# Quantitative Aptitude: Ratio and Proportion Questions Set 13

1. The ratio of amount of A and B is 4 : 3 and the ratio of amount of B and C is 4 : 5 . If the total number of amount A , B and C have rs. 3870, then find the how much amount B have ?
1200
2340
1080
880
960
Option C
Ratio of amount of A and B = 4 : 3
ratio of amount of B and C = 4 : 5
By multiplying ‘4’ in ratio of A and B
A : B = (4 : 3) 4 = 16 : 12
By multiplying ‘3’ in ratio of B and C
B : C = (4 : 5) 3 = 12 : 15
A : B : C = 16 : 12 : 15
let amount of A , B and C have = 16x , 12x and 15x
total = 43x
43x = 3870
x = 90
12x = 1080
B have = 1080

2. Rabin has three types of coins i.e 10 paisa , 20 paisa and 50 paisa and total value of this coins is rs. 78. The number of coins is in the ratio of 6 : 4 : 5. Find the number 10 paisa coins.
180
300
120
140
420
Option C
Let the number coins of 10 paisa , 20 paisa and 50 paisa is 6x, 4x and 5x respectively.
(10 * 6x) + (20 * 4x) + (50 * 5x) = rs. 78
60x + 80x + 250x = 78
390x = 7800
x = 20
The number 10 paisa coins = 6 * 20 = 120

3. A sum of amount of rs. 3500 is divided between three friends. The ratio of amount given to P and Q is 2 : 3 and Q and R is 3 : 5. What is difference the amount given to P and R ?
1240
940
480
1050
1280
Option D
Let the amount given to P and Q = 2x and 3x
Q and R = 3x and 5x
total amount = 3500
2x + 3x + 5x = 3500
10x = 3500
x = 350
difference = 5x – 2x = 3x = 3 * 350 = 1050

4. Rohit gave half of his monthly salary to his parents and one-third of remaining salary to his wife and remaining his salary gave to his son and daughter in the ratio of 13 : 12. If his monthly salary is rs.45000, then find how much amount he gave to his son ?
4500
3450
6300
5200
7800
Option E
Rohit gave to his parents = 45000/2 = 22500
remaining salary = 45000 – 22500 = 22500
he gave to his wife = 22500 * 3 = 7500
remaining salary = 22500 – 7500 = 15000
he gave to his son = 15000 * 13/25 = 7800

5. Two numbers are in the ratio of 4 : 3. When we added 60 in each number the ratio becomes 30 : 23. Find the sum of both initial numbers.
1520
2000
1470
3800
2540
Option C
Let two numbers is 4x and 3x
4x + 60 / 3x + 60 = 30/23
92x + 1380 = 90x + 1800
2x = 420
x = 210
total sum = 4x + 3x = 7x = 7 * 210 = 1470

6. The ratio of income of Rahul and Raju in the ratio of 6 : 5 and they saved rs. 1500 each, Their expenditure ratio 9 : 7 , then find what is the sum of their incomes ?
14000
18000
35000
20000
11000
Option E
Let income of Rahul and Raju = 6x and 5x
they saved = 1500 each
6x – 1500 / 5x – 1500 = 9/7
42x – 10500 = 45x – 13500
3x = 3000
x = 1000
sum = 6x + 5x = 11 * 1000 = 11000

7. There are total of 300 employees in a company. The ratio of male employees to female employees are 8 : 7. How many female employees have to be recruited so that the ratio
becomes male and female is equal ?
40
80
25
62
20
Option E
Number of male = 300 * 8/15 = 160
number of female = 300 * 7/15 = 140
let ‘x’ number of female we added
160 = 140 + x
x = 20

8. If the numerator is increased by 20 % and the denominator is decreased by 20% so that fraction becomes 2 : 3. What is the original fraction ?
2/5
5/9
4/9
2/3
4/11
Option C
Let the numerator and denominator be x and y respectively
(x * 120/100) / (y * 80/100) = 2/3
(6x/5) /(4y/5) = 2/3
6x / 4y = 2/3
18x = 8y
x/y = 8 /18 = 4/9

9. Total number of workers worked in a company is 50 and the ratio of male workers to female workers is 3 : 2. The ratio of amount of wages received by a male and a female worker is 7 : 6. If the wages received by each female workers is rs.120, then how much total wages received by all male workers ?
3800
3200
4500
4200
6500
Option D
Total workers = 50
male workers = 50 * 3/5 = 30
female workers = 50 * 2/5 = 20
wages received by a female workers = 120
wages received by a male workers = 120/6 *7 = 140
total wages received by all male workers = 140 * 30 = 4200

10. Three friends A , B and C got a total prize money is rs.2149. If B got 15% more A and C got 20% less than B, then find the how much amount of money C get ?
520
644
440
634
460
Option B
Total prize money = 2149
let A got = 100x
B got = 100x * 115/100 = 115x
C got = 115x * 80/100 = 92x
total = 100x + 115x + 92x = 307x
amount of money C got = 2149/307x * 92x = 644