- A man goes to his office at a speed of 30 km/hr and return to home at a speed of 45 km/hr. If he takes total 10 hours in all then, what is the distance between his office to home ?
120 km180 km340 km220 km200 kmOption B
Let distance = D km
D/30 – D/45 = 10
D = 180 km - The speed of car and bus in the ratio of 4 : 5. Car takes 1 hour more than bus to cover a distance of 240 km, then find speed of bus ?
40 km/hr30 km/hr60 km/hr84 km/hr72km/hrOption C
Let speed of car and bus = 4x and 5x respectively
240/4x – 240 /5x = 1
x = 12 km /hr
speed of bus = 5 * 12 = 60 km/hr - A train length of 225 meters can cross a pole in 9 sec. How much time taken by train if cross a platform whose length is 255 meters ?
22 sec19 1/5 sec12 1/2 sec18 sec20 secOption B
Speed of train = 225/9 = 25 m/sec
time = 225 + 255 / 25 = 19 1/5 sec - Ram goes to office from house at speed of 30 km/hr and reach 2 minutes before his usual time, if he goes at speed of 20 km/hr , then he reaches 3 minutes late. What is distance between office to house ?
6 km5 km12 km14 km8 kmOption B
Let distance = D
(D/20 – D/30) = 5/60 hours
D = 5 km - Train A starts from M with the speed f 80 km/hr at 10 am and B starts with the speed of 100 km/hr at 12 pm from N and total distance between M and N is 700 km, find at what time they will cross each other ?
4:00 pm3:00 pm2:00 pm5:00 pm3:30 pmOption B
Speed of train A = 80 km/hr
distance travel by train A from 10 am to 12 pm = 2 * 80 = 160 km
remaining distance = 700 – 160 = 540 km
time = 540/ (80 + 100) = 3 hours
time = 12 pm + 3 hours = 3:00 pm - 180m length of train crosses a platform at speed of 90 km/hr in 12 sec. Another train ar speed of 144 km/hr crosses same platform in 8 seconds. What is length of the other train ?
200 m400 m600 m500 m300 mOption A
Speed of train = 90 * 5 / 18 = 25 m/sec
let length of platform = x
x + 180/25 = 12
x = 300 – 180 = 120 m
let length another train = y
speed of other train = 144 * 5/18 = 40 m/sec
y + 120/40 = 8
y = 320 – 120 = 200m - two trains of length of 145 m and 215 m are running in same direction with speed of 162 km /hr and 108 km/hr respectively. How much time will they take to cross each other ?
18 seconds12 seconds15 seconds25 seconds24 secondsOption E
Speed of 145 m long train = 162 * 5/18 = 45 m/sec
speed of 215 m long train = 108 * 5/18 = 3 m/sec
time = 145 + 215/45 – 30= 360/15 = 24 sec - The sum of the length of train A and B is 700 meters and the speed of train A is 54 km/hr. If they are running in opposite direction, then they can cross each other in 20 seconds. Find the speed of train B ?
48 km/hr75 km/hr108 k/hr54 km/hr72 km/hrOption E
Speed of train A = 54 * 5/18 = 15 m/sec
total length = 700m
let speed of train B = x m/sec
700/(15 + x) = 20
x = 20 m/sec
speed of train B = 20 * 18/5 = 72 km /hr - Two stations P and Q are at a distance of 225 km. Train A starts running from station P and train B starts running from station Q respectively and meet each other after 3 hours. If the speed of train A is 5 km/hr more than the speed of train B, then find speed of train A ?
42 km/hr40 km/hr28 km/hr32 km/hr50 km/hrOption B
Let speed of train B = x km/hr
speed of train A = (x + 5) km/hr
total distance = 225 km
225/(x + 5 + x) = 3
225 = 6x + 15
x = 35
speed of train A = 35 + 5 = 40 km/hr - Sushant covers a distance by walking for 6 hours. While returning his speed decreased by 2 km/hr and he takes 9 hours to cover the same distance. What was his speed while returning ?
4 km/hr5 km/hr8 km/hr6 km/hr14 km/hrOption A
Let original speed of Sushant = x km/hr
while returning his speed = (x – 2) km /hr
x * 6 = 9 ( x – 2 )
6x = 9x – 18
x = 6
his speed while returning = 6 – 2 = 4 km/hr
Quantitative Aptitude: Time, Speed and Distance Set 25
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Quantitative Aptitude: Time, Speed and Distance Set 24
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Quantitative Aptitude: Time, Speed and Distance Set 23
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