# Mixed Reasoning Questions Set 8

Directions (1-3): Study the following information carefully and answer the questions that follow.
Six students A, B, C, D, E and F participated in two quizzes based on Math and English.
The total marks of A in Math was just above C and in English just above F. B was just above C in English but he scored less than D in Math.
F got more marks than D and E in English but did not perform as well in Math as in English as compared to D and E. No one is in between C and D in Math and C and A in English.

1. Who got the highest marks in English?
A) A
B) B
C) D
D) C
E) Cannot be determined
Option B
Solution:
For Math we get (in order of descending marks)
A, C , D  [B is less than D and F is below D and E]
For English we get (in order of descending marks)
B, C, A, F, D/E, E/D [D and E are below F]
2. Which of the following students has scored the least in English?
A) Only D
B) Only E
C) Only C
D) Only D or E
E) Cannot be determined
Option D
3. Who was just below D in Math?
A) B
B) E
C) C
D) F
E) Cannot be determined
Option E

Directions (4-6): Each question below contains two rows marked by I and II. The resultant of each row can be found by the rules given below. Answer the question followed by the rows by finding the resultant with the help of following five rules:

Step 1) If an even number is followed by an odd (prime) number, then the resultants will be additions of two numbers.

Step 2) If an odd number is followed by a perfect square, then the resultants come by subtracting smaller number from greater number.

Step 3) If an odd number is followed by another odd number, then the resultants will be additions of two numbers.

Step 4) If an even number is followed by an odd (non-prime) number, then the resultants come by subtracting smaller number from greater number.

Step 5) If an odd number is followed by an even number, then the resultants come by multiplying the numbers.

Note: For each resultant start from step 1. So for each operation priority will be given to Step 1, then step 2 and so on.

1. I.     4      5      6
II.   6     15      4
Find the multiplication of the resultant of two rows.
A) 285
B) 275
C) 280
D) 270
E) 260
Option D
Solution:
For row I –
From rule 1: 4 + 5 = 9
From rule 5: 9 × 6 = 54
Resultant of first row = 54
For row II –
From rule 4: 15 – 6 = 9
From rule 2: 9 – 4 = 5
Resultant of second row = 5
So 54*5 = 270
2. I.     9    3      21
II.   3     x      11
If x is the resultant of first row, then find the resultant of second row.
A) 19
B) 16
C) 15
D) 18
E) 17
Option E
Solution:
For row I –
From rule 3: 9 + 3 = 12
From rule 4: 21 – 12 = 9
Resultant of first row = 9
So x = 9
For row II –
From rule 2: 9 – 3 = 6
From rule 1: 6 + 11 = 17
Resultant of second row = 17
3. I.   12     25      2
II.   9     15      17
Find the LCM of the resultant of the first row and one more than the resultant of second row.
A) 542
B) 546
C) 552
D) 556
E) 558
Option B
Solution:
For row I –
From rule 4: 25 – 12 = 13
From rule 5: 13 × 2 = 26
Resultant of first row = 26
For row II –
From rule 3: 9 + 15 = 24
From rule 1: 24 + 17 = 41
Resultant of second row = 41, so 1 more than the resultant of second row = 1+41 = 42
So LCM of 26 and 42 is 546

Directions (7-8): From which of the following statements, the given conclusions follow?

1. Conclusions: All dogs are cats is a possibility.  Some monkeys are dogs.
Statements:
A) All dogs are monkeys. All monkeys are lions. No lion is cat.
B) Some dogs are monkeys. No monkey is lion. No lion is cat.
C) Some dogs are monkeys. All monkeys are lions. No monkey is cat.
D) All dogs are monkeys. Some monkey is lion. No monkey is cat.
E) None
Option B
You will have to check all the options to find out that which statements make both the conclusions follow.
Here B) option: Some dogs are monkeys.  So Some monkeys are dogs.
And there is no relation between dog and cats, so possibility occurs.
2. Conclusions: Some white are green. No red is black.
Statements:
A) All red are white. Some red are green. No green is black.
B) Some red are white. Some red are green. All white are black
C) All red are white. Some red are green. No white is black
D) No red is white. All green are white. Some white are black
E) None
Option C
C) option: Some red are white and No white is black. SO No red is black.
All red are white. Some red are green. SO Some white are green.

Directions (9-10): In each question below is given a group of letters followed by four combinations of digits/symbols given in (A), (B), (C) and (D). You have to find out which of the combinations correctly represents the group of letters based on the rules and mark the answer accordingly. If none of the combinations correctly represents the group of letters, mark (E) as your answer.

(i) If the first two letters are consonants, the codes for these letters are to be interchanged.

(ii) If the second letter is a vowel, the codes for the first and third letters are to be interchanged.

(iii) If the first letter is a vowel then the last letter is to be coded as the code for the vowel.

 Letter A C G I K M P R S U X Z Code 5 8 & 6 # 0 @ % 4 1 7 !

1. UGZRP
A) 1&!%@
B) 1&!%1
C) 1&6%1
D) 1%!%1
E) None of these
Option B
Solution:

From rule (iii), last letter P will be coded as 1 (code for vowel U) and all other letters will be coded as per their code.
2. KAMUS
A) #5#14
B) 05014
C) 05#14
D) #5014
E) None of these