Simple Interest/Compound Interest Questions for IBPS PO, SBI PO, NIACL, NICL, LIC, Dena Bank PO PGDBF, BOI, Bank of Baroda and other competitive exams

- Find the compound interest on Rs36,000 at a rate in which Rs216 becomes Rs343 in 3years and the time is 2years?

A) Rs12000

B) Rs12500

C) Rs13000

D) Rs13500

E) Rs14200

- If a principal becomes triple in 3years on C.I. then find in how many years it will be 27 fold?

A) 39years

B) 9years

C) 18years

D) 27years

E) 10years

- If a principal becomes amount of rs14500 at 14(2/7)% rate of interest in 3years at simple interest. Find the S.I on principal?

A) Rs4250

B) Rs4300

C) Rs4400

D) Rs4350

E) Rs4270

- If the difference between C.I and S.I is rs256 at 20% rate of interest in 3years. Find the amount on C.I?

A) Rs4320

B) Rs2500

C) Rs3456

D) Rs3200

E) Rs3478

- A sum becomes 8000 in 3years and 10000 in 6years at C.I. Find the sum ?

A) Rs6400

B) Rs6500

C) Rs6000

D) Rs7000

E) Rs7200

- Find the C.I on rs9000 at 15% rate of interest for 3years?

A) Rs4645.87

B) Rs4680.87

C) Rs4685.87

D) Rs4687.87

E) Rs4356.77

- Find the compound interest on 18000 at 20% rate of interest in 1(1/2) years, if compounded half yearly ?

A) Rs5958

B) Rs4916

C) Rs5780

D) Rs3500

E) Rs6724

- Find the difference between S.I and C.I on Rs 5000 if rate of interest for first year is 10% and 2nd year is 15% and 3rd year is 20%?

A) Rs300

B) Rs320

C) Rs330

D) Rs340

E) Rs360

- If the principal become 6 fold on S.I in 10 years then find in how many years it will be 12 fold?

A) 24years

B) 22years

C) 12years

D) 20years

E) 25years

- If the compound interest on a sum at 25% rate of interest is Rs900 then find the S.I of 3years at same rate?

A) Rs1000

B) Rs1100

C) Rs1300

D) Rs1200

E) Rs1500

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question no 4 ,

plz explain the method

C.I in 3years = 5……………6

. 5……………6

. 5………..….6

. 125 216

. (91)

skip this method

use basic method

si 20*3 = 60

ci 20% for 3 year when u calculated value comes = 72.8

differ 72.8-60=12.8

12.8 is value of 256

256/12.8*100=2000

this is P =2000

now u calculate Ci on 2000 for 20% in 3 year u find answer

no

ryt hai qs

solution bhi ryt hai

concept hota hai one less hota hai

solution diya hai achche se pdo aa jayga

try this

R=(n-1)*100/T where n=no of times

find out R frm here then

T=(n-1)*100/R put value of R frm abv

🙂

bro…here principal means amount …;)

are dese quiz enough for maths?

yes

bt u have to practice more

1 to 12

mtlb difference 12-1 =11 so here 11 comes

1 to 6

difference 6-1=5

10/5=2

11*2= 22 ans everything is correct here question and solution i hope u understand

always wlc bro

CI For 3 year there are 2-3 approaches:

1st =3r.3r^2.r^3

2nd=effective method

3rd=percentile

you can use any approach ,

By Effective method = 20+20(20*20/100)=44

again consider 44 as first value and 20 is another =44+22(44*22/100)=72.8

p =100

=>si =60 (3yrs)

=>ci =72.8 (3yrs)

=>12.8 = 256 =>100 =2000

now 72.8 =1456

=>totl =2000+1456 =3456

thanx

SI = 2250

CI = 2590

Diff = 340

no prob its easy

See –

For Si =10+15+20=45%

For CI=

use effective method For first 2 year = 10+15+(10*15/100)=25+1.50=26.50 ,

again use the same, For remaining =

26.5+20+(26.5*20/100)=46.5+5.30=51.80

Diff of CI and SI==51.80-45=6.80%

6.80% of 5000=340

all done but i have a doubt on Q 10 i think this question is incompleteany mod plz help to understand this question

Re-check Qo no 10.

Info is not properly mentioned /

all done bt qus 10-time is not given for ci

same problem

Q8> however i gt the answer correct frm diffrent method this method seems new to me..pls explain @Shubhra ma’am (hw 10..11

20…23

5…6)

C.I .. 10…….11

. 20……23

. 5…….6

. 1000…..1518

. (518)

= 518/1000*100 = 51.8 %

= difference = 51.8 – 45 = 6.8%

= 6.8% of 5000 = 340

pls explain 5 th q.. how to cal

tq mam

ty 🙂