**Directions(1-5):** Find out the values of x and y and then choose a correct option.

- I.x^2 + 31x +234 = 0

II.y^2 – 2y – 195 = 0

x > yx >= yy > xy >= xNo relationOption D

I.x^2 + 31x +234 = 0

=>x^2 + 18x + 13x + 234 = 0

=>(x+18)(x+13) = 0

=>x = -18,-13

II.y^2 – 2y – 195 = 0

=>y^2 – 15y + 13y – 195 = 0

=>(y-15)(y+13) = 0

=>y = -13,15

y >= x - I.3x^2 – 15x + 18 = 0

II.3y^2 = 4y + 15

x >= yy >= xx > yy > xNo relationOption E

I.3x^2 – 15x + 18 = 0

=>3x^2 – 9x – 6x + 18 = 0

=>(3x-6)(x-3) = 0

=>x = 2,3

II.3y^2 = 4y + 15

=>3y^2 – 9y + 5y – 15 = 0

=>(3y+5)(y-3) = 0

=>y = -5/3,3

No relation - I.x^2 – 16x + 63 = 0

II.y^2 – 11y + 30 = 0

y >= xy > xx >= yx > yNo relationOption D

I.x^2 – 16x + 63 = 0

=>x^2 – 9x – 7x + 63 = 0

=>(x-9)(x-7) = 0

=>x = 9,7

II.y^2 – 11y + 30 = 0

=>y^2 – 5y – 6y + 30 = 0

=>(y-5)(y-6) = 0

=>y = 5,6

x > y - I.5x^2 – 18x + 16 = 0

II.3y^2 – 13y + 14 = 0

y > xx > yx >= yy >= xNo relationOption D

I.5x^2 – 18x + 16 = 0

=>5x^2 – 10x – 8x + 16 = 0

=>(x-2)(5x-8)= 0

=>x = 2,8/5

II.3y^2 – 13y + 14 = 0

=>3y^2 – 6y – 7y + 14 = .

=>(y-2)(3y -7) = 0

=>y = 7/3,2

y >= x - I.11x + 9y = 169

II.13x – 5y = 59

y >= xx >= yx > yy > xNo relationOption D

Solving both the equations, we get

x = 8

y = 9

y > x - The upstream speed and downstream speed of a boat is 32 km/hr and 40 km/hr resp. Find the time taken by the boat to travel a distance of 240 km upstream when the speed of the stream is 50% more than its usual speed?
3 hours6 hours9 hours5 hours8 hoursOption E

Speed of boatman in still water = (32+40)/2 = 36 km/hr.

Speed of stream = (40-32)/2 = 4 km/hr.

New upstream speed = 36 – 1.5*4 = 30 km/hr.

Required time = 240/30 = 8 hours - A and B together can do a piece of work in 12 days. A,B and C together can do the same work in 8 days. In how many days can C alone can do the same piece of work?
26 days24 days25 days20 days28 daysOption B

Total work = 24 units

A and B can do work in one day = 24/12 = 2 units

A, B and C together in one day = 24/8 = 3 units

work done by C alone in one day = 3-2 = 1 unit

Time taken by C alone to complete the work = 24/1 = 24 days - Train A of length 240 m can cross a train B of length 460 m (stationary) in 35 seconds. Find the time taken by both trains to cross each other while moving opposite direction, if train B is moving at a speed 25% less than speed of train A.

25 seconds10 seconds20 seconds15 seconds18 secondsOption C

Let the speed of train A be x m/s.

(240+460)/x = 35

=>x = 20 m/s

Speed of train B = 20*0.75 = 15 m/s

Required time = (240+460)/(20+15) = 20 seconds - Mrs. Sharma invests 15% of her monthly salary, i.e., Rs. 4428 in Mutual Funds. Later she invests 18% of her monthly salary on Pension Policies also she invests another 9% of her salary on Insurance Policies. What is the total monthly amount invested by Mrs. Sharma?

1632918520145801239813125Option D

15% → 4428

1% → 4428/15

( 15 + 18 + 9) = 42% → 4428

15 × 42 → Rs. 12398.4 == 12398 - A trader sells two bullocks for Rs. 8,400 each, neither losing nor gaining in total. If he sold one of the bullocks at a gain of 20%, what is the loss of other sold ?
17(3/7)%13(1/3)%12(3/4)%14(2/7)%11(2/5)%Option D

S.P. of two bullock = 8400 + 8400 = Rs. 16800

CP of first bullock = 100/120*8400 = 7000

CP of second bullock =16800 – 7000

Required % loss = [9800-8400]/9800*100 = 14(2/7)% - The average weight of a class of (x+5) students is 48 kg. If the weight of a student whose weight is 70 kg is excluded, find the average weight of the class decreases by 0.5 kg. Find the value of x.
3060405080Option C

Total weight = (x+5)

48(x+5) – 70 = (48 -0.5)*(x+5-1)

=>x = 40 - Out of his total income, Mr. Kapoor spends 20% on house rent and 70% of the rest on house hold expenses. If he saves Rs 1,800 what is his total income (in rupees)?

