Simple Interest/Compound Interest Questions for IBPS PO, SBI PO, NIACL, NICL, LIC, Dena Bank PO PGDBF, BOI, Bank of Baroda and other competitive exams
- Find the compound interest on Rs36,000 at a rate in which Rs216 becomes Rs343 in 3years and the time is 2years?
A) Rs12000
B) Rs12500
C) Rs13000
D) Rs13500
E) Rs14200
- If a principal becomes triple in 3years on C.I. then find in how many years it will be 27 fold?
A) 39years
B) 9years
C) 18years
D) 27years
E) 10years
- If a principal becomes amount of rs14500 at 14(2/7)% rate of interest in 3years at simple interest. Find the S.I on principal?
A) Rs4250
B) Rs4300
C) Rs4400
D) Rs4350
E) Rs4270
- If the difference between C.I and S.I is rs256 at 20% rate of interest in 3years. Find the amount on C.I?
A) Rs4320
B) Rs2500
C) Rs3456
D) Rs3200
E) Rs3478
- A sum becomes 8000 in 3years and 10000 in 6years at C.I. Find the sum ?
A) Rs6400
B) Rs6500
C) Rs6000
D) Rs7000
E) Rs7200
- Find the C.I on rs9000 at 15% rate of interest for 3years?
A) Rs4645.87
B) Rs4680.87
C) Rs4685.87
D) Rs4687.87
E) Rs4356.77
- Find the compound interest on 18000 at 20% rate of interest in 1(1/2) years, if compounded half yearly ?
A) Rs5958
B) Rs4916
C) Rs5780
D) Rs3500
E) Rs6724
- Find the difference between S.I and C.I on Rs 5000 if rate of interest for first year is 10% and 2nd year is 15% and 3rd year is 20%?
A) Rs300
B) Rs320
C) Rs330
D) Rs340
E) Rs360
- If the principal become 6 fold on S.I in 10 years then find in how many years it will be 12 fold?
A) 24years
B) 22years
C) 12years
D) 20years
E) 25years
- If the compound interest on a sum at 25% rate of interest is Rs900 then find the S.I of 3years at same rate?
A) Rs1000
B) Rs1100
C) Rs1300
D) Rs1200
E) Rs1500
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question no 4 ,
plz explain the method
C.I in 3years = 5……………6
. 5……………6
. 5………..….6
. 125 216
. (91)
skip this method
use basic method
si 20*3 = 60
ci 20% for 3 year when u calculated value comes = 72.8
differ 72.8-60=12.8
12.8 is value of 256
256/12.8*100=2000
this is P =2000
now u calculate Ci on 2000 for 20% in 3 year u find answer
no
ryt hai qs
solution bhi ryt hai
concept hota hai one less hota hai
solution diya hai achche se pdo aa jayga
try this
R=(n-1)*100/T where n=no of times
find out R frm here then
T=(n-1)*100/R put value of R frm abv
🙂
bro…here principal means amount …;)
are dese quiz enough for maths?
yes
bt u have to practice more
1 to 12
mtlb difference 12-1 =11 so here 11 comes
1 to 6
difference 6-1=5
10/5=2
11*2= 22 ans everything is correct here question and solution i hope u understand
always wlc bro
CI For 3 year there are 2-3 approaches:
1st =3r.3r^2.r^3
2nd=effective method
3rd=percentile
you can use any approach ,
By Effective method = 20+20(20*20/100)=44
again consider 44 as first value and 20 is another =44+22(44*22/100)=72.8
p =100
=>si =60 (3yrs)
=>ci =72.8 (3yrs)
=>12.8 = 256 =>100 =2000
now 72.8 =1456
=>totl =2000+1456 =3456
thanx
SI = 2250
CI = 2590
Diff = 340
no prob its easy
See –
For Si =10+15+20=45%
For CI=
use effective method For first 2 year = 10+15+(10*15/100)=25+1.50=26.50 ,
again use the same, For remaining =
26.5+20+(26.5*20/100)=46.5+5.30=51.80
Diff of CI and SI==51.80-45=6.80%
6.80% of 5000=340
all done but i have a doubt on Q 10 i think this question is incomplete
any mod plz help to understand this question
Re-check Qo no 10.
Info is not properly mentioned /
all done bt qus 10-time is not given for ci
same problem
Q8> however i gt the answer correct frm diffrent method this method seems new to me..pls explain @Shubhra ma’am (hw 10..11
20…23
5…6)
C.I .. 10…….11
. 20……23
. 5…….6
. 1000…..1518
. (518)
= 518/1000*100 = 51.8 %
= difference = 51.8 – 45 = 6.8%
= 6.8% of 5000 = 340
pls explain 5 th q.. how to cal
tq mam
ty 🙂