# Mixed Reasoning Questions – Set 16 (New Pattern)

Miscellaneous Reasoning Questions for IBPS PO/Clerk, NIACL, NICL, RBI Grade B, Dena Bank PO PGDBF, BOI, OBC SO, Bank of Baroda and other competitive exams

Directions (1-3): The symbols represent a date as:

‘#’ – Either the month or date is 5
‘\$’ – Either the month or date is 6
‘%’ – Either the month or date is 12
‘@’ – Either the month or date is 3
‘+’ – Either the month or date is 10

Example: Time ‘@+’ represents 3 October.
The first symbol represents the date and the second symbol represents month.

1. Medha’s birthday fall on ‘%#’. Her sister’s birthday falls after 29 days of Medha’s. On which date her sister’s birthday fall?
A) ++
B) %\$
C) \$@
D) @+
E) +\$
Option D
%# – 12 May. After 29 days is 10 June
So +\$

2. BRICS summit was scheduled to be happened on ‘+@’. But due to some issues, it got postponed and new date is after exact 9 months. The delegation which is to attend the summit will have to leave for it 4 days before to reach on time. When will the delegation have to leave  for the summit?
A) \$#
B) @+
C) %\$
D) #%
E) \$%
Option E
Solution:
+@ – 10 March. 9 months after means in December
So 10 December. Now 4 days before means 6 December \$%
3. A child’s birthday falls on ‘@\$’. His father is exactly 30 years older than him. His mother is 22 days older than his father. Find the birth date of his mother. (Each year in between has same number of days)
A) @#
B) %#
C) \$@
D) +%
E) Other than those given in options
Option B
Solution:
Father exact 30 years older . So his birth date also @\$ – 3 June
Mother 22 days older. So 3 June – 22 days = 12 May = %#

Directions (4-6): A string of numbers is given as input. The further steps given are obtained by applying certain logic. Numbers of step II have been obtained by using at least 1 digit of each number in step I. Each step is a resultant of previous step only.

Input:

1. What is the average of numbers obtained in step 2 and 3?
A) 30
B) 27.5
C) 25
D) 22.5
E) Other than options given
Option D
Solution:

(40+48+0+2)/4 =
2. What is the ratio of numbers obtained in Step 2 respectively?
A) 3 : 7
B) 2 : 3
C) 5 : 6
D) 4 : 5
E) 6 : 7
Option C
Solution:
40/48 = 5/6
3. Find the difference between sum of numbers obtained in 1st step and sum of numbers obtained in all other steps.
A) 137
B) 143
C) 145
D) 141
E) 139
Option D
Solution:
Required difference = (96+68+68) – (40+48+0+2+1)

Directions (7-10): Consider the following steps for given input and read the instructions to reach to the last step.

Instructions:
Step-I: Interchange the alphabets in input as arrows mentioned

Step-II: (i) If both letters are consonant and number is less than 5, then consonants changes to next letter in English alphabetical series.
(ii) If there is one vowel and one consonant, then subtract 3 from the number.
(iii) It there is single letter, then add 2 to the number.

Step-III: has been derived using a special pattern.

1. What is the sum of all numbers in step II of given input?
A) 42
B) 40
C) 33
D) 36
E) 43
Option D
Solution:

In step-III, we see that some letters are at same place as in step II, but numbers are all changed. So it can be inferred that both patterns for step I and step II are applied for step III. In step I, numbers were constant with respect to arrows, but here letters have to be kept constant. So we get:

Now try some application in this as were given for step-II:
We see when there is single consonant, number changes to number – 3.
When both are consonants and number < 5, then consonants change to previous letter.
And when one is vowel and other consonant, then letters change to next letter.
For given input:

2. In last step, which of the following letter/s occur more than 1 time?
A) F
B) B
C) J
D) Both B and K
E) Both B and T
Option D
3. Which of the following represents the second element in 3rd row in step III?
A) Is3
B) IS5
C) JT5
D) JT1
E) V3
Option C
4. In step III, how many letters are there which represent number greater than 13 according to English alphabetical series? (A = 1, B = 2, ….., Z = 26)
A) 3
B) 5
C) 6
D) 1
E) 4
Option A
V, P and T

## 43 Thoughts to “Mixed Reasoning Questions – Set 16 (New Pattern)”

1. Hitesh Rana

1st question you have written after 29 months but in answer 29 days

2. Bharti singh

Plz explain 4-6Q

1. I ll add solution. Wait

1. Bharti singh

Ok

1. Check the steps in solution now

1. Bharti singh

Thanku

3. rajesh

IN 4-6 QUE
STEP 2:
8*9-9= 63 SHOULD COME HOW DID 39 HAS COME

1. Its 6*8 – 9 = 39
See this
Numbers of step II have been obtained by using at least 1 digit of each number in step I.

4. rajesh

QUE 8-10, PLZ EXPLQIN STEP 3

1. See 1st step me arrows k according interchange hai. And 2nd step me rules hai.

Now last step k liye ye both methods apply karne hai.
Means
2nd step k bad phle to arrows k according interchange karo and then usi me rules lgao for last step.

