 # Quantitative Aptitude: Quadratic Equations Set 11

Directions: In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-

1. I. 3x2 – 8x + 4 = 0
II. 3y2 – 16y + 16 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
Option E
Solution:

3x2 – 8x + 4 = 0
3x2 – 2x – 6x + 4 = 0
Gives x = 2, 2/3
3y2 – 16y + 16 = 0
3y2 – 12y – 4y + 16 = 0
Gives y = 4, 4/3
2. I. 3x2 + 10x + 7 = 0
II. 2y2 – 5y – 12 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
Option E
Solution:

3x2 + 10x + 7 = 0
3x2 + 3x + 7x + 7 = 0
Gives x = -1, -7/3
2y2 – 5y – 12 = 0
2y2 – 8y + 3y – 12 = 0
Gives y = -3/2, 4
3. I. 4x2 + 15x + 9 = 0
II. 4y2 – 13y – 12 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
Option D
Solution:

4x2 + 15x + 9 = 0
4x2 + 12x + 3x + 9 = 0
Gives x = -3, -3/4
4y2 – 13y – 12 = 0
4y2 – 16y + 3y – 12 = 0
Gives y = -3/4, 4
4. I. 3x2 + 23x + 30 = 0
II. 3y2 – 4y – 4 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
Option B
Solution:

3x2 + 23x + 30 = 0
3x2 + 18x + 5x + 30 = 0
Gives x = -5/3, -6
3y2 – 4y – 4 = 0
3y2 – 6y + 2y – 4 = 0
Gives y = 2, -2/3
Put all values on number line and analyze the relationship
-6…. -5/3….. -2/3…… 2
5. I. 5x2 – 36x – 32 = 0,
II. 3y2 – 11y + 6 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
Option E
Solution:

5x2 – 36x – 32 = 0
5x2 + 4x – 40x – 32 = 0
Gives x = -4/5, 8
3y2 – 17y – 6 = 0
3y2 + y – 18y – 6 = 0
Gives y = -1/3, 6
6. I. 4x2 + 17x + 18 = 0,
II. 3y2 + 4y – 4 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
Option D
7. I. 4x2 – 9x – 9 = 0,
II. 4y2 + 11y + 6 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
Option C
8. I. 3x2 – 19x + 28 = 0,
II. 4y2 – 11y + 6 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
Option A
9. I. 3x2 + 19x + 28 = 0,
II. 6y2 – y – 2 = 0A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
Option B

10. I. 3x2 + 7x – 6 = 0,
II. 6y2 – y – 2 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
Option E
Solution:

3x2 + 7x – 6 = 0
3x2 + 9x – 2x – 6 = 0
Gives x = -3, 2/3
6y2 – y – 2 = 0
6y2 + 3y – 4y – 2 = 0
Gives y = -1/2, 2/3

## 29 Thoughts to “Quantitative Aptitude: Quadratic Equations Set 11”

1. Niti

Ans 6 : E hona chahiye ??

2. Niti

1. shreya pnb po

x= -2, -2.25
y= -2 , + .66
if u draw a no. line then -2.25, -2 , 0 .66 hence y >= x

1. Shubhra

Hie. U working as PO already or selected this tym?

1. shreya pnb po

this tym mam

1. Shubhra

Ok. Congrats :))
Now also preparing for any exam?

2. shreya pnb po

thank u mam.. yes nicl ao

3. Shubhra

Ok 🙂

2. Niti

yes got it
ty 🙂 dear

3. •?((¯°·._.• ąʍβɨЌą •._.·°¯))؟•

mam plz check the sol of ques no 1

1. shreya pnb po

e correct 0.66, 1.3, 2,4 if u draw no. line so e option. 1.3 <2<4

1. •?((¯°·._.• ąʍβɨЌą •._.·°¯))؟•

congrats dear :))

1. SM (pnb po)

ty

1. Yogi ji

2. Shubhra

Ans correct hai.
14 y ki jagah 12y h

4. Yogi ji

Mam plz check solution of 7 ques can’t determined bhi ho sakta hai

5. Yogi ji

7 ques x=-2. 2,+3
Y=-0.7,-2
Ne ans hna chaiye

1. Suraj

x= -3/4 and 3
y= -3/4 and -2

so y<=x

1. Yogi ji

-2, – 2.25 Se bda hua

1. Suraj

-2.25 kaha se aaya?

1. Yogi ji

Ha yaar. Health thik nhi. Mind hi kharab ho gya lgta.

2. Yogi ji

Kal bhi mix quiz hga?

3. Suraj

haaaa

4. Yogi ji

Give me link of day 5 syollg role

5. Suraj

http://aspirantszone.com/syllogism-by-rules-shortcut-tricks-for-new-pattern-syllogism/

6. Yogi ji

6. jaga

thank u

7. Ayushi

thanku

8. tanfoglio schusswaffen

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