# Quantitative Aptitude: Time and Work Set 11

Time and Work Questions for IBPS/SBI PO, NIACL, NICL, LIC, BOI, Bank of Baroda and other competitive exams

1. A can do a work in 25 days which B alone can do in 20 days. A started the work and was joined by B after 10 days . Find the number of days taken in completing the work ?
A) 7(1/3)days
B) 16(2/3) days
C) 12(1/3)days
D) 5(1/7)days
E) 11(1/10)days
Option  B
Solution:
Total work = 100 units
A = 4  units/ work
A do for 10 days of work = 40
remaining = 60
A+ B = 9
remaining work completed in= 60/9  = 6(2/3)
B = 5 units/work
Total days in completing the work = 10 + 6(2/3) = 16(2/3) days
2. 6 men of the first group do (2/3) of the work in (1/3) times compared to 4 men of the second group, find the respective ratio for  one day of 2 men of the first group and 4 men of the second group?
A)  3: 4
B) 3 : 7
C) 2 : 3
D) 1 : 3
E) 2 : 5
Option  C
Solution:
6 M * (3/2)W* (T/3) = 4 m * W * T
=> 2M/4m  = 2 / 3
3. Aman is thrice as efficient as Bikash. Aman started the work and worked  for 6 days then he is replaced by Bikash , he worked for  9 more days and they together finish  50% of the work. Find in how many days Bikash completed the work?
A)  35 days
B) 40 days
C) 57 days
D) 54 days
E) 48 days
Option  D
Solution:
Aman : Bikash = 3 : 1
Total work = 27 work
Aman complete  = 16 work/day
Bikash complete = 9 work /day
50% ===== 27
100% ====54
B alone take = 54/1 =  54 days

4. A, B and C can complete a piece of work in 10, 12 and 15 days resp.A left the work 5 days before the completion of the work  B left two days after A had left the work. Find the number of days required to complete the work?
A) 7 days
B) 5 days
C)10 days
D) 12 days
E) 8 days
Option  A
Solution:
Total work = 60 units
A takes =  6 units/day
B takes = 5 units/day
C takes = 4 units/day
Now ,
(x-5)/10 + (x-3)/12 + x/15 = 1
=> x = 7 days
5. A can do a work in 12 days when he had worked for 3 days B joined him if they complete the work in 3 more days. In how many days can B alone finish the work.
A) 2 days
B) 5 days
C) 4 days
D) 6 days
E)  3 days
Option  D
Solution:
A’s 1 day’s of work = 3/12 = ¼
Remaining work = 1 – (1/4) = ¾ days
(A+B)———( ¾)—— 3 days
(A+B)———1———- 4 days
(A+B) takes  = 4 days to complete the work
A takes = 12 days to complete the work
total work = 12 units
B can complete the work in = 12/ 2 =  6 days
6. 6 women  can complete a piece of work in 15 days . After 3 days from the start of the work , some of them left the work. If the remaining work was completed by the rest of the women in 20 days. How many women left after 3 days from the start of the work?
A) 14/ 3 days
B) 15/4 days
C) 15/2 days
D) 16/3 days
E) 11/2 days
Option B
Solution:
Let the number fo women left the work be x
6 women done the work in 3 days = 3/6 = ½
remaining work = 1 – ½ = ½
Now,
M1 D1/W1 = M2D2/W2
=> (6 * 15 )/1 = {(6-x)*20}/(1/2)
=> x = 15/4 days
7. A is thrice as good as B and it takes 30 days less than B for doing a job. How much time required to finish the work together.
A) 21(1/3) days
B) 23(1/2) days
C) 22(1/2) days
D) 20(1/4) days
E) 22(1/3) days
Option  C
Solution:
A : B = 3 : 1 ( efficiency )
(A + B)’s day’s work = (1/15)  + (1/45) = 4/45
Total time taken by both of them = 45/4 =11(1/4) days
8. 10 men , 6 women and 9 boys  were given a project of doing 2000 designs of a building in 5 days. All of them designed on the first day. On the second day 2 women and 3 boys are absent. On the third day , 3 men and and 5 boys are absent. If the ratio of the number ofdesigns done by them is in the ratio 3 : 2 : 1 respectively. Then find the number of designs designed by them on the second day (approx.)?
A) 620
B) 600
C) 667
D) 650
E) 682
Option  C
Solution:
Let the ratio be 3x : 2x : 1x
Designs of building on the first day = 10 * 3x + 6 * 2x + 9 * x = 51x
On the second day = 10 * 3x + 4 * 2x + 6 *x = 44x
On the third day = 7 *3x + 6 * 2x + 4 * x = 37x
Now, 51x + 44x + 37x = 2000
=> 132x = 2000
Therefore, 2000/132*44 = 666.66  = 667 (approx.)
9. 9 children can complete a piece of work in 200 days. 18 men can complete the same work in 150 days  and 12 women can complete the work in 180 days . In how many days can 10 children , 3 men and 12 women together complete the work?
A) 85(1/2) days
B) 80(1/2) days
C) 81(1/3) days
D) 81(9/11) days
E) 88(1/2) days
Option  D
Solution:
9* 200 children = 18 * 150 men = 12 * 180 women
=>1800 children = 2700 men = 2160 women
=> 10 children = 15 men = 12 women
Now, 10 children + 3 men + 12 women
= 10 children + 2 children + 10 children = 22 children
=> 22 children can complete the work in = (200*9)/22 = 81(9/11) days
10. A man gets Rs.620 for every day for his work . If he earns Rs.12400 in a month of 31 days . Find how many days did he work?
A) 10 days
B) 21 days
C) 20 days
D) 18 days
E) 15 days
Option  C
Solution:
Number of days = 12400/620 = 20 days

## 4 Thoughts to “Quantitative Aptitude: Time and Work Set 11”

1. ADK

Q.7. A…………B
……..3………….1 (efficiency)
……..1…………..3(time)
2——–30
1——-15
Total work == 45
Time together == 45/4 == 11 1/4 days

1. Banya

corrected

2. aspirant

Q6. 6*15=6*3+(6-x)*20
x=12/5

3. jaga

chod diya 9no question 🙂