Rs.6600Rs.7000Rs.8800Rs.7500Rs.8100Option D

Saving % = 100 – (20 + 56) = 24%

24% = 1800

100% = 1800/24*100 = Rs.7500 - A hemispherical bowl of internal diameter 54 cm contains a liquid. The liquid is to be filled in cylindrical bottles of radius 3 cm and height 9 cm. How many bottles are required to empty the bowl?
180162125170154Option B

Volume of hemi-sphere = 2/3*pi*27*27*27 cm^3

Volume of cylindrical bottle = pi*3*3*9

Required no. of bottles = 162 bottles {Divide hemisphere volume to the cylinder} - A can do a piece of work in 8 days which B can destroy in 3 days. A has worked for 6 days, during the last 2 days of which B has been destroying. How many days must A now work alone to complete the work?
9(1/7) days8(1/4) days7(1/3) days5(1/2) days6(1/5) daysOption C

In 6 days part of the work done by A = 6/8 = ¾

During 2 days, part of the work destroyed by B = 2/3

work done = ¾ – 2/3 = 1/12

Remaining work = 1 – 1/12

Required no. of days = 11/12 × 8 = 7(1/3) days - Two trains, A and B, start from stations X and Y towards each other, they take 4 hours 48 minutes and 3 hours 20 minutes to reach Y and X respectively after they meet if train A is moving at 45 km/hr., find the speed of the train B.
54 km/hr.38 km/hr.44 km/hr.61 km/hr.50 km/hr.Option A

S2/S1 = (24/5)^1/2/(10/3)^1/2 = (36)^1/2/(25)^1/2 = 6/5

S2 = 6/5*45 = 54 km/hr. - 19,10,11,24,100,?

950700808660740Option C

19*0.5+0.5 = 10

10*1+1 = 11

11*2+2 = 24

24*4+4 = 100

100*8+8 = 808 - 21,38,?,174,293,446

7780958965Option D

+17*1

+17*3

+17*5

+17*7

+17*9

? = 89 - 563,562,558,549,?,508
459533420600580Option B

-1^2,-2^2,-3^2,-4^2,-5^2

?= 533 - 21,44,?,104,141,182
6873809278Option B

+23,+29,+31,+37,+41

? = 73 - 13,14,16,22,?,166
4046385964Option B

+1!,+2!,+3!,+4!,+5!

? = 46 - If the number of employees who donot wear spectacles in company E is 12.5% more than the number of employees who wear spectacles in the same company. Find the number of employees in the company E.
477385459562440Option C

Number of employees in company E who donot wear spectacles = 112.5% of 216 =243

Required number of employees in company E = 243+216 = 459 - If the respective ratio of the number of male employees to female employees of company D who wear spectacles is 11:7. Find the number of female employees who wear spectacles in company D.

150136168147140Option D

Required number of female employees = 7/18*378 = 147 - If the total number of employees in company D was 730. Find the number of employees who donot wear spectacles in the same company.

312352367348330Option B

Number of employees who donot wear spectacles = 730 – 378 = 352 - If the ratio of the number of employees who wear spectacles to the number of employees who donot wear spectacles in company B is 3:2 resp. Find the number of employees in company B.

16201350148017101220Option B

Number of employees who wear spectacles in company B = 810

Number of employees who donot wear spectacles in company B = 810*2/3 = 540

Required number of employees in company B = 810+540 = 1350 - Find the difference between the number of employees who wear spectacles in company A and that of the same company C.
186170144162159Option D

Required Difference = 729 – 567 = 162 - 251 + ? + 317 – 469 = 358 – 297 + 343
315258296305385Option D

251 + ? + 317 – 469 = 358 – 297 + 343

=>? + 568 – 469 = 701 – 297

=>? + 99 = 404

=>?= 305 - (81^5 / 27^8)* 9^5 = 3^(? – 2)
9108124Option C

(81^5 / 27^8)* 9^5 = 3^(? – 2)

.=> {(3^4)^5 / (3^3)^8 }*(3^2)^5 = 3^(?-2)

=>? = 8 - (484)^1/2 + (784)^1/2 – (361)^1/2 = 25% of ?
148135161150124Option E

(484)^1/2 + (784)^1/2 – (361)^1/2 = 25% of ?

=>22 + 28 – 19 = 25% of ?

=>? = 124 - 893 + ?^2 – 724 = 18*25 + 16*5

2215121910Option D

893 + ?^2 – 724 = 18*25 + 16*5

=>?^2 + 169 = 450+80

=>?^2 = 361

=>? = 19 - (16)^2 + 219.98% of 20 = ?
500400100200300Option E

(16)^2 + 219.98% of 20 = ?

= >256 + 220% of 20 = ?

=>? = 300 - (600% of 75)/45 = ?^2 – (676)^1/2
68954Option A

(600% of 75)/45 = ?^2 – (676)^1/2

=>(600% of 75)/45 = ?^2 – 26

=>450/45 = ?^2 – 26

=>? = 6 - 12% of 375 = 20% of ? + 25% of 140
2025355045Option D

12% of 375 = 20% of ? + 25% of 140

=>12^ of 375 = 20% of ? + 25% of 140

=>? = 50 - 7.5% of 140 + 2.5% of 80 = ?
17.912.518.114.410.8Option B

7.5% of 140 + 2.5% of 80 = ?

=>7.5/100*140 + 2 = ?

=>? = 12.5 - (1024 – 263 – 233)/( 986 – 764 – 156) = ?

96587Option D

(1024 – 263 – 233)/( 986 – 764 – 156) = ?

=>(1024 – 496)/(986 – 920) = ?

=>? = 8 - [135/15*32]/?= 45*24
0.1600.2120.2660.1250.121Option C

[135/15*32]/?= 45*24

=>9*32/ ? = 45*24

=>? = 0.266

**Directions(16-20):** Find the missing ‘?’ term of the following series.

**Directions(21-25):** Answer the questions based on the following information.

The chart given shows the percentage distribution of the number of employees who wear spectacles in five different companies. Total number of employees in five companies together is 4500.

**Directions(26-35):** What will be the value of question mark ‘?’ in the following questions.