Reasoning: Syllogism Set 12 (New Pattern)

Direction (1-3): Each of the following questions consists of six statements followed by options consisting of three statements put together in a specific order. Choose the option that indices a combination where the third statement can be logically deduced from the first two statements and that option will be your answer.

  1. I. Some orange is white.
    II. Some white is black.
    III. All black is orange.
    IV. Some green are blue.
    V. No blue is white.
    VI. All red are green.
    A) [IV, VI, V]
    B) [I, II, V]
    C) [II, III, I]
    D) [IV, V, VI]
    E) None is correct
    View Answer
    Option C
    Some white is black., All black is orange. Gives Some orange is white.
  2. I. Some red is green.
    II. All blue is black.
    III. Some blue is white.
    IV. Some red is white.
    V. Some black is blue.
    VI. Some white is black.
    A) [VI, IV, I]
    B) [II, III, VI]
    C) [I, II, IV]
    D) [I , V, III]
    E) None is correct
    View Answer
    Option B
    All blue is black. and Some blue is white.
    Gives Some white is black.
  3. I. No red is green.
    II. Some white is red.
    III. All blue is white.
    IV. Some green is blue.
    V. No white is black.
    VI. No blue is black.
    A) [I, II, V]
    B) [II, III, V]
    C) [I, IV, VI]
    D) [III, V, VI]
    E) None is correct
    View Answer
    Option D

Direction (4-8): Each option contains some statements. Determine from which statements the given two conclusions follow.

  1. Conclusions: All tiger is dog. No lion is cat.
    Statements:
    A) All lion is horse. No horse is cat. Some cat is dog. All dogs are tiger. Some tiger is monkey.
    B) All horse is monkey. Some monkey is dog. Some dog is cat. All cats are tiger. No tiger is lion.
    C) All tiger is cat. All cats are dog. Some lion is monkey. All monkeys are horse. No lion is dog.
    D) Some horse is monkey. All monkeys are cat. Some cat is lion. No lion is dog. All dogs are tiger.
    E) None.
    View Answer
    Option C
  2. Conclusions: Some pencil is eraser. No scale is pen.
    Statements:
    A) Some books are pencil. No pencil is scale. All erasers are scale. Some scales are pen. All pens are copy.
    B) All books are scale. All pens are pencil. Some pencils are eraser. All erasers are copy. No scale is pencil.
    C) Some books are pencil. All pencils are copy. No copy is pen. Some pen is eraser. No eraser is scale.
    D) Some books are pencil. No pencil is eraser. No eraser is copy. Some copy are scale. All scales are pen.
    E) None
    View Answer
    Option B 
  3. Conclusions: All white being green is a possibility. Some grey are not blue.
    STATEMENTS:
    A) Some blue are white. All white us grey. No grey is green.
    B) All blue are white. All white is grey. Some grey is green.
    C) All blue are white. No white is grey. Some grey is green.
    D) Some blue are white. Some white is grey. All grey is green.
    E) None
    View Answer
    Option C
  4. Conclusions: Some green are white. Some red are white.
    Statements:
    A) All white are yellow. All yellow are red. Some red are green.
    B) All white are yellow. Some yellow are red. All red are green.
    C) Some white are yellow. All yellow are red. All red are green
    D) All white are yellow. All yellow are red. Some red are green.
    E) None
    View Answer
    Option C
  5. Conclusions: Some red are not black, Some green are white.
    Statements:
    A) Some white are not black. All white are red. All red are green.
    B) All red are white. Some black are not white. Some red are green.
    C) All white are black. No black is red. No red are green.
    D) Some white are black. No black is red. Some red are green
    E) None
    View Answer
    Option A

Direction (9-10): Statements are followed by 4 conclusions. Determine which conclusion(s) follow(s) from the given statements.

  1. Statements: All H are G. Some G are D. No D is C. Some C are T.
    Conclusions:
    I. No C is G
    II. Some G are not C.
    III. All D are H is a possibility.
    IV. All D are T is a possibility.
    A) Only II, III and either I or IV follow.
    B) Only III follows
    C) All follows.
    D) Only II, III and IV follow
    E) None of these
    View Answer
    Option D
    Explanation:

    I is not definite
    All G are C is not a possibility, so II follows.
    III is a possibility.
    IV is a possibility as
  2. Statements: All B are F. Some H are F. All P are H. No J is F.
    Conclusions:
    I. All J being H is a possibility
    II. Some P are not J
    III. Some H are not J.
    IV. Some P are F
    A) Only II, III and IV follow.
    B) Only I and III follows
    C) All follows.
    D) Only I, III and IV follow
    E) None of these
    View Answer
    Option B
    Explanation:

    I is a possibility as

    II – All P are J is a possibility, so II does not follow. (as seen in above venn, if all P are J, then also all statements agree, so it is a possibility)
    III – All H are J is not a possibility, so III follows. (if all H are J, some F will be J which is not possible)
    IV is not definite

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30 Thoughts to “Reasoning: Syllogism Set 12 (New Pattern)”

    1. ǟʍɮɨӄǟ

      kitna sote ho brother :))

      1. K!nG Iz B!nG

        kya hua…..??

