Miscellaneous Reasoning Questions for IBPS PO/Clerk, NIACL, NICL, RBI Grade B, Dena Bank PO PGDBF, BOI, OBC SO, Bank of Baroda and other competitive exams

**Directions (1-3):** The symbols represent a date as:

‘#’ – Either the month or date is 5

‘$’ – Either the month or date is 6

‘%’ – Either the month or date is 12

‘@’ – Either the month or date is 3

‘+’ – Either the month or date is 10

Example: Time ‘@+’ represents 3 October.

The first symbol represents the date and the second symbol represents month.

- Medha’s birthday fall on ‘%#’. Her sister’s birthday falls after 29 days of Medha’s. On which date her sister’s birthday fall?

A) ++

B) %$

C) $@

D) @+

E) +$

- BRICS summit was scheduled to be happened on ‘+@’. But due to some issues, it got postponed and new date is after exact 9 months. The delegation which is to attend the summit will have to leave for it 4 days before to reach on time. When will the delegation have to leave for the summit?

A) $#

B) @+

C) %$

D) #%

E) $%

- A child’s birthday falls on ‘@$’. His father is exactly 30 years older than him. His mother is 22 days older than his father. Find the birth date of his mother. (Each year in between has same number of days)

A) @#

B) %#

C) $@

D) +%

E) Other than those given in options

**Directions (4-6):** A string of numbers is given as input. The further steps given are obtained by applying certain logic. Numbers of step II have been obtained by using at least 1 digit of each number in step I. Each step is a resultant of previous step only.

**Input:
**

- What is the average of numbers obtained in step 2 and 3?

A) 30

B) 27.5

C) 25

D) 22.5

E) Other than options given

- What is the ratio of numbers obtained in Step 2 respectively?

A) 3 : 7

B) 2 : 3

C) 5 : 6

D) 4 : 5

E) 6 : 7

- Find the difference between sum of numbers obtained in 1
^{st}step and sum of numbers obtained in all other steps.

A) 137

B) 143

C) 145

D) 141

E) 139

**Directions (7-10):** Consider the following steps for given input and read the instructions to reach to the last step.

**Instructions:**

Step-I: Interchange the alphabets in input as arrows mentioned

Step-II: (i) If both letters are consonant and number is less than 5, then consonants changes to next letter in English alphabetical series.

(ii) If there is one vowel and one consonant, then subtract 3 from the number.

(iii) It there is single letter, then add 2 to the number.

Step-III: has been derived using a special pattern.

- What is the sum of all numbers in step II of given input?

A) 42

B) 40

C) 33

D) 36

E) 43

- In last step, which of the following letter/s occur more than 1 time?

A) F

B) B

C) J

D) Both B and K

E) Both B and T

- Which of the following represents the second element in 3rd row in step III?

A) Is3

B) IS5

C) JT5

D) JT1

E) V3

- In step III, how many letters are there which represent number greater than 13 according to English alphabetical series? (A = 1, B = 2, ….., Z = 26)

A) 3

B) 5

C) 6

D) 1

E) 4

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1st question you have written after 29 months but in answer 29 days

Yes days

Plz explain 4-6Q

I ll add solution. Wait

Ok

Check the steps in solution now

Thanku

IN 4-6 QUE

STEP 2:

8*9-9= 63 SHOULD COME HOW DID 39 HAS COME

Its 6*8 – 9 = 39

See this

Numbers of step II have been obtained by using at least 1 digit of each number in step I.

QUE 8-10, PLZ EXPLQIN STEP 3

See 1st step me arrows k according interchange hai. And 2nd step me rules hai.

Now last step k liye ye both methods apply karne hai.

Means

2nd step k bad phle to arrows k according interchange karo and then usi me rules lgao for last step.

In solution see the first figure and its explanation above that figure.

See those steps if u get now. Otherwise ask again.

@mod

baki sb to thik h bs qsn 7-10 upr se nikl gya….

step2 se step-3 se step4 keseeeeeeee ….??

plz jra or deep kr k smjha do _/_

See 1st step me arrows k according interchange hai. And 2nd step me rules hai.

Now last step k liye ye both methods apply karne hai.

Means

2nd step k bad phle to arrows k according interchange karo and then usi me rules lgao for last step.

