Time Speed Distance Questions for NICL, SBI PO, IBPS PO, NIACL, LIC, Dena Bank PO PGDBF, BOI, Bank of Baroda and other competitive exams.
- Two trains are running with speed 40kmph and 60kmph in the same direction. A man in the slower train passes by the faster train in 36seconds. Find the length of faster train?
A) 100mtr
B) 150mtr
C) 200mtr
D) 250mtr
E) 300mtr
- After travelling two hours a train met with an accident due to this it stops for an hour. After this the train moves at 66(2/3)% speed of its original speed and reaches to destination 3hour late. If the accident would occur at 200km ahead in the same line then the train reaches only 2.5hours late. Then find the distance of journey and the original speed of the train?
A) 2400km,600kmph
B) 1800km,300kmph
C) 2400km,400kmph
D) 1800km,200kmph
E) 2000km,100kmph
- A man travels a distance in three equal parts. He covers first part at 20kmph,second part at 40kmph and third part at 120kmph. Find the distance if he covers total distance in 20hrs.
A) 1400km
B) 1200km
C) 1440km
D) 1600km
E) 1500km
- A person who can walk down a hill at the rate of 6kmph and climb up the hill at rate of 4kmph. He ascends and comes down to his starting point in 5hrs. how far did he ascends ?
A) 12km
B) 14km
C) 20km
D) 24km
E) 16km
- A student walks from his house at a speed of 2(1/2)km per hour and reaches his school 6minutes late. The next day he increases his speed by 1kmph and reaches 6minutes before school time. How far is the school from his home?
A) 5/4km
B) 9/4km
C) 7/4km
D) 11/4km
E) 10/4km
- In covering a distance of 60km Abhi takes 2hrs more than Sam. If Abhi triples his speed then he would take 2hrs less than Sam. Abhi speed in kmph is ?
A) 10kmph
B) 12kmph
C) 15kmph
D) 20kmph
E) 14kmph
- Two men start together to walk a certain distance, one at 5kmph and another at 4kmph. The former arrives an hour before the latter. Find the distance?
A) 10km
B)Â 15km
C) 20km
D) 25km
E) 30km
- A man covers a distance in downstream at 18kmph. If the speed of stream is 2kmph then find his speed in upstream?
A) 12kmph
B) 14kmph
C) 16kmph
D) 18kmph
E) 20kmph
- The distance between a thief and apolicemen is 300m. the speed of thief is 12m/s and the speed of police is 15m/s. find the distance covered by police to catch the thief?
A) 1000m
B) 1200m
C) 1500m
D) 2000m
E) 1300m
- Two trains of same length passes each other in 36sec. if the speed of trains are 40kmph and 20kmph respectively, then find the length of train?
A) 200 m
B) 400 m
C) 600 m
D) 300 m
E) 500 m
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Can u plz explain how average speed is 72 km in question no 3
explain the third qus
In Q 2 option C also follow all conditions but only .1 difference comes so can we accept it as a ans or its wrong ??
q5 ?
u can easily solve with the help of options so go for it
its also easy
u can understand Q 3?
by option how?
use these given value and solve
qs 8 ?
its very simple
downstream speed =18
stream speed 2 but when we swim against stream speed it will be double so now stream speed 4
so 18-4=14ans
ty
downstream =x+y
upstream =x-y
now (x-y)^2 = (x+y)^2 -4xy
=(18)^2 -4*14*4 =14 km/hr
Q4. There are 3 containers A, B and C which contain water, milk and acid respectively in equal quantities. 10% of the content of A is taken out and poured into B. Then, the same 10% from B is transferred to C, from which again the same 10% is transferred to A. What is the proportion of milk in container A at the end of the process ?
(a) 9/10
(b) 1/11
(c) 1/121
(d) 10/1011
(e) None of these
process kitni baar ki h ye to bathoo 1,2,3,4???
etna hi hai qs me
na phir to nhi hoga ese kese hoga process to btani pdegi ki kitni baar kiya h
2 baar kiya hoga to alag aayga 3 baar kiya hoga to alag % aayega
quantity A 100x (water) Ataken 10% water poured into B
means A remaining 90X
now,B=100Xmilk710X water
10%poured into c means remaining 10x,x
C contained 100x acid 10x milk x water
10% poured into A
(90x+x/10) water x milk 10x acid
X=1011/10=101.1=10/1011
done
plz explain Q 3 in details
>>>TY,,,TY<<<
qs 3 ?
