Directions(1-10): Find the approximate value of the following questions.
- (21.6) ² ÷ (– 7.2) ² × ? = 15483.36 – 15276.09
2016182326Option D
(21.6) ² ÷ (– 7.2) ² × ? = 15483.36 – 15276.09
=>9 × ? = 207.27
⇒ ? = 23.03 == 23 - 348 ÷ 29 × 15 + 156 = (?)³ + 120
75648Option C
348 ÷ 29 × 15 + 156 = (?)³ + 120
=>(?)³ = 180 + 156 – 120 = 216
⇒ ? = 6 - 25 × 3.25 + 50.4 ÷ 24 = ?
8076707883Option E
25 × 3.25 + 50.4 ÷ 24 = ?
=>? = 81.25+2.1 = 83.35 == 83 - 350% of ? ÷50+248=591
29903300289049003550Option D
350% of ? ÷50+248=591
=>350 × ?/100 × 1/50 = 343
=> ? = 4900 - 1/2 of 3842 + 15% of ? = 2449
32253000352031103340Option C
1/2 of 3842 + 15% of ? = 2449
=>1/2 × 3842 + 15/100 × ? = 2449
=>? = (528 × 100)/15
=>? = 3520 - 3.2% of 500 × 2.4% of ? = 288
818900750660840Option C
16×2.4/100 𝑥 = 288
=>? = 750 - (𝟐√𝟑𝟗𝟐 – 𝟐𝟏) + (√𝟖– 𝟕)^𝟐 = (? )^2
±4±1±6±2±7Option C
(𝟐√𝟑𝟗𝟐 – 𝟐𝟏) + (√𝟖– 𝟕)^𝟐 = (? )^2
(?)² = 2 × 7√8 – 21 + 8 + 49 – 14√8
= 57 – 21 = 36
=> ? = ±6 - (? )^ 𝟒 ÷ 𝟐𝟕 = 𝟐𝟒3
96758Option A
(? )^ 𝟒 ÷ 𝟐𝟕 = 𝟐𝟒3
(?)⁴ = 243 × 27
=>(?)⁴ = (9) ⁴
⇒ ? = 9 - 46% of 450 +? % of 19.07 = 359.56
890800778678980Option B
46% of 450 +? % of 19.07 = 359.56
=>? /100 × 19.07 = 359.56 – 207
=> ? = {152.56 × 100}/19.07
=>? = 800 - 0.03 × 0.01 – 0.003 ÷ 100 + 0.03 =?
0.060.050.030.040.07Option C
0.03 × 0.01 – 0.003 ÷ 100 + 0.03 =?
? = 0.0003 – 0.00003 + 0.03 = 0.03027 == 0.03
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