In solution see the first figure and its explanation above that figure.
See those steps if u get now. Otherwise ask again.

5. Sandy

@mod
baki sb to thik h bs qsn 7-10 upr se nikl gya….
step2 se step-3 se step4 keseeeeeeee ….??
plz jra or deep kr k smjha do _/_

1. See 1st step me arrows k according interchange hai. And 2nd step me rules hai.

Now last step k liye ye both methods apply karne hai.
Means
2nd step k bad phle to arrows k according interchange karo and then usi me rules lgao for last step.

In solution see the first figure and its explanation above that figure.
See those steps if u get now. Otherwise ask again

6. KUCH B........

wooow:)) ty mam::))

7. Navya

96…….68……..68
6*8-8 = 40 and 9*6-6 = 48
then in input question
76…….89…….88
7*8-8 = 48
6*9-8 = it is 46 not 39 ma’am…………correct me if I am wrong

1. No no. Dont go from solution to input.
From input it is 1×3 – 2
Means
6×8 – 9 = 39

1. Navya

ok got it thank u ma’am

8. puneet

in Q- 4 to 6 ..how we get 39 .. can u explain in step 2

1. input it is 1×3 – 2
Means
6×8 – 9 = 39

1. puneet

ok ..so u r not taking last digit of each number….. you explain this in question ..but in answer step 2 u get 40 by 6*8-8 …by taking last number of each digit …

1. Navya

76……89……88
(1)…..(2)……(3)
rule is 1×3 – 2
6×8-9 = 39
7×8-8 = 48

1. puneet

thanks ….

2. puneet

just getting confuse ..so i asked u miss

9. Navya

unable to understand Ques 7
how step IV will come from step II in the given input??

1. See 1st step me arrows k according interchange hai. And 2nd step me rules hai.

Now last step k liye ye both methods apply karne hai.
Means
2nd step k bad phle to arrows k according interchange karo and then usi me rules lgao for last step.

In solution see the first figure and its explanation above that figure.
See those steps if u get now. Otherwise ask again

1. Navya

if we follow the same rule then given instuction is …..If both letters are consonant and number is less than 5, then consonants changes to next letter in English alphabetical series

and in your solution instruction is…When both are consonants and number < 5, then consonants change to previous letter.
which one is correct ma'am?

1. No you dont have to apply same rules for last step

Step II has different instructions , and coming from step 3 to 4 has different instructions

2. for step 2:

Step-II: (i) If both letters are consonant and number is less than 5, then consonants changes to next letter in English alphabetical series.
(ii) If there is one vowel and one consonant, then subtract 3 from the number.
(iii) It there is single consonant, then add 2 to the number.

for last step we have to self derive the instructions, that is what the question is na. That u have to derive for last step

For last step, we found, that these were followed

We see when there is single consonant, number changes to number – 3.
When both are consonants and number < 5, then consonants change to previous letter.
And when one is vowel and other consonant, then letters change to next letter.
For given input:

1. Navya

got it 😉
Big thanks to u ma’am for clearing my doubt

2. AMAZON

@disqus_hIdzmXnn6e:disqus ,Hey would you like to explain this dear, i have mentioned my doubt above see.

3. AMAZON

@Shubhra_AspirantsZone:disqus mam please do explain after step second i exchanged the digits according to the arrows while keeping alphabets constants, then i applied the step thirds rule , and according to that MT2 has to be NU from rule 1st of step 2nd

4. After step 2—

I8………..O1……….P3
MT2………………..AT9
GT9……HN4………C6

Next rule says:
When both are consonants and number < 5, then consonants change to previous letter.

So MT will change to LS na ?? – You have to apply new rule here

not that is already given in question

5. AMAZON

@@Shubhra_AspirantsZone:disqus which new rules mam , do we have to make assumption for it or like how? Actually i applied the one’s which is given for the step 2nd above.

6. yes for 4th step we will have to derive rules na

If they are already given in question, then what s the use of giving option.

See in explanation. We derived rules after interchanging the numbers as:

We see when there is single consonant, number changes to number – 3.
When both are consonants and number < 5, then consonants change to previous letter.
And when one is vowel and other consonant, then letters change to next letter.

7. AMAZON

okay got ya Mam
🙂 Finally Done.

2. jitendra srivastav

mam if there are odd no of box in ip/op then what we do

1. then the condition will be given accordingly
Like in this question above, Step 1 has odd number of boxes. So condition given is: Numbers of step II have been obtained by using at least 1 digit of each number in step I.

10. BETTER THAN YESTERDAY

Visuuu ???

11. Army.

mam @Shubhra_AspirantsZone:disqus in question no 7..in step 2..according to instructions..we have to add 2 where there is one consonant..bt in fig you have added 2 in vowel also..like i4..can u plzz explain this…?

1. Yes, it will be single letter

1. Army.

hmm thanku mam..

12. jaga

THANK U