# Quantitative Aptitude: Time and Work Set 10

Time and Work Questions for IBPS/SBI PO, NIACL, NICL, LIC, BOI, Bank of Baroda and other competitive exams

1. A is thrice as good a workman as B and therefore able to finish a job in 48 days less than B working together ,they can do it in how many days together ?
A) 13 days
B) 15 days
C) 18 days
D) 12 days
E) 116 days
Option  C
Solution:
.                   A:B
Efficiency=3:1
Time=1:3
Multiplying by 24 on both the sides ,
A’s=24 days
B’s=72 days
Therefore,2 units =48 days
1 units =24 days
Total work=No. of days *Efficiency
.                                       72*1
.                                        =72
One day work of A and B is 3+1=4 units
A and B will complete the work in =72/4=18days.
2. Three men –A ,B and C working together can do a job 6 hours less time than A did alone ,1 hour less time than B alone and half the time needed by C .In how many days will A finish the work alone ?
A) 20/3 days
B) 23/4 days
C) 22/5 days
D) 33/6 days
E) 27/8 days
Option A
Solution:
A+B+C          A           B            Cx hr.            x+6       x+1       2xTaking LCM = 2x (x+1)(x+6)
Taking efficiency of A and B ;
2x(x+1)(x+6)/(2x2 +2x+2x2 +12x)        = 2x/1
3x2 +7x-6=0
X=-3(ignore)
X=2/3
A will finish its work in (x+6)=20/3 days
3. A work is started by a man on the first day. Each subsequent day a new person joined the work and it is known that the total work will completed on the 11th day. If from the starting day 6 men working on that work and no new men added later, in how many days the work got completed?
A) 15 days
B) 12 days
C) 14  days
D) 11 days
E)  None of these.
Option D
Solution:
1day work of a man is 1 unit. If a new person joined the work on second day, 2 units of work get completed. Similarly 3 units on 3rd day, 4 units on 4th day so on…
Then for all the eleven days the total work = 1 + 2 + 3+ ………….11 = 66 units (Use formula
N(N+1)/2)
Now 6 men /day work = 6 units/day.
They can complete 66 units of work in =
66/6
=11 days
4. Two men can complete a piece of work in 3 days while 3 women can complete the same work in 4 days and 4 children can complete the same work in 6 days. Then find in how many days 1 men ,1 women and 2 children can complete the same work ?
A) 4 days
B) 3 days
C) 5 days
D) 2 days
E) None of these.
Option B
Solution:
2M *3 = 3W*4 = 4C*6
.      1M =  2W =   4C
LCM=4
1 Man’s efficiency= 4units/day
2 Women’s efficiency=2units/day
4 Children’s efficiency= 1 units/day
Total work =(2*4)*3=24 days
(1man+1woman+2children)=4+2+2=8
(1man+1woman+2children) complete the work =24/8=3 days
5. 30 men are supposed to do a work in 38 days. After 25 days, 5 more men were employed on work for which the work is completed in 1 day before . If 5 more men were not worked then how many days took in delay?
A) 1 day
B) 2 days
C) 3 days
D) 4 days
E) None of these.
Option A
Solution:
30Men * 25 days = 750
35 Men * 12 Days = 420
Total =750+420=1170
Now,1170/30 =39 days
1 day delay
6. A group of men decided to do a job in 4 days but 20 men dropped out everyday ,the job was completed at the end of the 7th day .Find the men who are in the work initially ?
A) 155
B) 135
C) 120
D) 140
E)  160
Option D
Solution:
Total work = M * 4 = 4M
M + (M+20) +…….
7/2 [2M +6(-20)] =4M
M=140
7. A printer A can print one thousand books in 15 hours ,printer B can print the same number of books in 10 hours and printer C can print the same number of books in 12 hours . If all the printers are started to print the books at 8 A.M, After sometime printer A is closed at 9 A.M and printer B and printer C remains working. Find at what time the printing will be completed ?
A) 4(3/11)hours
B) 3(1/11)hours
C) 5(1/11)hours
D) 3(5/11)hours
E) None of these.
Option C
Solution:
Let printing completed in be T hours
Then A ‘s 1 hour work ,B’s T hours work and C;s T hours work =Total work
1/15 +T/10+T/12 =1
T= 5(1/11)
Hence ,the printing of books will be completed at 5(1/11)hours
8. Ramesh and Ram can do a piece of work in 24 and 30 days respectively. They both started and worked for 6 days. Ram then leaves the work and another their friend Rohit joins the work and completed the remaining work with Ramesh in 11 days . Find how many days are taken by Rohit alone to finish the work?
A) 110 days
B) 132 days
C) 150 days
D) 120 days
E) None of these.
Option D
Solution:
(1/24 + 1/30) *6 +(1/24 + 1/Rohit ) *11 = 1
Therefore ,Rohit takes 120 days to finish the work.
9. A woman has her three daughters. First and second can take 24 and 30 days resp. to complete a work .In how many days third one takes to complete the work. If woman can complete the whole work alone in 3(3/11) days .The efficiency of woman is double than her three daughters.
A) 22 days
B) 12 days
C) 13 days
D) 21 days
E) 19 days
Option B
Solution:
LCM = 72 (if we are taking woman and her two daughters )
Here it is given
Woman Three daughters
Time taken = 1 : 2
Efficiency= 2 : 1Three daughters, let P +Q+R=11
3+2+R=11
R=6 days
Her third daughter complete the work in =72/6= 12 Days
10. A contractor takes a road construction project to finish it in 40 days and for that he engaged 200 men. After 30 days he employed 100 more men in this project, then the work finished on time. Find if the 100 more men would not worked then how many more days required to finish the work ?
A) 8 days
B) 10 days
C) 12 days
D) 7 days
E) None of these.
Option E
Solution:
100 * 10 days = 1000
Now 1000/200 = 5 days (Initial total no. of men engaged in the project)
Hence ,5 more days required to finish the work if 100 more men would not joined .

## 14 Thoughts to “Quantitative Aptitude: Time and Work Set 10”

1. Shubhra

https://disqus.com/home/discussion/http-www-aspirantszone-com/discussion_zone_12_july_2017/

9 PM banking and 10 PM English by Gusto. U can join here

1. AMAZON

Mam question no 9th, How LCM is 72 please tell?

2. ||Rise&shine||

Que no 9 me,, let P +Q+R=11 ye kyun liye… 3+2+R=11,, p=3and q=2 kaise????? mam pls explain..

3. Jellyfish

7/10
Que no 9
P+q+r=11??

4. vikas

8/10

5. Sandy

@Mod
Qsn=9
LCM= 72….kese..?

6. Jit

Thanks AZ

7. KUCH B........

9th sum
woman—-1—2-
36/11—24–30
360=lcm
110—15–12
given dounle the efficency of all three
15+12+28=55*2=110
so 3 ki efficency28
360/28=90/7 days me work complete karegi
aise ku nai hua?

1. thinker

8. Shubham Gupta

In question 9 it will be 36 instead of 30

9. kumkum ahuja

thank u az:))

1. <>>>>>>>>>>>>>

Taking efficiency of A and B ;
2x(x+1)(x+6)/(2×2 +2x+2×2 +12x) = 2x/1

mam in quaestion 2…….how it is equal to R.H.S 2x/1…

10. <>>>>>>>>>>>>>

Taking efficiency of A and B ;
2x(x+1)(x+6)/(2×2 +2x+2×2 +12x) = 2x/1

mam in quaestion 2…….how it is equal to R.H.S 2x/1

11. Hacked@disqus

For 1st ques use 3*48/(3*3-1)