In solution see the first figure and its explanation above that figure.

See those steps if u get now. Otherwise ask again

wooow:)) ty mam::))

96…….68……..68

6*8-8 = 40 and 9*6-6 = 48

then in input question

76…….89…….88

7*8-8 = 48

6*9-8 = it is 46 not 39 ma’am…………correct me if I am wrong

No no. Dont go from solution to input.

From input it is 1×3 – 2

Means

6×8 – 9 = 39

ok got it thank u ma’am

please explain q 7

in Q- 4 to 6 ..how we get 39 .. can u explain in step 2

input it is 1×3 – 2

Means

6×8 – 9 = 39

ok ..so u r not taking last digit of each number….. you explain this in question ..but in answer step 2 u get 40 by 6*8-8 …by taking last number of each digit …

76……89……88

(1)…..(2)……(3)

rule is 1×3 – 2

6×8-9 = 39

7×8-8 = 48

thanks ….

just getting confuse ..so i asked u miss

unable to understand Ques 7

how step IV will come from step II in the given input??

Ma’am please help

See 1st step me arrows k according interchange hai. And 2nd step me rules hai.

Now last step k liye ye both methods apply karne hai.

Means

2nd step k bad phle to arrows k according interchange karo and then usi me rules lgao for last step.

In solution see the first figure and its explanation above that figure.

See those steps if u get now. Otherwise ask again

if we follow the same rule then given instuction is …..If both letters are consonant and number is less than 5, then consonants changes to next letter in English alphabetical series

and in your solution instruction is…When both are consonants and number < 5, then consonants change to previous letter.

which one is correct ma'am?

No you dont have to apply same rules for last step

Step II has different instructions , and coming from step 3 to 4 has different instructions

for step 2:

Step-II: (i) If both letters are consonant and number is less than 5, then consonants changes to next letter in English alphabetical series.

(ii) If there is one vowel and one consonant, then subtract 3 from the number.

(iii) It there is single consonant, then add 2 to the number.

for last step we have to self derive the instructions, that is what the question is na. That u have to derive for last step

For last step, we found, that these were followed

We see when there is single consonant, number changes to number – 3.

When both are consonants and number < 5, then consonants change to previous letter.

And when one is vowel and other consonant, then letters change to next letter.

For given input:

got it 😉

Big thanks to u ma’am for clearing my doubt

@disqus_hIdzmXnn6e:disqus ,Hey would you like to explain this dear, i have mentioned my doubt above see.

@Shubhra_AspirantsZone:disqus mam please do explain after step second i exchanged the digits according to the arrows while keeping alphabets constants, then i applied the step thirds rule , and according to that MT2 has to be NU from rule 1st of step 2nd

please explain

After step 2—

I8………..O1……….P3

MT2………………..AT9

GT9……HN4………C6

Next rule says:

When both are consonants and number < 5, then consonants change to previous letter.

So MT will change to LS na ?? – You have to apply new rule here

not that is already given in question

@@Shubhra_AspirantsZone:disqus which new rules mam , do we have to make assumption for it or like how? Actually i applied the one’s which is given for the step 2nd above.

yes for 4th step we will have to derive rules na

If they are already given in question, then what s the use of giving option.

See in explanation. We derived rules after interchanging the numbers as:

We see when there is single consonant, number changes to number – 3.

When both are consonants and number < 5, then consonants change to previous letter.

And when one is vowel and other consonant, then letters change to next letter.

okay got ya Mam

🙂 Finally Done.

see this picture once @@Shubhra_AspirantsZone:disqus https://uploads.disquscdn.com/images/6abd6cb0e4d1a8e5e4cfe6675a39941aa7ffa8e7ff999425793faca3c7ca61b5.jpg

mam if there are odd no of box in ip/op then what we do

then the condition will be given accordingly

Like in this question above, Step 1 has odd number of boxes. So condition given is: Numbers of step II have been obtained by using at least 1 digit of each number in step I.

Visuuu ???

mam @Shubhra_AspirantsZone:disqus in question no 7..in step 2..according to instructions..we have to add 2 where there is one consonant..bt in fig you have added 2 in vowel also..like i4..can u plzz explain this…?

Yes, it will be single letter

hmm thanku mam..

THANK U