Quantitative Aptitude: Simplification Questions Set 96

  1. Calculate the approximate value of the question mark (?) in the given questions:
    149.88% of 19.89 + √360.81 × 3.98 = ? – 139.89
    246
    256
    305
    315
    None of these
    Option A
    30 + 19*4 =x – 140
    30 + 7+ = x – 140
    x = 246

     

  2. ? + 1349.79 ÷ 4.99 – 124.89 = 120.10% of 1649.98
    1765
    1835
    2135
    1555
    None of these
    Option B
    x+ 1350/5 – 125 = 120/100 * 1650
    x + 270 – 125 = 1980
    x + 145 = 1980
    x = 1835

     

  3. (?)² + 180.44 × 4.8 + 64.9 × 3.9 = 2384.88
    55
    45
    35
    40
    None of these
    Option C
    x^2 + 180 * 5 + 65 * 4 = 2385
    x^2 + 900 + 260 = 2385
    x= 1225

     

  4. ?% of 299.98 = (21.09)² + (18.97)² + (6.15)^3 + 2.22
    305
    295
    335
    340
    350
    Option D
    x/100 * 300 = 441 + 361 + 216 + 2
    x/100 * 300= 1020
    3 x = 1020
    x = 340

     

  5. ?^3 × 19.98 + 15.05 % of 450.03 = (14.02)^2 + 5^√31.99
    1
    3
    2
    4
    9
    Option C
    x^3 * 20 + 15/100 * 450 = 196 + 2
    x^3 *20 + 67.5 = 198
    x^3 *20 =130.5
    x^3= 6.525
    x=1.86 = 2

     

  6. 1575.23 / 45.09 + 25.05 * √255.85 = ?
    435
    440
    395
    405
    515
    Option A
    1575 / 45 + 25 * 16
    35 + 25 * 16
    35 + 400 = 435

     

  7. 25 + 3.9 × 9.9 + 9.98 = ?
    65
    75
    55
    45
    None of these
    Option B
    25 + 4 * 10 + 10 = ?
    25 + 40 + 10 = ?
    x = 75

     

  8. (350 × 9.99) ÷ 5.4001 + 1245.20 = ?
    1805
    2455
    2005
    2105
    1945
    Option E
    (350 * 10) /5 + 1245 = ?
    3500/5 + 1245 =?
    x = 1945

     

  9. 30.95² – 10.05² + (1987.29 + 24.85 ÷ ?) = 900
    1
    2
    3
    4
    7
    Option A
    31^2 – 10^2 + (1987 + 25 / X) = 900
    961 – 100 + (2012 /x) =900
    861 x +2012 = 900
    x = 1.29 = 1

     

  10. 140% of 3780 + 38.78% of 140 = ?
    5001
    5187
    5487
    5355
    5347
    Option E
    140/100 * 3780 + 39/100 * 140 = x
    5292 + 54.6 = x
    5347 = x

     


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