- Without any stoppage a person travels a certain distance at an average speed of 50 km/hr and with stoppages he covers the same distance at an average speed of 40 km/hr. How many minutes per hour does he stop?
20min18min24min15minNoneOption B

Solution:

Let the total distance be x km.

Time taken at the speed of 50 km/hr = x/50 hrs.

Time taken at the speed of 40 km/hr = x/40 hrs.

He rested for ( x/40 – x/50) hrs = = x/200 hrs.

His rest per hour = x/200 / x/60 = 3/10 hrs. = 18 minutes.

- Two trains A and B start from station X and Y towards Y and X respectively. After passing each other they take 4 hours 48 minutes and 3 hour 20 minutes to reach Y and X respectively. If train A is moving at 45 km/hr, then the speed of train B is?
54km/hr50km/hr48km/hr45km/hrNoneOption A

Solution:

A’s speed/B’s speed =√ (Time taken by B to reach X) / (Time taken by A to reach Y)

45/B=√10/3/24/5

45/B=√5/6

B=54km/hr.

- Two men A and B walk from P to Q, a distance of 28 km, at 3 and 4 km an hour respectively. B reaches Q, returns immediately and meets A at R. Find the distance from P to R.
16km20km18km24kmNoneOption D

Solution:

When B meets A at R, B has walked the distance PQ + QR and A the distance PR.

That is , both of them have together walked twice the distance from P to Q, i.e 56 km.

Hence the distance PR travelled by A = 3/7 of 56 km = 24 km

- The speed of a car increases by 2 kms after every one hour. If the distance travelling in the first one hour was 15 kms. what was the total distance travelled in 10 hours?
240km200km180km230kmNoneOption A

Solution:

Total distance travelled in 10 hours =(15+17+19+…..upto 10 terms)

a=15, n= 10,d=2.

Required distance = 10/2[2 x 15+{10-1) x 2] =5(30+18)

= 240 kms.

- A man covers a certain distance on an average speed of 40 km/hr, he late by 10 min. However, he travel the same distance with a speed of 20 km/hr, he late by 25 min. Find the distance.
12km15km10km20kmNoneOption C

Solution:

Distance = Product of two speeds/ Difference of two speeds x Difference between arrival times.

(40*20)/20 *15/60

Distance =10km.

- If a person walks at 18 km/hr instead of 12 km/hr, he would have walked 30 km more. What is the actual distance travelled by him?
60km55km50km70kmNoneOption A

Solution:

He travels 30 km more due to an increase in speed of 6 km/hr.

Then 6……… 30

……. 12 ?==> 60km.

- A Man travelled from A to B. He went to B at the speed of 30 km/h and came back at the speed of 12 km/h. If he took 9 hours and 20 min to complete his journey, what is the distance between A and B?
90km75km80km70kmNoneOption C

Solution:

Average speed=2xy/(x+y)

=(2*30*12)/42

=120/7km/hr.

Distance =120/7*28/3=160km

Then Distance between A and B is 160/2=80km.

- In a 100m race, A runs at 1.66m/s. if A gives B a start of 4m and still beats him by 12 seconds,what is B’s speed?
1.32m/s1.5m/s2.3m/s2.5m/sNoneOption A

Solution:

time taken by B =time taken by A + 12

96/x =100/1.66 + 12

x=1.32m/s.

- Two buses start from a bus terminal with a speed of 20 km/h at interval of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at interval of 8 minutes?
10 km/hr6 km/hr8 km/hr5 km/hrNoneOption D

Solution:

Let Speed of the man is x km/hr.

Distance covered in 10 minutes at 20 km/hr = distance covered in 8 minutes at (20+x) km/hr.

20*10/60 = 8/60(20+x)

200 = 160+8x

8x = 40

then x = 5 km/hr.

- A train goes from StationA to StationB at 45km/hr and returns to A at a slower speed. If its average speed for the whole journey is 36 km/hr, at what speed did it return?
32km/hr30km/hr25km/hr26km/hrNoneOption B

Solution:

Average speed=2xy/(x+y)

=2*45*x/(45+x)=36

45x=18(45+x)

X=30km/hr.

chk question no 3 ans

S ans is 24 we changed.

No9 explain plz

q no1 –ans will be 12 min i think.