mere kuch or aa rha
Que-3 ?
ye kaun sa method h?
given spd
s(1) =20km/hr
s(2) =40km/hr
s(3) =120km/hr
take lcm =120
let distance =120
d(1) =d(2) =d(3) =40
now t1 +t2+t3 =20
(40/20) +(40/40)+(40/120) =20
=>10/3 =20 =>1 =6
so 120 =720 => d =720 km
Que no 9 easier way
X/12=X+300/15
X=1200
1200+300=1500 thief covered dist &police covered dist 1200km
Mam qye 3 explain
Average of 3quantity is
3*a*b*c/(ab)+(BC)+(ca) when dist is same
According to this formula
3*30*40*120/8000=36*20=720 ans ???
same
i think mam ka galat ho gaya hoga
aayat math ke liye konsa book follow karti ho ??
After travelling two hours a train met with an accident due to this it stops for an hour. After this the train moves at 66(2/3)% speed of its original speed and reaches to destination 3hour late. If the accident would occur at 200km ahead in the same line then the train reaches only 2.5hours late. Then find the distance of journey and the original speed of the train?
A) 2400km,600kmph
B) 1800km,300kmph
C) 2400km,400kmph
D) 1800km,200kmph
E) 2000km,100kmph
appka soln chahiye mam
Ye mujhe bhi nai aya try karti hu
https://uploads.disquscdn.com/images/f620f604c95c3744d6413801871e8a425600050fe0758295554522afcf64b19f.jpg
ty maam :))
2nd question smjh aya ??
2nd muze problem ho rahi hai
Qn2 —
diff of time= 3 – 2.5 = 1/2 hr
original spd = V
66 2/3% of its original spd = 2/3*V
1/2 = 200/(2V/3) – 200/V
1/2 = 200*/2V
V = 200 km/hr
let normal time = T
extra time = 3T/2 – T = T/2
T/2 = 3
T = 6 hrs
total distance = 200 + 200*6 = 1400 km
Sir ratio wale metd se kaise karenge??
ratio wale se mujhe nhi ata sorry
Ok ty
🙂
spd ratio =2:3
=> time ratio =3:2
now 3/2 -1 =30 mins
=>1 =60mins
since in time 1 it travelled 200km
=>200 =60min=>200km/hr =spd
now again 3/2 -1 =3
=>1= 6 hrs
=>distance in 6 hrs =6*200 =1200
=> totl dist =1200+200 =1400
vgud
..:)))
dear
x/y-x/2/3*y=2…1
x/y-x+200/4y=1/2..2
solve 1&2 ye method galat hai kya?
isse to X & Y ki value hi nhi ayega
But dist &speed unknown hai to Lena hoga ??
thx got it..
ok 🙂
Qn3 —
let distance of each equal part = D
then total distance = 3D
T1 +T2 +T3 = 20
D/20 +D/40 +D/120 = 20
10D/120 = 20
D = 240
total distance = 3D = 720
ys same here
_/_
ques no 3 ka ans to optin se differ aa ra 😛
yes ans is 200/1400
ok sir 😛 apna solution do
spd ratio =2:3
=> time ratio =3:2
now 3/2 -1 =30 mins
=>1 =60mins
since in time 1 it travelled 200km
=>200 =60min=>200km/hr =spd
now again 3/2 -1 =3
=>1= 6 hrs
=>distance in 6 hrs =6*200 =1200
=> totl dist =1200+200 =1400
thanKU :))
@@disqus_0OrBOABGUE:disqus Please dear tell me in this question , i didn’t get after 2=4 and 3=6 fir time 6 kese aaya hain
kindly explain?
6 : In covering a distance of 60km Abhi takes 2hrs more than Sam. If Abhi triples his speed
then he would take 2hrs less than Sam. Abhi speed in kmph is ?
. Abhi triples his speed
. triple…………….normal
speed 3……………………1
time 1…………………..3
. 3 -1 =2
2=4hrs
3=6hrs
so Abhi cover60km in 6hrs
60/6 =10kmph
see here…:)
let initial spd s(i) of abhi =1 now trippling his speed mns 1*3 =3
now ini.to increased spd ratio
s(i)————-s(c)
1—————-3
=> initial to increased time ratio
T(i)———–T(c)
3—————-1
now 2 ratio =(+2-(-2))=4 => 3 ratio = inital time = 6hrs
now ini.spd =totl dist/ini.time =60/6 =10km/h
6hrs is the initial time of abhi with which he covers 60 kms
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