = - I. 2x
^{2}+ 15x + 18 = 0

II. 2y^{2}– 5y – 25 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption

x = y = - I. 3x
^{2}+ 11x – 20 = 0

II. 2y^{2}– 17y + 35 = 0If x > yIf x < yIf x ≥ yIf x ≤ yIf x = y or relation cannot be establishedOption

x = y =