Directions: In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-
- I. 3x2 – 8x + 4 = 0
II. 3y2 – 16y + 16 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
- I. 3x2 + 10x + 7 = 0
II. 2y2 – 5y – 12 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
- I. 4x2 + 15x + 9 = 0
II. 4y2 – 13y – 12 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
- I. 3x2 + 23x + 30 = 0
II. 3y2 – 4y – 4 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
- I. 5x2 – 36x – 32 = 0,
II. 3y2 – 11y + 6 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
- I. 4x2 + 17x + 18 = 0,
II. 3y2 + 4y – 4 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
- I. 4x2 – 9x – 9 = 0,
II. 4y2 + 11y + 6 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
- I. 3x2 – 19x + 28 = 0,
II. 4y2 – 11y + 6 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
- I. 3x2 + 19x + 28 = 0,
II. 6y2 – y – 2 = 0A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
- I. 3x2 + 7x – 6 = 0,
II. 6y2 – y – 2 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
Ans 6 : E hona chahiye ??
@mod please check ans 6
x= -2, -2.25
y= -2 , + .66
if u draw a no. line then -2.25, -2 , 0 .66 hence y >= x
Hie. U working as PO already or selected this tym?
this tym mam
Ok. Congrats :))
Now also preparing for any exam?
thank u mam.. yes nicl ao
Ok 🙂
yes got it
ty 🙂 dear
mam plz check the sol of ques no 1
e correct 0.66, 1.3, 2,4 if u draw no. line so e option. 1.3 <2<4
congrats dear :))
ty
Ab to mat padh
Ans correct hai.
14 y ki jagah 12y h
Mam plz check solution of 7 ques can’t determined bhi ho sakta hai
7 ques x=-2. 2,+3
Y=-0.7,-2
Ne ans hna chaiye
x= -3/4 and 3
y= -3/4 and -2
so y<=x
-2, – 2.25 Se bda hua
-2.25 kaha se aaya?
Ha yaar. Health thik nhi. Mind hi kharab ho gya lgta.
Kal bhi mix quiz hga?
haaaa
Give me link of day 5 syollg role
http://aspirantszone.com/syllogism-by-rules-shortcut-tricks-for-new-pattern-syllogism/
Link plz
thank u
thanku
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