        1. ǟʍɮɨӄǟ

          dp change kro mujhe bhi neeni ane lagti hai

          1. K!nG Iz B!nG

            hahaha,,,
            lo fir chole bhature khao:p

          2. ǟʍɮɨӄǟ

            now good 🙂

          3. ǟʍɮɨӄǟ

            ab ise dekh kar bhukh lagne lgi :pp

  1. Bhola Ladka (करे तो क्या करे)

    Good Questions 🙂

    1. ǟʍɮɨӄǟ

      bhola ladka ……….lolz

      1. Bhola Ladka (करे तो क्या करे)

        hehehe 😛 I know i know

  2. ǟʍɮɨӄǟ

    8/10

    thankyou shubhra mam :)) very nice questions

  3. YUMN ZAIDI

    Each of the following questions consists of six statements followed by options consisting of three statements put together in a specific order. Choose the option that indices a combination where the third statement can be logically deduced from the first two statements and that option will be your answer.

    I. Some orange is white.
    II. Some white is black.
    III. All black is orange.
    IV. Some green are blue.
    V. No blue is white.
    VI. All red are green.
    A) [IV, VI, V]
    B) [I, II, V]
    C) [II, III, I]
    D) [IV, V, VI]
    E) None is correct
    plz exp how to do these ???

    1. Suraj

      YOU HAVE TO CHECK THIS:
      take for example option A) [IV, VI, V]
      does the third i.e V : follows from 1st two i.e IV and VI
      means does statement V: No blue is white.
      follow from IV. Some green are blue.
      and
      VI. All red are green.

      similarly check all.. the option in which the third follows from 1st two… that is the answer

    2. ǟʍɮɨӄǟ

      u have to check each option from the given five and tell which one is correct means………………… u have given 3 statements in each option so first 2 statements are the premises and third statement is conclusion so u have to figure out which combination of options is true so that conclusion follows from the statements correctly

      take this option C) [II, III, I]
      II Means 2nd statement which is II. Some white is black. and III is All black is orange. u have to check that from both statements whether I statement which is Some orange is white. follows or not

  4. YUMN ZAIDI

    mam plz reply

    1. ǟʍɮɨӄǟ

      what is your doubt dear ???

  5. ǟʍɮɨӄǟ

    tough puzzle

    I. Study the following information carefully to answer the given questions
    There are Seven Lecturers – A, B, C, D, E, F and G taught seven subjects,viz., Maths, Zoology, Botany, Chemistry, Physics, English and Statistics on one day in a week starting from Monday and ending on Sunday (of the same week). There will be separate timings for each lecture.

    Note: Total hours taken by all the lecturers = 18 hours. The minimum and maximum timing of any lecture will be one hour and five hour respectively. There are two pairs of timings that can be followed by four lecturers.
     Chemistry is taught on Thursday. English is neither taught on Tuesday nor on Saturday. The Botany professor gave lecture immediately after the lecturer A. B is not a Chemistry Professor.
     Maths is taught for one hour. The Professor B gave his lecture on one of the days before Friday. Either the professor E or the professor F not gave his lecture on Sunday. Professor F gave his lecture immediately after E. Lecturer A spent more time than Lecturer C.
     Time taken by lecturer C is the sum of time taken by the lecturers B and F. Subjects Maths & Zoology are taught for same duration. The lecturer who took maximum time is immediately preceded by the person who took less than one hour of maximum time.
     The difference between the subjects taught on Friday and Sunday is equalled to the time taken by the lecturer A. Professor who gave maths lecture immediately preceded and followed by C and G respectively.
     Professor who gave lecture on Sunday spent less than three hours. Only one lecture is held between Chemistry and Botany. Zoology is taught after two days of maths lecture. Statistics is neither taught on Monday nor Sunday.
     Botany is not taught on the immediate next day on which Zoology is taught. Physics is taught on Monday.

    1. ǟʍɮɨӄǟ

      sab try karna :))

      1. purvi

        ye me kar chuki hu

        1. ǟʍɮɨӄǟ

          achha 🙂

  6. YUMN ZAIDI

    8 q why not B ??
    plz exp

    1. In B
      Some red are not black does not follow
      All red are black is a possibility so Some red are not black does not follow

  7. Laughing tym its nitrous oxide

    sir isme dekhna
    Conclusions: All white being green is a possibility. Some grey are not blue.

    C) All blue are white. No white is grey. Some grey is green.

    no grey is white reversed
    some white is blue
    no+some ==some not reversed so mtlb
    some blue are not grey to follow kesse hua ??

    1. Suraj

      TO check: All white being green is a possibility.
      No white is grey. Some grey is green.=> No+All= SOme not reversed =? Some GREEN is NOT White
      On day 5 table : if SOme A is Not B=> All B being A is a possibility.
      So All white being green is a possibility

      To check: Some grey are not blue.

      All blue are white. No white is grey. => ALL+ NO= NO=> No blue us grey or NO Grey is blue

      AS per table on day 5: NO A is B => Some A are not B => Some B are not A => both these are true
      So Some grey are not blue is also true

  8. sachin shukla@ my turn 2017

    ty

  9. Pawan

    “can never be” is a case of possibility in syllogism ?? please explain

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